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Chemical Bonding and Molecular Structure Test -11

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Chemical Bonding and Molecular Structure Test -11
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  • Question 1
    1 / -0

    The values of electronegativity of atoms A and B are 1.20 and 4.0 respectively. The percentage of ionic character of A and B bond is

    Solution

    We know that ionic characters

    \(=\,16[E_A\,-\,E_B]\,+\,3.5\,\times\,[E_A\,-\,E_B]^2\)

    or ionic characters = 72.24%

  • Question 2
    1 / -0

    The number of electrons that are paired in oxygen molecule is

    Solution

    Configuration of \(O_2\) molecule is

    \(\sigma(1s)^2\sigma^\ast(1s)^2(2s)^2\sigma^\ast(2s)^2\pi(2p_x)^2\pi(2p_y)^2\) \(\sigma(2p_z)^2\pi^\ast(2p_x)^1\pi^\ast(2p_y)^1]\)

    No. of pair are 7 so total no. of paired electrons are 14.

  • Question 3
    1 / -0

    The covalency of nitrogen in \(HNO_3\) is

    Solution

    (+1)+ x + 3(−2) = 0

    ⇒ 1+ x−6 =0

    ⇒ x = 6−1

    = 5

  • Question 4
    1 / -0

    Arrange the following compounds in order of increasing dipole moment.

    (I) Toluene

    (II)  m−dichlorobenzene

    (III)  o−dichlorobenzene

    (IV)  p−dichlorobenzene

    Solution

    The correct order of increasing dipole moment is p-dichlorobenzene < Toluene < m-dichlorobenzene < o-dichlorobenzene.

  • Question 5
    1 / -0

    The type of hybrid orbital’s used by the chlorine atom in \(ClO^-_2 \)is                                            

    Solution

    Chlorine atom in \(ClO^-_2\) is \(sp^3\) hybridised but its shape is angular.

  • Question 6
    1 / -0

    Which of the following is not a correct statement?

    Solution

    Due to electrostatic force of attraction, the melting points and boiling points of ionic compounds are high.

  • Question 7
    1 / -0

    Which of the following pairs have identical bond order?

    Solution

    Bond order in \(N_2,O^{2+}_2\) is 3 (calculate by energy level diagram).

  • Question 8
    1 / -0

    The polarity of a covalent bond between two atoms depends upon                                        

    Solution

    Electronegativities are used to determine the polarity of covalent bonds. The polarity of a covalent bond can be judged by determining the difference between the Electronegativities of the two atoms involved in the covalent bond.

  • Question 9
    1 / -0

    In the following which has highest boiling point

    Solution

    HF has highest boiling point because it has hydrogen bonding.

  • Question 10
    1 / -0

    Which of the following has minimum melting point?

    Solution

    HCl contain weak covalent bond.

  • Question 11
    1 / -0

    Which molecule is not linear

    Solution

    \(H_2O\) is not linear because oxygen is \(sp^3\) hybridised in \( H_2O\).

  • Question 12
    1 / -0

    The valency of sulphur in sulphuric acid is

    Solution

    The valency of sulphur in sulphuric acid is 6

  • Question 13
    1 / -0

    Which type of bond is formed between similar atoms?

    Solution

    Similar atoms form covalent bond.

  • Question 14
    1 / -0

    As compared to covalent compounds, electrovalent compounds generally have

    Solution

    Electrovalent compounds have high melting point and high boiling point.

  • Question 15
    1 / -0

    Highest covalent character is found in

    Solution

    Covalent character increases when we come down a group so \(CaI_2\) will have highest covalent character.

  • Question 16
    1 / -0

    The following salt shows maximum covalent character

    Solution

    Among the given choice \(Al\) is least electropositive therefore, the bond between \(Al\) and \(Cl\) will be least ionic or most covalent or the difference in electronegativity of two atom is less than 1.8.

  • Question 17
    1 / -0

    Which of the following will show least dipole character? 

    Solution

    Ethane due to its symmetrical structure.

  • Question 18
    1 / -0
    Which compound exhibits maximum dipole moment among the following?
    Solution
    p-nitro aniline has a maximum dipole moment.

    The dipole moments of $$C-N$$ bond of carbons attached to nitro and amino groups reinforce each other.

  • Question 19
    1 / -0
    Identify the pair in which the geometry of the species is T-shape and square pyramidal, respectively.
    Solution

  • Question 20
    1 / -0
    The number and type of bonds in $$C_{2}^{2-}$$ ion in $$CaC_2$$ are :
    Solution
    $$C_2^{2-}$$ ion $$\longrightarrow$$ $$[C\equiv C]^{2-}$$

    Dicarbide ion $$C_2^{2-}$$ has 1 sigma and 2 pi bonds. There are two $$\pi$$ bonds and one $$\sigma$$ bond in a triple bond.

    Hence, the correct option is $$(B)$$.
  • Question 21
    1 / -0
    Total number of lone pair of electrons in $$I_3{^-}$$ ion is :
  • Question 22
    1 / -0
    Among the following, the molecule with the highest dipole moment is:
    Solution
    $$CCl_4  < CHCl_3 < CH_2Cl_2 <CH_3Cl$$
    $$CCl_4 $$ dipole moment is 0 and The dipole moment of methyl chloride $$CH_3Cl$$ is maximum. It is $$1.86$$ D.
  • Question 23
    1 / -0
    Which of the following contains maximum number of lone pairs on the central atom?
    Solution
    From figure we get option $$D$$ is correct.

  • Question 24
    1 / -0
    Which of the following molecules has two sigma $$(\sigma)$$ and two pi $$(\pi)$$ bonds?
    Solution
    The structure of HCN is $$H-C\equiv N$$. It has $$2 \pi$$ and $$2 \sigma $$bonds.
  • Question 25
    1 / -0
    The hybridizations of atomic orbitals of nitrogen in $$NO_2^+ ,\ N{ O }_3^-$$ and $$NH_4^+$$ respectively are :
    Solution
    $$NO_2^{+}$$ contains 2 sigma bonds so hybridization is $$sp$$ and shape is linear.

    $$N{ O }_3^{-}$$ contains 3 sigma bonds so hybridization is $$sp^{2}$$ and shape is trigonal.

    $$NH_4^{+}$$ contains 4 sigma bonds so hybridization is $$sp^{3}$$ and shape is tetrahedral.

    Hence, option A is correct.
  • Question 26
    1 / -0
    Which one of the following pairs of species have this same bond order?
    Solution
    $$\displaystyle CN^{-}, CO$$ are isoelectronic species (contains same number of electrons). They have same bond order.
  • Question 27
    1 / -0
    MnO is?
    Solution
    Solution:- (B) Antiferromagnetic
    In the presence of the strong magnetic field, antiferromagnetic materials are weakly magnetised in the direction the field. This property of the materials is called antiferromagnetism and the materials which exhibit this propert are called antiferromagnetic materials.
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