Hydrogen Test

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Hydrogen Test - 10

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Weekly Quiz Competition

Question 1
1 / -0

When sodium peroxide is treated with dilute sulphuric acid, we get.

A
Sodium sulphate and water

B
Sodium sulphate and oxygen

C
Sodium sulphate, hydrogen and oxygen

D
Sodium sulphate and hydrogen peroxide

Solution

\(Na_2O_2\) + dil.\(H_2SO_4\) → \(Na_2SO_4\) + \(H_2O_2\)
Question 2
1 / -0

Hydrogen peroxide is obtained by the electrolysis of.......

A
Water

B
Sulphuric acid

C
Hydrochloric acid

D
Fused sodium peroxide

Solution

\(2HSO^-_4(aq)\) \(\overset{electrolysis}{\longrightarrow}\) \(HO_3SOOSO_3H(aq)\) \(\overset{hydrolysis}{\longrightarrow}\) \(2HSO_4^-(aq)\) + \(2H^+(aq)\) + \(H_2O_2(aq)\)
Question 3
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Which of the following reactions is an example of use of water gas in the synthesis of other compounds?

A
\(CH_4 (g) + H_2O (g)\underset{Ni}{\overset{1270\,k}{\longrightarrow}} \) \(CO (g) + H_2 (g)\)

B
\(CO (g) + H_2O (g) \underset{Catalyst}{\overset{673\,k}{\longrightarrow}} \) \(CO_2 (g) + H_2 (g)\)

C
\(C_nH_{2n+2} + nH_2O (g) \underset{Ni}{\overset{1270\,k}{\longrightarrow}} \) \(nCO + (2n+1) H_2\)

D
\(CO (g) + 2H_2 (g) \underset{Catalyst}{\overset{Cobalt}{\longrightarrow}}\) \( CH_3OH (l)\)

Solution

The reaction shown in equation(iv) shows the synthesis of methanol from water gas.
Question 4
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Which of the following statements is correct?

(i) Elements of group 15 form electron deficient hydrides.

(ii) All elements of group 14 form electron precise hydrides.

(iii) Electron precise hydrides have tetrahedral geometries.

(iv) Electron rich hydrides can act as Lewis acids.

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

Electron precise hydrides have the required number of electrons to write their conventional Lewis structures. All elements of group 14 form such compounds (e.g., \(CH_4 \)) which are tetrahedral in geometry.
Question 5
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Which of the following statements is correct?

(i) Hydrides of group 13 act as Lewis acids.

(ii) Hydrides of group 14 are electron deficient hydrides.

(iii) Hydrides of group 14 act as Lewis acids.

(iv) Hydrides of group 15 act as Lewis bases.

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

All elements of group 13 forms electron-deficient compounds and thus acts as Lewis acids. Electron-rich hydrides have excess electrons which are present as lone pairs. Elements of group 15-17 form such compounds.

Question 6

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Match the terms in Column I with the relevant item in Column II.

Column I	Column II
(i) Electrolysis of water produces	(a) atomic reactor
(ii) Lithium aluminum hydride is used as	(b) polar molecule
(iii) Hydrogen chloride is a	(c) recombines on metal surface to generate high temperature
(iv) Heavy water is used in	(d) reducing agent
(v) Atomic hydrogen	(e) hydrogen and oxygen

(i) → (e) (ii) → (d) (iii) → (b) (iv) → (a) (v) → (c)

(i) → (e) (ii) → (d) (iii) → (b) (iv) → (c) (v) → (a)

(i) → (e) (ii) → (b) (iii) → (d) (iv) → (a) (v) → (c)

(i) → (e) (ii) → (a) (iii) → (b) (iv) → (d) (v) → (c)

Question 7
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Which of the following statements is correct?

(i) Metallic hydrides are deficient of hydrogen.

(ii) Metallic hydrides conduct heat and electricity.

(iii) Ionic hydrides do not conduct electricity in solid state.

