Classification of Elements and Periodicity in Properties Test

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Classification of Elements and Periodicity in Properties Test - 13

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Weekly Quiz Competition

Question 1
1 / -0

IUPAC symbol of atomic number $119$ .

A
$Uuh$

B
$Uun$

C
$Uue$

D
$Uub$

Solution

According to the rule of IUPAC element having atomic number, more than 100 can be named by using numbers of its atomic number.
Here $1$ is written as $Un$ and $9$ is written as $en$ and the name end with $ium$ .
Thus the name of the given compound will be $\text{Ununennium}$ and symbol will be $Uue$

Hence, the correct option is $\text{C}$
Question 2
1 / -0

Beryllium and aluminium exhibit many properties which are similar. But, the two elements differ in:

A
maximum covalency in compounds

B
forming polymeric hydrides

C
forming covalent halides

D
exhibiting amphoteric nature in their oxides

Solution

Beryllium and aluminum exhibit many properties that are similar. But, the two elements differ in exhibiting maximum covalency in compounds.
For example $Be$ forms $BeCl_2$ and $Al$ forms $AlCl_3$ .

$Be$ and $Al$ shows some similarities due to the diagonal relationship. Some of these include the following.

They form polymeric hydrides.
Their halides are covalent. Both $Be$ and $Al$ form covalent
compounds.

Their oxides are amphoteric in nature.
$BeO+2HCl \rightarrow BeCl_2 + H_2O$
$BeO + 2NaOH \rightarrow Na_2BeO_2+H_2O$

$Al_2O_3+6HCl \rightarrow 2AlCl_3 +3H_2O$
$Al_2O_3 +2NaOH \rightarrow 2NaAlO_2 + H_2O$
Question 3
1 / -0

The correct order of electron affinity is:

A
O $>$ F $>$ Cl

B
F $>$ O $>$ Cl

C
F $>$ Cl $>$ O

D
Cl $>$ F $>$ O

Solution

The correct order of electron affinity is $\displaystyle Cl > F > O$
On moving from left to right across a period, the electron affinity becomes more negative.
On moving from top to bottom in a group, the electron affinity becomes less negative.
Chlorine has more negative electron affinity than fluorine. Because adding an electron to fluorine 2p orbital causes greater repulsion than adding an electron to chlorine 3p orbital which is larger in size.
Note: The electron affinity (in kJ/mol) of Cl, F and O is $\displaystyle -349$ , $\displaystyle -328$ and $\displaystyle -141$ respectively.
Question 4
1 / -0

Which among the following factors is the most important in making fluorine the strongest oxidising agent?

A
Electron affinity

B
Ionisation enthalpy

C
Hydration enthalpy

D
Bond dissociation energy

Solution

Fluorine is the strongest oxidizing agent due to low heat of dissociation and high heat of hydration which compensate the lower value of electron affinity.
Question 5
1 / -0

Within each pair of elements F & Cl, S & Se, and Li & Na respectively, the elements that release more energy upon an electron gain are:

A
$F, S$ and $Li$

B
$Cl, S$ and $Li$

C
$Cl, Se$ and $Na$

D
$F , Se$ and $Na$

Solution

Down the group electron affinity decrease due to increasing size. So, the electron affinity of $S>Se$ and $Li>Na$ so energy release will also be more. But in case of $F$ and $Cl$ , there is exception, $Cl>F$ . It is due to the small size of $F$ atom where the incoming electron face high electron-electron repulsion. So, the energy release will be more in $Cl$ .

So, option B is correct.
Question 6
1 / -0

Identify the incorrect match.
Name IUPAC Official Name
a) Unnilunium i) Mendelevium
b) Unniltrium ii) Lawrencium
c) Unnilhexium iii) Seaborgium
d) Unununnium iv) Darmstadtium

A
(b), (ii)

B
(c), (iii)

C
(d), (iv)

D
(a), (i)

Solution

The IUPAC name for $Unununnium$ ( $Z= 111$ ) is $Roentgenium$ not $Darmstadtium$

All other matches are correct.

Option C is correct
Question 7
1 / -0

Which of the following sequence contains atomic number of only representative elements?

