The p-Block Elements Test

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The p-Block Elements Test - 65

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Weekly Quiz Competition

Question 1
1 / -0

$$CH_3CH=\overset{\overset{\displaystyle CH_3}{|}}{C}CH_3$$ changes to __________ in hydroboration-oxidation reaction.

A
$$CH_3\underset{\underset{\displaystyle OH}{|}}{C}H\underset{\underset{\displaystyle CH_3}{|}}{C}HCH_3$$

B
$$CH_3CH_2\overset{\overset{\displaystyle OH}{|}}{\underset{\underset{\displaystyle CH_3}{|}}{C}}CH_3$$

C
$$CH_3CH_2\underset{\underset{\displaystyle CH_3}{|}}{C}HCH_2OH$$

D
none of these

Solution
Question 2
1 / -0

Pick out the wrong statement.

A
Nitrogen has the ability to form $$p\pi -p\pi $$ bonds with itself

B
Bismuth forms metallic bonds in elemental state

C
Catenation tendency is higher in nitrogen when compared with other elements of the same group

D
Nitrogen has higher first ionization enthalpy when compared with other elements of the same group

E
Arsenic forms $$d\pi -d\pi $$ bonds with transition metals

Solution

Catenation tendency of phosphorus is higher than that of nitrogen due to high bond energy of $$P - P$$ single bond as compared to $$N - N$$ single bond.
Question 3
1 / -0

In the structure of borax, the numbers of boron atoms and B-O-B units, respectively, are :

A
4 and 5

B
4 and 3

C
5 and 4

D
5 and 3

Solution

The structure of borax is shown. It contains 4 B atoms and 5 B-O-B bonds.
Hence option $$A$$ is correct.
Question 4
1 / -0

The anion which cannot be formed by boron is:

A
$$B{ F }_{ 6 }^{ 3- }$$

B
$$B{ H }_{ 4 }^{ - }$$

C
$$B{ \left( OH \right) }_{ 4 }^{ - }$$

D
$$B{ O }_{ 2 }^{ - }$$

Solution

Boron cannot form $$B{ F }_{ 6 }^{ 3- }$$ anions due to absence of $$d$$ orbitals in boron. Since $$d$$ orbitals are not present in boron, it cannot expand its octet beyond 8. $$B{ F }_{ 6 }^{ 3- }$$ anion will have 12 valence electrons around B.

Question 5

1 / -0

Match the column I with column II and mark the appropriate choice

Column I	Column II
$$(A)$$ Boron fibres	$$(i)$$ Heat resistant glasses
$$(B)$$ Borax	$$(ii)$$ Bulletproof vest
$$(C)$$ Aluminium	$$(iii)$$ Filler in automobile tyre
$$(D)$$ Carbon black	$$(iv)$$ Transport industry

$$(A)\rightarrow (i),(B)\rightarrow (ii),(C)\rightarrow (iii),(D)\rightarrow (iv)$$

$$(A)\rightarrow (ii),(B)\rightarrow (i),(C)\rightarrow (iv),(D)\rightarrow (iii)$$

$$(A)\rightarrow (ii),(B)\rightarrow (iii),(C)\rightarrow (i),(D)\rightarrow (iv)$$

$$(A)\rightarrow (iii),(B)\rightarrow (ii),(C)\rightarrow (i),(D)\rightarrow (iv)$$

Solution

(A) Boron fibers $$\rightarrow$$ Boron carbide fibers and fiber composites may be used in the manufacture of ballistic materials for protective, durable and lightweight body armor. $$\rightarrow$$ (ii) Bulletproof vest

(B) Borax $$\rightarrow$$ used to produce various types of high strength and heat-resistant ceramic products. $$\rightarrow$$ (i) Heat-resistant glasses

(C) Aluminium $$\rightarrow$$ More than a quarter of all aluminium is used in the transport sector. $$\rightarrow$$ (iv) Transport industry

(D) Carbon black $$\rightarrow$$ Carbon black is mainly used as a reinforcing filler in tires and other rubber products. $$\rightarrow$$ (iii) Filler in automobile tyre

Question 6
1 / -0

Which of the following statements is incorrect for following species:

$$BO_3^{3-}, \, CO_3^{2-}, \, NO_3^-$$

A
They are isoelectronic and isostructural.

