States of Matter Test

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States of Matter Test - 72

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Weekly Quiz Competition

Question 1
1 / -0

The density of air 380K and 722 mm of Hg is 1g/$${ cm }^{ 3 }$$. If air is cooled to 100K and 1 atm the final density is:

A
4

B
5

C
6

D
7
Question 2
1 / -0

What is the total pressure (atm) in the chamber ?

A
83.14

B
831.4

C
8.21

D
None
Question 3
1 / -0

For which of the following reactions, Gay Lussac's law is not applicable:

A
Formation of $$HI$$ from its constituents

B
Formation of $$N H_{3}$$ from its constituents

C
Formation of $$C O_{2}$$ from its constituents

D
Formation of $$
S O_{3}
$$ from $$
S O_{2}
$$ and $$
O_{2}
$$

Solution
Question 4
1 / -0

Directions For Questions

The apparatus shown consists of three temperature jacketed $$1.642$$ L bulbs connected by stopcocks. Bulb A contains a mixture of $$H_2O(g), CO_2(g)$$ and $$N_2(g)$$ at $$27^o$$C and a total pressure of $$570$$ mm Hg. Bulb B is empty and held at a temperature of $$-73^o$$C. Bulb C is also empty and is held at a temperature of $$-193^o$$C. The stopcocks are closed and the volume of the lines connecting the bulbs is zero. $$CO_2$$ sublimes at $$-78^o$$C and $$N_2$$ boils at $$-196^o$$C. Neglect the volume of any solid, if formed.

...view full instructions

Both stopcocks are opened and the system is again allowed to come at equilibrium. The pressure throughout the system is $$33.5$$ mm Hg. What do bulbs A, B and C contain?

A
$$A:N_2(g), B:N_2(g), H_2O(s), C:N_2(g), H_2O(s), CO_2(s)$$

B
$$A:N_2(g), B:N_2(g), H_2O(s), C:N_2(g), CO_2(s)$$

C
$$A:N_2(g), B:N_2(g), H_2O(s), CO_2(s), C:N_2(g), H_2O(s), CO_2(s)$$

D
$$A:N_2(g), B:N_2(g), H_2O(s), CO_2(g), C:N_2(g)m H_2O(s), CO_2(s)$$
Question 5
1 / -0

A steel rigid vessel of volume $$1 l$$ is filled with a mixture of methane and oxygen at a total pressure of one atm at $$27^o$$C. The gas mixture is exploded. What would be the final pressure of the products at $$127^o$$C? Aqueous tension at $$27^o$$C$$=0.04$$ atm.

A
$$3.13$$ atm

B
$$1.33$$ atm

C
$$1.28$$ atm

D
$$2.08$$ atm
Question 6
1 / -0

Which of the following behaviour is true about the ideal binary liquid solution of liquids A and B if $$ P^0_A < P^0_B $$?

A
plot of $$ P_{total}| vs X_A $$ in non linear

B
plot of $$ P_{total}| vs X_B $$ is linear with +ve slope

C
plot of $$ P_{total}| vs X_B $$ is linear with slope = 0

D
plot of $$ P_{total}| vs X_B $$ is linear with -ve slope

Solution
Question 7
1 / -0

Directions For Questions

The apparatus shown consists of three temperature jacketed $$1.642$$ L bulbs connected by stopcocks. Bulb A contains a mixture of $$H_2O(g), CO_2(g)$$ and $$N_2(g)$$ at $$27^o$$C and a total pressure of $$570$$ mm Hg. Bulb B is empty and held at a temperature of $$-73^o$$C. Bulb C is also empty and is held at a temperature of $$-193^o$$C. The stopcocks are closed and the volume of the lines connecting the bulbs is zero. $$CO_2$$ sublimes at $$-78^o$$C and $$N_2$$ boils at $$-196^o$$C. Neglect the volume of any solid, if formed.

...view full instructions

The stopcock between A and B is opened and the system is allowed to come to equilibrium. The pressure in A and B is now $$0.21$$ atm.
How many moles of $$H_2O$$ are in the system?

