Chemical Bonding and Molecular Structure Test 16

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Chemical Bonding and Molecular Structure Test 16

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Weekly Quiz Competition

Question 1
1 / -0

What is the nature of chemical bonding between $$Cs$$ and $$F$$?

A
lonic

B
Covalent

C
Coordinate

D
Metallic

Solution

The nature of the bond between calcium and fluorine is electrovalent ionic.
As calcium is a metal, $$F$$ is non-metal.
High electronegativity difference.
Charge transfer from fluorine to calcium.

Hence, the correct option is A.
Question 2
1 / -0

$$NH_3$$(excess) $$+ 3Cl_2\rightarrow A+N_2\uparrow$$; the bond present in compound $$A$$ is?

A
Ionic, Covalent and dative

B
Ionic and covalent

C
Dative and ionic

D
Dative only

Solution
Question 3
1 / -0

Lone pair of electrons are electrons in orbitals?

A
Which does not undergo hybridization

B
Which undergoes hybridization

C
Which undergoes hybridisation and participate in Bond formation

D
Which undergo hybridization but not participate in Bond formation

Solution
Question 4
1 / -0

For which of the above molecules dipole moment $$\mu \neq 0$$?

A
Only (c)

B
(c) and (d)

C
only (a)

D
(a) and (b)

Solution
Question 5
1 / -0

Correct order of dipole moment is:

A
$$CH_3F > CH_3Cl > CH_3Br > CH_3I$$

B
$$CH_3F > CH_3Br > CH_3Cl > CH_3I$$

C
$$CH_3Cl > CH_3F > CH_3Br > CH_3I$$

D
$$CH_3F > CH_3I > CH_3Cl > CH_3Br$$

Solution

The decreasing order of electronegativity among halogens is : $$F>Cl>Br>I$$. So due to highest electronegativity of $$F$$, $$F$$ atom attracts more attracts more electrons towards himself as a result more partial charge separation occurs in $${ CH }_{ 3 }F$$.
Therefore highest dipole moment is observed in $${ CH }_{ 3 }F$$.
$${ \overset { \delta + }{ CH } }_{ 3 }\overset { \mapsto }{ - } \overset { \delta - }{ F } >{ \overset { \delta + }{ CH } }_{ 3 }\overset { \mapsto }{ - } \overset { \delta - }{ Cl } >{ \overset { \delta + }{ CH } }_{ 3 }\overset { \mapsto }{ - } \overset { \delta - }{ Br } >{ \overset { \delta + }{ CH } }_{ 3 }\overset { \mapsto }{ - } \overset { \delta - }{ I } $$
Question 6
1 / -0

Find out the species with zero dipole moment
(i) $$trans-{CH}_3{CH}=CHCI$$
(ii) $${CS}_{2}$$

A
only one

B
i and ii

C
ii only

D
none of these

Solution
Question 7
1 / -0

Which of the following molecules has dipole moment greater than zero?

A
3-3-Diethylpentane

B
trans-2-pentene

C
2,2,3,3-tetramethyl butane

D
Neopentane

Solution
Question 8
1 / -0

A diatomic molecule has a dipole moment of 1.2 D. If the bond legth is $$1.0\times 10^{-8}$$ cm, what fraction of charge does exist each atom?

A
0.1

B
0.2

C
0.25

D
0.3

Solution

$$\mu = 1.2D$$ = $$1.2 \times 3.336 \times {10}^{-30} Cm$$

$$\mu = q \times l$$

$$q = \dfrac{1.2 \times 3.336 \times {10}^{-30}}{{10}^{-10}}$$

$$q = 4 \times {10}^{-20}\space C$$

Fraction of charge = $$\dfrac{4 \times {10}^{-20}}{1.6 \times {10}^{-19}}$$ = $$0.25$$
Question 9
1 / -0

In $$P_4O_6$$, the number of $$P-O$$ bonds and number of lone pairs on $$P$$ are:

A
12 and 4

B
8 and 8

C
12 and 16

D
12 and 12
Question 10
1 / -0

The inter nuclear distance in $$H_2$$ and $$Cl_2$$ molecules are $$74$$ and $$198$$ pm. respectively. The bond length of $$HCl$$ may be:

A
$$136 \,pm$$

B
$$272 \,pm$$

C
$$135.919 \,pm$$

D
$$271.919 \,pm$$

Solution

$$r_{H_2} = \dfrac{74}{2} = 37 \,pm$$

$$r_{Cl_2} = \dfrac{198}{2} = 99 \,pm$$

bond length $$= 37 + 99 = 136 \,pm$$

Option A is the correct answer.