Chemical Bonding and Molecular Structure Test 27

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Chemical Bonding and Molecular Structure Test 27

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Weekly Quiz Competition

Question 1
1 / -0

For the compounds $$ CH_3Cl, CH_3Br, CH_3I$$ and $$CH_3 F $$ the correct order of increasing C-halogen bond length is:

A
$$ CH_3F < CH_3Br < CH_3Cl < CH_3 I $$

B
$$ CH_3F < CH_3Cl < CH_3Br < CH_3 I $$

C
$$ CH_3Cl < CH_3Br < CH_3F < CH_3 I $$

D
$$ CH_3F < CH_3I < CH_3Br < CH_3Cl $$

Solution

As the radius halogen increase C - halogen bond length increased.

So, the correct order is:

$$ CH_3F < CH_3Cl < CH_3Br < CH_3 I $$
Question 2
1 / -0

The hybrid state and oxidation state of two oxygen atoms in $$H_2O_2$$ are respectively:

A
$$sp^2, -1$$

B
$$sp^2, +1$$

C
$$sp^3, -1$$

D
$$sp^3, +1$$

Solution
Question 3
1 / -0

Acetylene molecule contains:

A
5 sigma bonds

B
4 sigma and $$ 1 \pi - bond $$

C
3 sigma and $$ 2\pi - bonds $$

D
2 sigma and $$ 3 \pi-bonds $$

Solution
Question 4
1 / -0

Hydrogen directly combines with:

A
$$Ca$$

B
$$Zn$$

C
$$Fe$$

D
$$Cu$$

Solution
Question 5
1 / -0

Which of the correct order of increasing dipole moment?

A
$$CIF < BrCl < NO < HCl < LiI$$

B
$$LiI < BrCl < HCl < ClF < NO$$

C
$$BrCl < NO < HCl < ClF < LiI$$

D
$$NO < BrCl < HCl < LiI < ClF$$

Solution
Question 6
1 / -0

Which of the following is correct for hydrogen?

A
It can form bonds in $$+1$$ as well as $$-1$$ oxidation state

B
It is collected at cathode

C
It has a very high ionisation potential

D
All of the above

Solution

A) Hydrogen can only form single bonds with other atoms because it can only share one electron. This means that each of the two hydrogen atoms will have a +1 oxidation number except in metal hydrides where it is -1.

B) When the electrodes are connected to a source of direct current, the hydrogen ions are attracted to the cathode, where they each gain an electron, becoming hydrogen atoms again. Hydrogen atoms pair off into hydrogen molecules that bubble off as hydrogen gas.

C) Hydrogen has an electronic configuration of $$1S^1$$. It is a very small atom, and the single electron is close to the nucleus and therefore strongly attracted. There are no electrons screening it from the nucleus and so the ionization energy is high.

$$\therefore$$ All the above are correct

$$\mathbf{Hence\ the\ correct\ answer\ is\ option\ (D)}$$
Question 7
1 / -0

The molecule which does not exhibit dipole moment is:-

A
$$ NH_3 $$

B
$$ CHCl_3 $$

C
$$ H_2 O $$

D
$$ CCl_4 $$

Solution
Question 8
1 / -0

Which of the following statements is true about $$[Cu(NH_3)_4] SO_4 $$?

A
It has coordinate as well as covalent bonds

B
It has only coordinate bonds

C
It has only electrovalent bonds

D
It has electrovalent,covalent as well as coordinate bonds

Solution
Question 9
1 / -0

In which of the following the central atom has maximum number of lone piar of electrons?

A
$$ SF_4 $$

B
$$ XeF_4 $$

C
$$ ClO_3^- $$

D
$$ I_3^- $$

Solution
Question 10
1 / -0

Hybridisation of the _____atom change sin:

A
$$ AIH_3 to AlH_4^- $$

B
$$ H_2O to H_3 O^+ $$

C
$$ NH_2^- $$

D
$$ NF_3 $$

Solution

hybridization of central atom changes as the product is
in this change $$ AlH_3$$ to $$AlH_4^-$$