States of Matter Test

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States of Matter Test - 46

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Weekly Quiz Competition

Question 1
1 / -0

In the gas equation $$PV = nRT$$ , the value of $$R$$ depends upon:

A
Nature of gas

B
The pressure of gas

C
Unit of measurement

D
Temperature of gas

Solution

$$R$$ is the universal gas constant. It has a fixed value which depends upon the units in which $$P, V, n$$ and $$T$$ are expressed in the ideal gas equation, $$PV = nRT$$.

It's values are

$$0.0821\ L\cdot atm\cdot mol^{-1}\cdot K^{-1}$$ ,

$$8.314\ J\cdot mol^{-1}\cdot K^{-1}$$ or

$$2 \ cal\cdot mol^{-1}\cdot K^{-1}$$

Thus, option C is correct.
Question 2
1 / -0

Mass of a given gas occupies two litre at STP. By keeping the pressure constant, at what temperature the gas will occupy 4 litre?

A
$$ 546\ K $$

B
$$ 273\ K $$

C
$$ 100^oC $$

D
$$ 50^oC $$

Solution

At constant pressure,

$$V \propto T$$

$$V= KT$$

So if volume becomes double then temperature also becomes double.

Initial temperature at STP is 273 K which becomes 546 K.

Hence, option A is correct.
Question 3
1 / -0

When the pressure of 5L of $$N_2$$ is double and its temperature is raised from 300K to 600K, the final volume of the gas would be:

A
10 L

B
5 L

C
15 L

D
20 L

Solution

Since $$\dfrac{PV}{T}=nR=constant$$

$$\Rightarrow \dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$$

$$\Rightarrow \dfrac{P_1\times5}{300}=\dfrac{2P_1\times V_2}{600}$$

$$\Rightarrow V_2=5\ L$$
Question 4
1 / -0

If $$500ml$$ of a gas $$A$$ at $$1000$$ torr, and $$1000ml$$ of gas $$B$$ at $$800$$ torr are placed in $$2L$$ container the final pressure will be -

A
$$100$$ torr

B
$$650$$ torr

C
$$1800$$ torr

D
$$2400$$ torr

Solution

According to Boyle's Law (Modified)
$$P_1V_1+P_2V_2+........=P_fV_f$$
Given,
$$P_1=1000;\quad V_1=500$$ $$mL$$
$$P_2=800;\quad V_2=1000$$ $$mL$$
$$P_f=?;\quad V_f=2000$$ $$mL$$
$$\implies P_1V_1+P_2V_2=P_fV_f$$
$$\implies (1000)(500)+(800)(1000)=(P_f)(2000)$$
$$\implies \cfrac {1300}{2}=P_f$$
$$\implies P_f=650$$ $$torr$$
Question 5
1 / -0

The vapour pressure of a solution containing 5 g of a non electrolyte in 100 g of water at a particular temperature is $$2985 N{m}^{-2}$$. If the vapour pressure of pure water is $$3000 N{m}^{-2}$$, the molecular weight of solute is:

A
$$60$$

B
$$120$$

C
$$180$$

D
$$380$$

Solution

we have formula of $$\text{Relative lowering of vapour pressure}$$ which is

$$\dfrac{P_o-P}{P_o}=X_{solute}=\dfrac{n_{solute}}{n_{solute}+n_{solvent}}\approx\dfrac{n_{solute}}{n_{solvent}}$$

Now, pute the values

$$\dfrac{3000-2985}{3000}=\dfrac{\dfrac{5}{M}}{\dfrac{100}{18}}$$

$$\dfrac{15}{3000}=\dfrac{5\times 18}{100\times M}$$

$$M=180$$

correct answer is C.
Question 6
1 / -0

The temperature and pressure at which ice, liquid. water and water vapour can exist together are ?

