Chemical Bonding and Molecular Structure Test 26

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Chemical Bonding and Molecular Structure Test 26

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Weekly Quiz Competition

Question 1
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The number and type of bonds between two carbon atoms in $$ CaC_2 $$ are :

A
One $$ \sigma $$ and one $$ \pi $$ bond

B
One $$ \sigma $$ and two $$ \pi $$ bond

C
One $$ \sigma $$ and one-half $$ \pi $$ bond

D
One $$ \sigma $$ bond

Solution

$$CaC_2\rightarrow Ca^{2+} + C\equiv C^{2-} $$

There is a triple bond between two carbon atoms which means that there is one $$ \sigma $$ bond and two $$ \pi $$ bonds .
Question 2
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A molecule possessing dipole moment is:

A
$$ CH_4 $$

B
$$ H_2 O $$

C
$$ BF_3 $$

D
$$ CO_2 $$

Solution
Question 3
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The number of unpaired electrons in an $$ O_2 $$ molecule is:

A
$$H_2O > H_2S > H_2Se > H_2Te$$

B
$$H_2Te > H_2Se > H_2S > H_2O$$

C
$$H_2S > H_2O >H_2Se > H_2Te$$

D
$$H_2O > H_2S > H_2Te > H_2Se$$

Solution
Question 4
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The sigma and $$ \pi-bonds $$ present in benzene ring are:

A
Three sigma and three pi

B
Twelve sigma and three pi

C
Six pi and three sigma

D
Nine sigma and three pi

Solution
Question 5
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The types of bonds present in $$ NH_4Cl $$ are:

A
electrovalent, covalent and coordinate

B
only ionic

C
only covalent

D
covalent and coordinate

Solution

In $$NH_4Cl$$ molecule, ionic or electrovalent bond is formed between $$NH^{4+}$$ and $$Cl^-$$ ions, 3 covalent bonds are formed between N and three H atoms and one coordinate bond is formed between N and 1 H atom.
Question 6
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Correct order of bond length is:

A
$$HF > HI > HBr > HCl$$

B
$$HI >HBr>HCl>HF$$

C
$$HCl > HBr>HI>HF$$

D
$$HCl>HI>HBr>HF$$

Solution
Question 7
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Decreasing order of $$C - C$$ length in $$I. C_2H_4, \, II. C_2 H_2, \, III. C_6H_6, \, IV. C_2H_6$$ is

A
$$IV > III > I > II$$

B
$$I > II > IV > III$$

C
$$II > I > IV > III$$

D
$$IV > I > III > II$$

Solution

We know that, more the number of bonds between 2 atoms, shorter will be the bond length.

IV: Butane - has all single bonds making the longest bond lengths.

III: Benzene - has resonance meaning that the C-C bond has equal single bond and double bond character.

II: Butyne - has a triple bond.

I: Butene: has a double bond.

Thus, the correct order of decreasing C-C bond length is IV>III>I>II.

Hence, option A is correct.
Question 8
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The type of bond present in $$ CuSO_4 .5H_2O $$ are only.

A
Electrovalent and covalent

B
Electrovalent and coordinate covalent

C
Electrovalent,covalent and coordinate covalent

D
Covalent and coordinate covalent

Solution
Question 9
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Positive dipole moment is present in

A
$$ CCl_4 $$

B
$$ C_6H_6 $$

C
$$ BF_3 $$

D
$$ HF $$

Solution

the molecule which has highest dipole moment amongst the following is
$$[B]HF$$.

the 4 C-Cl bonds in $$CCl_4$$ are oriented to point at the vertices of a regular tetrahedron, and they cancel each other out exactly, so $$CCl_4$$ has no dipole moment
Dipole moment of Benzene($$C_6H_6$$) all most zero ( 0.0001 Debye).
In case of $$BF_3$$ the dipole moment is zero because it has a regular geometry and no lone pair of electrons is present on $$B$$. All the angles are 120 degree.

$$H-F$$ is polar due to difference of electronegativity of hydrogen and fluorine so it shows positive dipole moment.
Question 10
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On hybridization of one s-and one p-orbitals, we get:

A
Two mutually perpendicular orbitals

B
Two orbitals at $$ 180^o $$

C
four orbitals directed tetrahedrally

D
Three orbitals in the plane

Solution

On hybridization of one s-and one p-orbital, we get two orbitals at $$180^o$$. The number of hybrid orbitals formed is equal to the number of participating atomic orbitals, which in present case is 2. The angle between these two is equal to $$360^o$$ divided by the number of orbitals. $$\dfrac {360^o}{2} =180^o$$