Chemical Bonding and Molecular Structure Test 17

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Chemical Bonding and Molecular Structure Test 17

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Weekly Quiz Competition

Question 1
1 / -0

Non - zero dipole moment is shown by :

A
$$CCl_4$$

B
$$CS_2$$

C
$$H_2O$$

D
$$p-Cl-C_6H_4-Cl$$

Solution
Question 2
1 / -0

Which of the following has dipole moment ?

A
$$H_2S$$

B
$$CO_2$$

C
$$CCl_4$$

D
$$BF_3$$

Solution
Question 3
1 / -0

With a change in hybridization of the carbon bearing the charge, the stability of a carbanion decreases in the order

A
$$sp < { sp }^{ 2 } < { sp }^{ 3 }$$

B
$$sp < { sp }^{ 3 } < { sp }^{ 2 }$$

C
$${ sp }^{ 3 } < { sp }^{ 2 } < sp$$

D
$${ sp }^{ 2 } < sp < { sp }^{ 3 }$$

Solution

Stability of carbanions increases with increase in $$s-$$ character of hybrid orbital of carbon bearing charge hence correct order is:

$$ sp^{3} < sp^{2} < sp$$
Question 4
1 / -0

Which of the following has the weakest carbon-chloride bond?

A

B

C

D
$$CH_2=CH-CI$$

Solution
Question 5
1 / -0

The number of antibonding electron paris in $${O}_{2}^{2-}$$ molecular ion on the basis of molecular orbital theory are (At. no $$O=8$$)

A
$$2$$

B
$$3$$

C
$$4$$

D
$$5$$
Question 6
1 / -0

Which of the following is the decreasing order of their dipole moments?

A
$${NH}_{3}> {BF}_{3}> {NF}_{3}$$

B
$${NH}_{3}> {NF}_{3}> {BF}_{3}$$

C
$${BF}_{3}> {NH}_{3}> {NF}_{3}$$

D
$${BF}_{3}> {NF}_{3}> {NH}_{3}$$

Solution

In $$NH_3$$ all bond moments assists each other and so net moment adds up.
In $$NF_3$$, moment of low pairs is opposite to that of $$N-F.$$ So, net dipole moment reduces.
In $$BF_3$$, the molecule being planer, the moments cancel each other. Thus net moment is $$zero.$$
Hence, the order, $$NH_3>NF_3>BF_3$$
See the figure.
Question 7
1 / -0

Formal charge on nitrogen and oxygen in $$NO^-_3$$ ion are respectively:

A
$$0, \dfrac{-1}{3}$$

B
$$+1, \dfrac{-1}{3}$$

C
$$+1, \dfrac{-2}{3}$$

D
$$0, \dfrac{-2}{3}$$

Solution

Formula change is basically a change given to an atom, on assuming that the electrons in a chemical bond are shared equally between the atoms, neglecting theirrelative, $$EN.$$
$$FC=V-N-\cfrac{B}{2}$$ $$(V=\text{no. of valance electron}\\N=\text{No. of non bonding electrons}\\B=\text{No. of electrons in covalent bond})$$
$$FC$$ on $$N$$ in $$NO^-_3=0$$
$$FC$$ on $$O$$ in $$NO_3^-=\cfrac{-1}{3}$$
Question 8
1 / -0

The compoumd with no dipole moment is:

A
$${CH}_{3}Cl$$

B
$$C{Cl}_{4}$$

C
methylene chloride ($${CH}_{2}{Cl}_{2}$$)

D
chloroform ($$CH{Cl}_{3}$$)

Solution

$$CCl_4$$ has a net dipole moment of $$zero$$. Even though each of four $$C-Cl$$ bonds are polar, all the bond moments cancel due to tetrahedral structure of $$CCl_4.$$
Question 9
1 / -0

Which of the following has zero value of dipole moment:

A
Benzene

B
Naphthalene

C
p-dichlorobenzene

D
all the these

Solution
Question 10
1 / -0

Which of following has been arranged in order of decreasing dipole moment?

A
$$CH_{3}CI> CH_{3}F> CH_{3}Br> CH_{3}I$$

B
$$CH_{3}F> CH_{3}CI> CH_{3}Br> CH_{3}I$$

C
$$CH_{3}CI> CH_{3}Br> CH_{3}I> CH_{3}F$$

D
$$CH_{3}F> CH_{3}CI> CH_{3}I> CH_{3}Br$$

Solution