B
They have same bond order for E-O bond, where E is the central atom.

C
The extent of $$\pi$$-bonding is in the order of $$CO_3^{2-} \, < \, NO_3^- \, < \, BO_3^{3-}$$

D
Bond angles are same in every cases.

Solution

$$ \begin{array}{l} \text { (A) All of them have total } 32 \text { electrons are isoelectronic. } \\ \text { (B) Bond order }=\frac{\text { Total no. of bond }}{\text { Total } \sigma \text { -bonds. }} \text { It is } \frac{4}{3} \text { in } \mathrm{CO}_{3}^{2-} \text { and } \mathrm{NO}_{3} \text { - } \\ \text { but } 1 \text { in } \mathrm{BO}_{3}^{3-} \end{array} $$
$$ \text { (c) Extent of } \pi \text { -bonding : } \mathrm{NO}_{3}^{-}>\mathrm{CO}_{3}^{2-}>\mathrm{BO}_{3}^{3-} $$
$$ \begin{array}{l} \text { (2) Bond angles are nearly } 120^{\circ} \text { in each compound. } \\ \text { so, correct answer is (C)} \end{array} $$
Question 7
1 / -0

Hydrolysis of $$SiCl_4$$ gives ?

A
$$Si(OH)_4$$

B
$$SiOCI_2$$

C
$$SiO_2$$

D
$$H_2SiO_4$$

Solution

Hydrolysis of $$SiCl_4$$ gives $$SiO_2$$ (silica or silicon dioxide).

$$SiCI_ {4(l)}+2H_2O_((l)\rightarrow SiO_{2(s)}+ 4HCI_{aq}$$

Question 8

1 / -0

	List-I (ppt)		List-II (colour)
(P)	$${ Ag }_{ 2 }Cr{ O }_{ 4 }$$	(1)	Yellow
(Q)	$${ Cu }_{ 2 }\left[ Fe{ \left( CN \right) }_{ 6 } \right] $$	(2)	White
(R)	$$Ba{ SO }_{ 4 }$$	(3)	Chocolate brown
(S)	$$Pb{ I }_{ 2 }$$	(4)	Scarlet Red

$$P-4, Q-2, R-1, S-3$$

$$P-2, Q-3, R-4, S-1$$

$$P-4, Q-3, R-2, S-1$$

$$P-3, Q-4, R-1, S-2$$

Solution

$$Ag_2CrO_4:$$ Silver chromate : It is scarlet red in color.

$$Cu_2[Fe{(CN)}_6]:$$ It has a octahedral geometry of iron. and it is chocolate brown in color.

$$BaSO_4:$$ The precipitate of barium sulfate is white in color.

$$PbI_2:$$ Lead II iodide forms a bright yellow odorless crystalline solid , that becomes orange and red when heated.

Question 9
1 / -0

Product (A) and (B) in above reaction is :

A
$$O^--\overset{O}{\overset{||}{S}}-O-H, \, O^--\overset{O}{\overset{||}{S}}-O-CH_3$$

B
$$O^--\overset{O}{\overset{||}{S}}-O-H, \,\, O^--\underset{O^-}{\underset{|}{\overset{O}{\overset{||}{S_{\bigoplus}}}}}-O-CH_3$$

C
$$O^--\overset{O}{\overset{||}{S}}-O-CH_3, \,\, O^\ominus-\underset{CH_3}{\underset{|}{\overset{O}{\overset{||}{S_{\bigoplus}}}}}-H$$

D
d$$O^--\underset{H}{\underset{|}{\overset{O}{\overset{||}{S_{\bigoplus}}}}}-O, \,\, O^--\underset{CH_3}{\underset{||}{\overset{O}{\overset{||}{S}}}}-O^-$$

Solution

$$O^-$$act as a strong nucleophilic. Upon reaction with methyl iodide,it gives substitution product.And it get proportional in acidic condition.
A is the correct answer.
Question 10
1 / -0

$$(Me)_2SiCl_2$$ on hydrolysis will produce.