A
$$0.0075$$

B
$$0.015$$

C
$$0.05$$

D
$$0.035$$

Solution

No. of moles in flask A

Given:
P= 570 mm of Hg = 570/ 760 atm, V=1.642 L, T = 300 K

$$n=\dfrac{PV}{RT}=\dfrac{570\times 1.642}{760\times 0.082\times 300}$$

$$n=0.05$$ moles

$$n_{N_2}+n_{CO_2}+n_{H_2O}=0.05$$ moles

Upon opening the stop cock, the gases will dispose

In flask A: $$CO_2+N_2=(n_{CO_2}+n_{N_2})$$ ……$$(1)$$

In flask B: $$CO_2+N_2+H_2O=(n_{CO_2}+n_{H_2}+n_{H_2O})$$ ……….$$(2)$$

$$(2) - (1)$$

$$\Rightarrow n_{CO_2}+n_{N_2}+n_{H_2O}-(n_{CO_2}+n_{N_2})=n_{H_2O}$$
in flask A

no. of moles$$=\dfrac{0.21\times 1.642}{0.082\times 300}=0.014$$
in flask B

no. of moles$$=\dfrac{0.21\times 1.642}{0.082\times 200}=0.021$$

Total moles$$=(0.014+0.021)=n_{H_2O}$$

$$n_{H_2O}=0.05-0.035$$

$$=0.015$$ Option B.
Question 8
1 / -0

If water vapor comprises 3.5 percent of an air parcel whose total pressure is 1,000 mb, the water vapor pressure would be:

A
1,035 mb

B
35 mb

C
350 mb

D
965 mb

Solution

The water vapor pressure would be 35 mb because if the water vapor comprises 3.5 percent of the air parcel and the amount of the total pressure would be 1,000 mb. The temperature of the air parcel decreases due to the cause of work and expansion of the raised air parcel. The humidity increases until it reaches 100% inside the air parcel and the largest aerosol particles forming the excess water vapor during the cloud droplets in the beginning. It makes less sense as it rises during the expansion of the air parcel and increases in altitude because the air pressure starts decreasing around the parcel. But sometimes it became less dense when the temperature of the rising parcel was found in the coolest state.
hence answer is the option b
Question 9
1 / -0

One monoatomic gas is expanded adibatically from $$2L$$ to $$10L$$ at $$1\ atm$$ external pressure find $$\triangle U$$ (in atm $$L$$)?

A
$$-8$$

B
$$0$$

C
$$-66.7$$

D
$$58.2$$

Solution

Process is adiabatic $$\therefore Q = 0$$
$$\therefore \triangle U = W = -P_{ext} \triangle V$$
$$= -1 (10 - 2)\ atm \ L$$
$$= -8\ atm\ L$$.
Question 10
1 / -0

When the air temperature is below freezing, the saturation vapor pressure over water is _______.

A
Equal to zero

B
Less than the saturation vapor pressure over ice

C
Greater than the saturation vapor pressure over ice

D
Equal to the saturation vapor pressure over ice

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States of Matter Test - 72

Result

States of Matter Test - 72

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SHARING IS CARING

Question 1

4

5

6

7

Question 2

83.14

831.4

8.21

None

Question 3

Formation of $$HI$$ from its constituents

Formation of $$N H_{3}$$ from its constituents

Formation of $$C O_{2}$$ from its constituents

Formation of $$ S O_{3} $$ from $$ S O_{2} $$ and $$ O_{2} $$

Solution

Question 4

$$A:N_2(g), B:N_2(g), H_2O(s), C:N_2(g), H_2O(s), CO_2(s)$$

$$A:N_2(g), B:N_2(g), H_2O(s), C:N_2(g), CO_2(s)$$

$$A:N_2(g), B:N_2(g), H_2O(s), CO_2(s), C:N_2(g), H_2O(s), CO_2(s)$$

$$A:N_2(g), B:N_2(g), H_2O(s), CO_2(g), C:N_2(g)m H_2O(s), CO_2(s)$$

Question 5

$$3.13$$ atm

$$1.33$$ atm

$$1.28$$ atm

$$2.08$$ atm

Question 6

plot of $$ P_{total}| vs X_A $$ in non linear

plot of $$ P_{total}| vs X_B $$ is linear with +ve slope

plot of $$ P_{total}| vs X_B $$ is linear with slope = 0

plot of $$ P_{total}| vs X_B $$ is linear with -ve slope

Solution

Question 7

$$0.0075$$

$$0.015$$

$$0.05$$

$$0.035$$

Solution

Question 8

1,035 mb

35 mb

350 mb

965 mb

Solution

Question 9

$$-8$$

$$0$$

$$-66.7$$

$$58.2$$

Solution

Question 10

Equal to zero

Less than the saturation vapor pressure over ice

Greater than the saturation vapor pressure over ice

Equal to the saturation vapor pressure over ice

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Formation of $$
S O_{3}
$$ from $$
S O_{2}
$$ and $$
O_{2}
$$