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Hydrocarbons Test - 44

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Hydrocarbons Test - 44
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  • Question 1
    1 / -0
    Aluminium amalgam used as a reducing agent, is obtained by: 
    Solution
    Aluminium amalgam used as a reducing agent, is obtained by dipping aluminium foil in mercuric chloride solution.
    Hence, Option "A" is the correct answer.
  • Question 2
    1 / -0
    Adam's catalyst is: 
    Solution
    Adams' catalyst whose chemical name is platinum dioxide, is represented as platinum(IV) oxide hydrate (PtO2H2O)(PtO_2•H_2O). This catalyst is used in hydrogenolysis and hydrogenation  in organic synthesis.
  • Question 3
    1 / -0
    It is necessary to use ______ in the iodonation of alkane.
    Solution
    Iodonation of Alkane:
    Alkane on reaction with Carbon tetraiodide in presence of hydrogen peroxide gives alkyl iodide. Here, hydrogen peroxide act as an oxidising agent in the reaction.

    Therefore, it is necessary to use oxidising agent in the iodonation of alkane.
  • Question 4
    1 / -0
    The compound having only primary hydrogen atoms is: 
    Solution
    \bulletButane has 4 secondary and 6 primary hydrogen atoms.
    \bulletIso-butene has 8 primary hydrogen atoms and 0 secondary hydrogen atoms.
    \bulletCyclohexane has 0 primary hydrogen atoms and 12 secondary hydrogen atoms.
    \bullet2,3-dimethylbutene has 11 hydrogen atoms, 0 secondary hydrogen atoms and 1 tertiary hydrogen atoms.

    So, only Iso-butene has only primary hydrogen atoms.
    Hence, Option "B" is the correct answer.
  • Question 5
    1 / -0
    On mixing certain alkane with chlorine and irradiating it with ultraviolet light, it forms only one monochloro alkane. The alkane could be: 
    Solution
    Alkanes which form only one monochlorinated products on photochlorination are Methane and neopentane.

    Hence, Option "D" is the correct answer.
  • Question 6
    1 / -0
    Correct IUPAC name obtain in the reaction:
     1-chloropropane Dry EtherNa\mathrm{\xrightarrow[Dry \ Ether]{Na}} is
    Solution
    Complete reaction:

    2 CH3CH2CH2Cl1chloropropane+2NaDry EtherCH3CH2CH2CH2CH2CH3nHexane+2NaCl\mathrm{\underset{1-chloropropane}{2 \ CH_3-CH_2 - CH_2Cl} + 2Na \xrightarrow{Dry \ Ether} \underset{n-Hexane}{CH_3-CH_2-CH_2-CH_2-CH_2-CH_3 }+ 2NaCl}

    So, the IUPAC Name of the compound obtained in the above reaction is n-Hexane.

    Hence, Option "C" is the correct answer.
  • Question 7
    1 / -0
    Which of the following is not prepared by Kolbe's electrolytic process? 
    Solution
    Hydrocarbons prepared by Kolbe's Electrolysis contains even number of carbons. 
    Of the above given compounds, only C3H8\mathrm{C_3H_8} has odd number of carbons in it. So, it can't be prepared by Kolbe's electrolysis process.

    Hence, Option "A" is the correct answer.
  • Question 8
    1 / -0
    A hydrocarbon of formula C6H10C_{6}H_{10} absorbs only one molecule of H2H_{2} upon catalytic hydrogenation. Upon ozonolysis, the hydrocarbon yields a compound of the following structure,
    O=CHCH2CH2CH2CH2COHO = \overset {\overset {H}{|}}{C} - CH_{2} - CH_{2} - CH_{2} - CH_{2} - \overset {\overset {O}{\parallel}}{C} - H
    The hydrocarbon is
    Solution

  • Question 9
    1 / -0
    X is heated with sodalime and gives ethane. X is: 
    Solution
    The given reaction is decarboxylation reaction:

    RCOOHSodalimeΔRH+CO2\mathrm{RCOOH \xrightarrow[Sodalime]{\Delta} RH + CO_2}

    This means one carbon is reduced in decarboxylation reaction.
    So, X was Propanoic acid.

    Hence, Option "C" is the correct answer.
  • Question 10
    1 / -0
    Correct IUPAC name obtain in the reaction:
     1-chloropropane Dry EtherNa\mathrm{\xrightarrow[Dry \ Ether]{Na}} is
    Solution
    Complete reaction:

    2 CH3CH2CH2Cl1chloropropane+2NaDry EtherCH3CH2CH2CH2CH2CH3nHexane+2NaCl\mathrm{\underset{1-chloropropane}{2 \ CH_3-CH_2 - CH_2Cl} + 2Na \xrightarrow{Dry \ Ether} \underset{n-Hexane}{CH_3-CH_2-CH_2-CH_2-CH_2-CH_3 }+ 2NaCl}

    So, the IUPAC Name of the compound obtained in the above reaction is n-Hexane.

    Hence, Option "C" is the correct answer.
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