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Chemical Bonding and Molecular Structure Test -4

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Chemical Bonding and Molecular Structure Test -4
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  • Question 1
    1 / -0

    in case of a heteronuclear molecule like HF, the shared electron pair between the two atoms gets displaced more towards fluorine since the electronegativity of fluorine is far greater than that of hydrogen. This results in the molecule a

    Solution

    because of slight shifting of electron towards more electronegative element like F in HF brings a small amount of negative charge on F and positive charge on H which results in dipole moment.

  • Question 2
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    Elements in which apart from 3s and 3p orbitals, 3d orbitals also available for bonding In a number of compounds of these elements there are more than eight valence electrons around the central atom. One such example is

    Solution

    In H2SO4 , S has more than 8 electrons in valence shell.It has 12 electrons in its valence shell.

  • Question 3
    1 / -0

    Polarity in a molecule and hence the dipole moment depends primarily on electronegativity of the constituent atoms and shape of a molecule. Which of the following has the highest dipole moment?

    Solution

    CO2 is linear, so even though the C−O bonds have individual dipole moments, the overall dipole moment is zero as these cancel out (they point in opposite directions, as shown in the diagram below).

    On the other hand, H2O is "bent", which means that the individual dipole moments of the bond are at an angle to each other and because of Presence of lp on head of O atom in H2O therefore it has max dipole moment.

  • Question 4
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    Ionic crystalline compounds formed by ion-formation by electron transfer proves

    Solution

    Ionic crystalline compounds formed by ion-formation by electron transfer proves electronic theory of chemical bonding. According to this theory ionic bonds are formed when an atom looses electron/ electrons to become positive ion  and another atom gains the electron/ electrons to become negative ion. Ionic bonding is a process of complete transfer of Valence electrons.

  • Question 5
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    The criterion of overlap of atomic orbitals is the main factor for the formation of :

    Solution

    The valence bond theory is introduced to describe bonding in organic molecules. In this model, bonds are considered to form from the overlapping of two atomic orbitals on different atoms, each orbital containing a single electron.

    In general, greater the overlap, stronger is the bond formed between the two atoms. Thus, according to the orbital overlap concept, atoms combine together by overlapping their orbital and thus forming a lower energy state where their valence electrons with opposite spin, pair up to form covalent bond.

  • Question 6
    1 / -0

    Octet of electrons, represents a particularly stable electronic arrangement. Atoms achieve the stable octet when they are linked by chemical bonds. This rule is associated with one of the following theories

    Solution

    G.N.Lewis, proposed the octet rule to explain the valence electron sharing between atoms that resulted in a bonding type with the atoms attaining noble gas electronic configuration.

    The statement is : "a bond is formed between two atoms by mutual sharing of pairs of electrons to attain a stable outer-octet of electrons for each atom involved in bonding". This type of valence electron sharing between atoms is termed as covalent bonding.

  • Question 7
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    S in $$\displaystyle SF_{6}$$ is ______________ hybridized.
    Solution
    In $$SF_6$$, sulphur has six valence electrons and there are six fluorine atoms that are monovalent. So, by applying the hybridization formula answer comes for 6 hybrid orbitals, which is $$sp^3d^2$$ hybridisation.

  • Question 8
    1 / -0
    The hydrogen bond is absent in:
    Solution
    Hydrogen bond is absent in $$Ge$$. It is present in water, hydrogen fluoride and ammonia. A hydrogen bond is present between $$H$$ atom and highly electronegative atom of oxygen, fluorine or nitrogen.
  • Question 9
    1 / -0
    The total spin of two electrons forming a covalent bond is :
    Solution
    The total spin of two electrons forming a covalent bond is zero. When two electrons form a covalent bond, they have opposite spins. One electron has $$+\frac {1} {2}$$ spin and the other electron has $$-\frac {1} {2}$$ spin. Thus, sum of the spins of two electrons is zero.
    $$+\frac {1} {2}-\frac {1} {2}=0$$.
  • Question 10
    1 / -0
    The formal charge of the $$O$$ atoms in the ion is:

    Solution
    Formal charge of O atom $$=$$ Number of valence electrons - Number of dots - Number of lines
    $$=6-4-2$$
    $$=0$$
  • Question 11
    1 / -0
    Choose the correct option for the above molecule in view of chemical bonding.

    Solution
    Due to its linear structure and trans form dipole moment of molecule is zero.($$\mu=0$$)
  • Question 12
    1 / -0
    Which of the following is/are covalent binary compound(s)?
    Solution
    A binary compound is a compound composed of only two elements i.e., a binary compound is  made from exactly two different elements. There are  two types of binary compounds.
    1) Ionic binary compound: Binary compound which is formed by the combination of a metal atom and non metal atom is called ionic binary compound, e.g., KBr, NaCl, $$CaI_2$$, $$AlF_3$$, $$MgBr_2$$.
    2) Covalent binary compound: Binary compound which is formed by the combination of two non metal atoms is called  binary covalent  compound. In binary covalent compound sharing of electrons takes place, e.g., BF, $$N_2O$$, $$P_2O_5$$, $$N_2H_4$$, $$CH_4$$ and $$H_2O$$.
    A) Binary compound formed by B and F is $$BF_3$$ in which both boron(B) and florine(F) are non metals, hence, it is covalent binary compound.
    B) Binary compound formed by K and Br is KBr in which potassium(K) is metal and bromine(Br) is non metal. Hence, its is ionic binary compound.
  • Question 13
    1 / -0
    $$\displaystyle N_{2}$$ molecule contains ________ o and  _______ $$\displaystyle \pi-$$ bonds.
    Solution
    Sigma bond always between S-S and Px-Px overlap. While pi bond is formed between Py-Py and Pz-Pz overlap.
    So according to above diagram it is clear that there two pi bonds and one sigma bond in $$N_2$$.
  • Question 14
    1 / -0

    If there are five electron pairs in outer shell, then structure and bond angle as predicted by Sidgwick-Powell theory is:

    Solution
    With 5 electron pairs, the shape is trigonal bipyramidal with three bonds in the trigonal plane and 2 bonds in the pyramid i.e., perpendicular to the plane which are above and below the plane.

  • Question 15
    1 / -0
    Which of these molecules have non-bonding electron pairs on the central atom?
    I : $$SF_4$$       II : $$ICl_3$$         III: $$SO_2$$
    Solution
    $$SF_4$$ molecule has one non-bonding electron pair on the central atom Sulfur.

    $$ICl_3$$ molecule has two non-bonding electron pairs on the central atom Iodine. 

    $$SO_2$$ molecule has one non-bonding electron pair on the central atom Sulfur.

    So the answer is D.
  • Question 16
    1 / -0
    When a chemical bond is formed, there is decrease in :
    Solution
    When chemical bond is formed, the potential energy decreases. The distance between two atoms at which the potential energy is minimum is known as bond length.
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