Classification of Elements and Periodicity in Properties Test

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Classification of Elements and Periodicity in Properties Test - 58

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Weekly Quiz Competition

Question 1
1 / -0

The element having general electronic configuration $3d^4 4s^1 :$

A
Noble gas

B
Non metal

C
Metalloid

D
Transition metal

Solution

The element having general electronic configuration $3d^4 4s^1$ is a transition metal as its last electron enters d-orbital.
Question 2
1 / -0

The element with configuration $1s^2 2s^2 2p^6 3s^2$ would be

A
A metal

B
A non-metal

C
An inert gas

D
A metalloid

Solution

It belongs to s-blocks and s-block elements are metals.
Question 3
1 / -0

The element having electronic configuration belongs to $ns^2(n-1)d^{1-10} (n-2)f^{1-14}$ belongs to :

A
s-block

B
p-block

C
d-block

D
f-block

Solution

The general electronic configuration of f-block is $ns^2(n-1)d^{1-10} (n-2)f^{1-14}$ .
Hence, Option "D" is the correct answer.
Question 4
1 / -0

$1s^2 2s^2 2p^2 3s^2$ is the electronic configuration of the metal

A
$Na$

B
$Mg$

C
$Fe$

D
$Al$

Solution

$Mg$ has electronic configuration $1s^2 2s^2 2p^6 3s^2$ .
Question 5
1 / -0

Whose name is not associated with the development of periodic table?

A
Prout's

B
Newlands

C
Rutherford

D
Loother Meyer

Solution

William Prout discovered that the atomic mass of an element can never differ. He observed that many elements have atomic weights as multiple of that of hydrogen.
Newland and Lowther Meyer also played a great role in the attempts to classify the elements.
However, Rutherford played a prominent role in explaining the structure of the atom.
Therefore, the correct option is C.
Question 6
1 / -0

An element having the electronic configuration $[Ar]3d^24s^2$ belongs to

A
s- block elements

B
p- block elements

C
d- block elements

D
f- block elements

Solution

An element having the electronic configuration $[Ar]3d^24s^2$ belongs to d-block elements as last electron enters in d-orbital.
Question 7
1 / -0

The element having the electronic configuration $1s^2 2s^2 2p^6 3s^2 3p^1$ is

A
A transition element

B
A representative element

C
An inert gas

D
An inner-transition element

Solution

As last electron is filled in $3p-$ orbital so it belongs to p-block. s-block and p-block elements are representative elements.
Question 8
1 / -0

Carbons forms four covalent bonds by sharing its four valence electrons with four univalent atoms , E.g., hydrogen. After the formation of four bonds,carbon attains the electronic configuration of:

A
helium

B
neon

C
argon

D
krypton

Solution

Carbon atom has 2 electrons in its innermost shell and 4 valence electrons. When it forms covalent bonds with 4 univalent atoms, it gets an additional 4 electrons as a result of sharing them. Now there are 8 electrons in its outermost shell. This resembles the electronic configuration of neon, which has the electronic configuration 2, 8.

Option B
Question 9
1 / -0

The element X has the following electrons configuraton 2, 8, 8, 2 . it means that it belongs to :

A
Second period and a second group

B
Fourth period and the fourth froup

C
Fourth period and the second group

D
Second period and fourth group

Solution

The element which is mentioned is calcium (Ca) it is located in the fourth period and second group.

4th period and 2nd group C is correct answer
Question 10
1 / -0

Which of the following statement is not a correct statement about the trends when going from left to right across the periods of periodic table?

A
The elements become less metallic in nature

B
The number of valence electrons increases

C
The atoms lose their electrons more easily

D
The oxides become more acidic

Solution

A. It is true that elements becomes less metallic because tendency to lose $e^-$ decreases
B. Valence electrons increases across the period from left to right.
C. Tendency to lose electrons is difficult across the period.
D. The oxides become more acidic. True.

Hence C is correct option.

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Re-Attempt Weekly Quiz Competition

Classification of Elements and Periodicity in Properties Test - 58

Result

Classification of Elements and Periodicity in Properties Test - 58

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SHARING IS CARING

Question 1

Noble gas

Non metal

Metalloid

Transition metal

Solution

Question 2

A metal

A non-metal

An inert gas

A metalloid

Solution

Question 3

s-block

p-block

d-block

f-block

Solution

Question 4

NaNaNa

MgMgMg

FeFeFe

AlAlAl

Solution

Question 5

Prout's

Newlands

Rutherford

Loother Meyer

Solution

Question 6

s- block elements

p- block elements

d- block elements

f- block elements

Solution

Question 7

A transition element

A representative element

An inert gas

An inner-transition element

Solution

Question 8

helium

neon

argon

krypton

Solution

Question 9

Second period and a second group

Fourth period and the fourth froup

Fourth period and the second group

Second period and fourth group

Solution

Question 10

The elements become less metallic in nature

The number of valence electrons increases

The atoms lose their electrons more easily

The oxides become more acidic

Solution

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$Na$

$Mg$

$Fe$

$Al$