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States of Matter Test - 30

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States of Matter Test - 30
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Weekly Quiz Competition
  • Question 1
    1 / -0
    'Equal volumes of all gases at the same temperature and pressure contain equal number of molecules'. This law is called as
    Solution
  • Question 2
    1 / -0
    In the gas equation, $$PV=nRT$$:
    Solution
    $$(B)$$ $$n$$ moles of the gas have a volume $$V$$
    An ideal gas is a gas whose pressure $$P$$, volume $$V$$, and temperature $$T$$ are related by the ideal gas law i.e.
    $$PV = nRT$$, 
    where $$n$$ is the number of moles of the gas and $$R$$ is the ideal gas constant.
  • Question 3
    1 / -0
    Among the following substances, the lowest vapour pressure is exerted by:
    Solution
    Vapor pressure of mercury is very low (compared to a liquid like methyl alcohol) because the forces of interaction between the individual metal atoms of mercury is quite a bit stronger than the cohesive molecular forces (such as a hydrogen bonding) that holds together several molecules in case of alcohols,ethers and water.
  • Question 4
    1 / -0
    Which of the following is correct?
  • Question 5
    1 / -0
    $$3$$ moles of $$P$$ and $$2$$ moles of $$Q$$ are mixed, what will be their total vapour pressure in the solution if their partial vapour pressures are $$80$$ and $$60$$ torr respectively?
    Solution
    We know that :
    $$P_{total}=p_P+p_Q=p^0_Px_P + p^0_Qx_Q$$

    where  $$ p^0_P$$ and $$p^0_Q$$ are partial pressures of pure substances.
    $$x_P$$ and $$x_Q$$ are mole fractions.

    $$x_P=\dfrac{3}{5}=0.6$$

    $$x_Q = \dfrac{2}{5}=0.4$$

    hence 
    $$P_{total}=p^0_Px_P + p^0_Qx_Q= 80\times 0.6 + 60\times 0.4 =72torr$$
  • Question 6
    1 / -0
    The vapour pressure of a solvent at $$293$$K is $$100$$ mm Hg. Then the vapour pressure of a solution containing $$1$$ mole of a strong electrolyte $$(AB_2)$$ in $$99$$ moles of the solvent at $$293$$ K is:
    (Assume complete dissociation of solute)
    Solution
    Let us consider the problem:
    $$\frac{{({P_A}^0 - {\rm{ }}{P^0})}}{{{P_A}^0}} = i\frac{{({n_B})}}{{({n_A} + {n_B})}}$$
    Since,
    $$\frac{{\left( {100 - {P_A}} \right)}}{{100}} = 3{\rm{ }}\left[ {\frac{1}{{\left( {99 + 1} \right)}}} \right]$$
    Since,
    $$100 - {P_A} = 3$$
    Hence the solution is $${P_A} = 97 mm$$ of $$Hg$$.
  • Question 7
    1 / -0
    According to Avogadro's hypothesis, equal volumes of gases under the same conditions of temperature and pressure will contain:
    Solution
    According to avogadro's hypothesis, equal volumes of gases under the same conditions of temperature and pressure will contain, the same no. of molecules.
    For eg. One volume of hydrogen combines with one volume of chlorine to produce two volumes of HCl gas.
    $$H_2\\1vol$$   $$+$$  $$Cl_2=\\1 vol$$ $$2HCl\\2 vol$$
  • Question 8
    1 / -0
    A solution at $$20^o$$C is composed of $$1.5$$ mol of benzene and $$3.5$$ mol of toluene. If the vapour pressure of pure benzene of pure benzene and pure toluene at this temperature are $$74.7$$ torr and $$22.3$$ torr. respectively, then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be, respectively.
    Solution
    Let us the problem.
    According to the raoult's law is used   which states that for a solution of volatile liquids, the partial vapour pressure of each liquid in the solution is directly proportional to its mole fraction.
    $${X_{benzene}} = \frac{{1.5}}{5} = 0.3$$
    $${X_{toluence}} = \frac{{3.5}}{5} = 0.7$$
    $${P_T} = 74.7 \times 0.3 + 0.7 \times 22.3$$
    $$ = 22.41 + 15.61$$
    $$= 38.02\,torr$$
    $${Y_{benzene}} = \frac{{22.41}}{{38.02}} = 0.589$$
  • Question 9
    1 / -0
    If the absolute temperature of a gas is doubled and the pressure is reduced to one-half, the volume of the gas will
    Solution
    We know that $$\frac{P_1V_1}{T_1}$$ = $$\frac{P_2V_2}{T_2}$$
     Volume of the gas = v
    Pressure $$P_1$$ = p
    Pressure $$P_2$$ = $$\frac{1p}{2}$$
    Temperature = $$T_1$$ = t
    Temperature = $$T_2$$ = 2t
    $$V_2$$ = $$P_1V_1T_2/T_1$$
    = $$( p\times v\times2t)$$ / $$(2t\times p)$$
     = v
    That means $$V_2 = V_1$$
    So it increases four-fold so C is the correct option. 
  • Question 10
    1 / -0
    For an ideal gas, a number of moles per liter in terms of its pressure P, gas constant R and temperature T is:
    Solution
    According to Ideal Gas Equation, $$PV =nRT$$
    P is the pressure, V is the volume, n is the number of moles, R is gas constant and T is the temperature. 
    Therefore number of moles per litre, 
     $$ \frac{n}{v}  $$ =  $$ \frac{P}{RT}  $$ 
    Therefore, C is the correct option. 
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