A
$55,\ 12,\ 48,\ 53$

B
$13,\ 33,\ 54,\ 80$

C
$3,\ 33,\ 53,\ 87$

D
$22,\ 33,\ 55,\ 66$

Solution

Representative elements are the elements which lie in the group 1 and 2 on the far left and the last six columns or groups on the far right corner of the periodic table.
Sequence C option contains only representative elements.
Question 8
1 / -0

The elements $P,Q,R,S$ belong to group number $14,15,16,17$ respectively. Select the elements in increasing order of their electronegativity.

A
$P< Q< R< S$

B
$P> Q> R> S$

C
$R< Q< P< S$

D
$Q< P< S< R$

Solution

The elements P,Q,R,S belong to group number 14,15,16,17 respectively. The increasing order of electronegativity is $P<Q<R<S$ .
As we move from left to right in periodic table electronegativity of element increases.
Question 9
1 / -0

All elements of the same group will have:

A
same electronic configuration

B
similar outer electron configuration

C
same ionization potential value

D
different chemical properties

Solution

All the elements in a group having the same number of valence electrons and hence have a similar outer electronic configuration.

Hence, the correct option is $\text{B}$
Question 10
1 / -0

Which has the highest electron affinity?

A
$F$

B
$O$

C
$I$

D
$N$

Solution

Among the given elements, fluorine has the highest electron affinity value.
It increases in a period and decreases down the group.

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Re-Attempt Weekly Quiz Competition

	Name		IUPAC Official Name
a)	Unnilunium	i)	Mendelevium
b)	Unniltrium	ii)	Lawrencium
c)	Unnilhexium	iii)	Seaborgium
d)	Unununnium	iv)	Darmstadtium

Classification of Elements and Periodicity in Properties Test - 13

Result

Classification of Elements and Periodicity in Properties Test - 13

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Question 1

UuhUuhUuh

UunUunUun

UueUueUue

UubUubUub

Solution

Question 2

maximum covalency in compounds

forming polymeric hydrides

forming covalent halides

exhibiting amphoteric nature in their oxides

Solution

Question 3

O >>> F >>> Cl

F >>> O >>> Cl

F >>> Cl >>> O

Cl >>> F >>> O

Solution

Question 4

Electron affinity

Ionisation enthalpy

Hydration enthalpy

Bond dissociation energy

Solution

Question 5

F,SF, SF,S and LiLiLi

Cl,SCl, SCl,S and Li LiLi

Cl,SeCl, SeCl,Se and NaNaNa

F,SeF , SeF,Se and NaNaNa

Solution

Question 6

(b), (ii)

(c), (iii)

(d), (iv)

(a), (i)

Solution

Question 7

55, 12, 48, 5355,\ 12,\ 48,\ 5355, 12, 48, 53

13, 33, 54, 8013,\ 33,\ 54,\ 8013, 33, 54, 80

3, 33, 53, 873,\ 33,\ 53,\ 873, 33, 53, 87

22, 33, 55, 6622,\ 33,\ 55,\ 6622, 33, 55, 66

Solution

Question 8

P<Q<R<SP< Q< R< SP<Q<R<S

P>Q>R>SP> Q> R> SP>Q>R>S

R<Q<P<SR< Q< P< SR<Q<P<S

Q<P<S<RQ< P< S< RQ<P<S<R

Solution

Question 9

same electronic configuration

similar outer electron configuration

same ionization potential value

different chemical properties

Solution

Question 10

FFF

OOO

III

NNN

Solution

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$Uuh$

$Uun$

$Uue$

$Uub$

O $>$ F $>$ Cl

F $>$ O $>$ Cl

F $>$ Cl $>$ O

Cl $>$ F $>$ O

$F, S$ and $Li$

$Cl, S$ and $Li$

$Cl, Se$ and $Na$

$F , Se$ and $Na$

$55,\ 12,\ 48,\ 53$

$13,\ 33,\ 54,\ 80$

$3,\ 33,\ 53,\ 87$

$22,\ 33,\ 55,\ 66$

$P< Q< R< S$

$P> Q> R> S$

$R< Q< P< S$

$Q< P< S< R$

$F$

$O$

$I$

$N$