A
$${ 0 }^{ o }C,\quad 1 atm $$

B
$${ 2 }^{ o }C,\quad 4.7atm$$

C
$${ 0 }^{ o }C,\quad 4.7mm$$

D
$${ -2 }^{ o }C,\quad 4.7mm$$

Solution

The temperature and pressure at which ice, liquid, water and water vapour exist together at triple point of water.
Triple point of water is $$0^\circ C \ and \ 4.7mm$$
Hence, Option "C" is the correct answer.
Question 7
1 / -0

Which of the following is an anti-knocking compound, that has been phased out in many countries so far?

A
Lead tetrachloride

B
Tetra Ethyl Lead

C
Ethyl tetrachloride

D
None of these

Solution

Given :Which of the following is an anti-knocking compound, that has been phased out in many countries so far?

Solution :
An anti-knocking agent is a chemical compound that, when added to gasoline, raises the octane value of the gasoline.
Tetra Ethyl Lead is an anti-knocking compound, that has been phased out in many countries so far.
The Correct Opt = B
Question 8
1 / -0

A gas is said to behave like an ideal gas when the relation $$\dfrac{PV}{T} =$$ constant. When do you expect a real gas to behave like an ideal gas?

A
When the temperature is low

B
When both the temperature and pressure are low

C
When both the temperature and pressure is high

D
When the temperature is high and pressure is low

Solution

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure, as the potential energy due to inter molecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them.
Hence option $$D$$ is correct answer.
Question 9
1 / -0

According to the equipartition principle, each degree of freedom contribute following amount to the translational kinetic energy of molecule: (hence k = Boltzmann constant)

A
$$\dfrac{1}{2} kT$$

B
$$kT$$

C
$$\dfrac{3}{2} kT$$

D
$$\dfrac{1}{3} kT$$

Solution

According to the equipartition principle, each degree of freedom contributes an amount of $$\dfrac{1}{2}kT$$ to the kinetic energy of the molecule.
Question 10
1 / -0

The solubility of a specific non-volatile salt is $$4\mathrm { g }$$ in $$100\mathrm { g }$$ of water at $$25 ^ { \circ } \mathrm { C } .$$ If $$2.0 g,$$ $$4.0\mathrm g$$ and $$6.0 g$$ of the salt added of $$100 g$$ of water at $$25 ^ { \circ } \mathrm { C } ,$$ in system $$X , Y$$ and $$Z .$$ The vapour pressure would be in the order:

A
$$X < Y < Z$$

B
$$X > Y > Z$$

C
$$Z > X = Y$$

D
$$x > Y = z$$

Solution

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States of Matter Test - 46

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States of Matter Test - 46

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Question 1

Nature of gas

The pressure of gas

Unit of measurement

Temperature of gas

Solution

Question 2

$$ 546\ K $$

$$ 273\ K $$

$$ 100^oC $$

$$ 50^oC $$

Solution

Question 3

10 L

5 L

15 L

20 L

Solution

Question 4

$$100$$ torr

$$650$$ torr

$$1800$$ torr

$$2400$$ torr

Solution

Question 5

$$60$$

$$120$$

$$180$$

$$380$$

Solution

Question 6

$${ 0 }^{ o }C,\quad 1 atm $$

$${ 2 }^{ o }C,\quad 4.7atm$$

$${ 0 }^{ o }C,\quad 4.7mm$$

$${ -2 }^{ o }C,\quad 4.7mm$$

Solution

Question 7

Lead tetrachloride

Tetra Ethyl Lead

Ethyl tetrachloride

None of these

Solution

Question 8

When the temperature is low

When both the temperature and pressure are low

When both the temperature and pressure is high

When the temperature is high and pressure is low

Solution

Question 9

$$\dfrac{1}{2} kT$$

$$kT$$

$$\dfrac{3}{2} kT$$

$$\dfrac{1}{3} kT$$

Solution

Question 10

$$X < Y < Z$$

$$X > Y > Z$$

$$Z > X = Y$$

$$x > Y = z$$

Solution

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