A
$$(Me)_2Si(OH)_2$$

B
$$(Me)_2Si=O$$

C
$$[-O-Me_2(Si-O-)]_n$$

D
$$Me_2Si(Cl)(OH)$$

Solution

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The p-Block Elements Test - 65

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Question 1

$$CH_3\underset{\underset{\displaystyle OH}{|}}{C}H\underset{\underset{\displaystyle CH_3}{|}}{C}HCH_3$$

$$CH_3CH_2\overset{\overset{\displaystyle OH}{|}}{\underset{\underset{\displaystyle CH_3}{|}}{C}}CH_3$$

$$CH_3CH_2\underset{\underset{\displaystyle CH_3}{|}}{C}HCH_2OH$$

none of these

Solution

Question 2

Nitrogen has the ability to form $$p\pi -p\pi $$ bonds with itself

Bismuth forms metallic bonds in elemental state

Catenation tendency is higher in nitrogen when compared with other elements of the same group

Nitrogen has higher first ionization enthalpy when compared with other elements of the same group

Arsenic forms $$d\pi -d\pi $$ bonds with transition metals

Solution

Question 3

4 and 5

4 and 3

5 and 4

5 and 3

Solution

Question 4

$$B{ F }_{ 6 }^{ 3- }$$

$$B{ H }_{ 4 }^{ - }$$

$$B{ \left( OH \right) }_{ 4 }^{ - }$$

$$B{ O }_{ 2 }^{ - }$$

Solution

Question 5

$$(A)\rightarrow (i),(B)\rightarrow (ii),(C)\rightarrow (iii),(D)\rightarrow (iv)$$

$$(A)\rightarrow (ii),(B)\rightarrow (i),(C)\rightarrow (iv),(D)\rightarrow (iii)$$

$$(A)\rightarrow (ii),(B)\rightarrow (iii),(C)\rightarrow (i),(D)\rightarrow (iv)$$

$$(A)\rightarrow (iii),(B)\rightarrow (ii),(C)\rightarrow (i),(D)\rightarrow (iv)$$

Solution

Question 6

They are isoelectronic and isostructural.

They have same bond order for E-O bond, where E is the central atom.

The extent of $$\pi$$-bonding is in the order of $$CO_3^{2-} \, < \, NO_3^- \, < \, BO_3^{3-}$$

Bond angles are same in every cases.

Solution

Question 7

$$Si(OH)_4$$

$$SiOCI_2$$

$$SiO_2$$

$$H_2SiO_4$$

Solution

Question 8

$$P-4, Q-2, R-1, S-3$$

$$P-2, Q-3, R-4, S-1$$

$$P-4, Q-3, R-2, S-1$$

$$P-3, Q-4, R-1, S-2$$

Solution

Question 9

$$O^--\overset{O}{\overset{||}{S}}-O-H, \, O^--\overset{O}{\overset{||}{S}}-O-CH_3$$

$$O^--\overset{O}{\overset{||}{S}}-O-H, \,\, O^--\underset{O^-}{\underset{|}{\overset{O}{\overset{||}{S_{\bigoplus}}}}}-O-CH_3$$

$$O^--\overset{O}{\overset{||}{S}}-O-CH_3, \,\, O^\ominus-\underset{CH_3}{\underset{|}{\overset{O}{\overset{||}{S_{\bigoplus}}}}}-H$$

d$$O^--\underset{H}{\underset{|}{\overset{O}{\overset{||}{S_{\bigoplus}}}}}-O, \,\, O^--\underset{CH_3}{\underset{||}{\overset{O}{\overset{||}{S}}}}-O^-$$

Solution

Question 10

$$(Me)_2Si(OH)_2$$

$$(Me)_2Si=O$$

$$[-O-Me_2(Si-O-)]_n$$

$$Me_2Si(Cl)(OH)$$

Solution

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