(iv) Ionic hydrides are very good conductors of electricity in solid state.

A
(ii),(iii),(iv)

B
(i),(iii),(iv)

C
(i),(ii),(iv)

D
(i),(ii),(iii)

Solution

Ionic hydrides are crystalline, non-volatile and non-conducting in solid state.
Question 8
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In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): Some metals like platinum and palladium, can be used as storage media for hydrogen.

Reason (R): Platinum and palladium can absorb large volumes of hydrogen.

A
Statements A and R both are correct and R is the correct explanation of A

B
A is correct but R is not correct

C
A and R both are correct but R is not the correct explanation of A

D
A and R both are false

Question 9

1 / -0

Match the items in Column I with the relevant item in Column II.

Column I	Column II
(i) Hydrogen peroxide is used as a	(a) zeolite
(ii) Used in Calgon method	(b) perhydrol
(iii) Permanent hardness of hard water is removed by	(c) sodium hexametaphosphate
	(d) propellant

(i) → (b), (d) (ii) → (b) (iii) → (a), (c)

(i) → (b), (d) (ii) → (c) (iii) → (a), (c)

(i) → (a), (d) (ii) → (c) (iii) → (b), (c)

(i) → (b), (c) (ii) → (c) (iii) → (a), (d)

Question 10
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Which of the following ions will cause hardness in water sample?

A
\(Ca^{2+}\)

B
\(Na^+\)

C
\(Cl^-\)

D
\(K^+\)

Solution

Presence of calcium and magnesium salts in the form of hydrogencarbonate, chloride and sulphate in water makes water ‘hard’.
Question 11
1 / -0

Which of the following compounds is used for water softening?

A
\(Ca_3 (PO_4)_2\)

B
\(Na_3PO_4\)

C
\(Na_6P_6O_{18}\)

D
\(Na_2HPO_4\)

Solution

Sodium hexametaphosphate(\(Na_6P_6O_{18}\)), commercially called ‘calgon’, is used to remove hardness from water.
Question 12
1 / -0

Elements of which of the following group(s) of periodic table do not form hydrides?

A
Groups 7,8,9

B
Group 13

C
Groups 15, 16, 17

D
Group 14

Solution

The metals of group 7, 8 and 9 do not form hydrides.
Question 13
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Only one element of forms hydride.

A
Group 6

B
Group 7

C
Group 8

D
Group 9

Solution

From group 6, only chromium forms CrH.
Question 14
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Which of the following reacts easily with \(H_2O\) to form hydrogen

A
\(HCl\)

B
\(KH\)

C
\(NH_3\)

D
\(B_2H_6\)

Solution

KH react easily with \(H_2O\) to form hydrogen.
Question 15
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Which of the following metal evolves hydrogen on reacting with cold dilute \(HNO_3\)?

A
Mg

B
Al

C
Fe

D
Cu

Solution

Mg reacts with nitric acid to give \(Mg(NO_3)_2\) and evolves \(H_2\)

\(Mg+2HNO_3\rightarrow Mg(NO_3)_2+H_2\)

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Hydrogen Test - 10

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Hydrogen Test - 10

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Question 1

Sodium sulphate and water

Sodium sulphate and oxygen

Sodium sulphate, hydrogen and oxygen

Sodium sulphate and hydrogen peroxide

Solution

Question 2

Water

Sulphuric acid

Hydrochloric acid

Fused sodium peroxide

Solution

Question 3

\(CH_4 (g) + H_2O (g)\underset{Ni}{\overset{1270\,k}{\longrightarrow}} \) \(CO (g) + H_2 (g)\)

\(CO (g) + H_2O (g) \underset{Catalyst}{\overset{673\,k}{\longrightarrow}} \) \(CO_2 (g) + H_2 (g)\)

\(C_nH_{2n+2} + nH_2O (g) \underset{Ni}{\overset{1270\,k}{\longrightarrow}} \) \(nCO + (2n+1) H_2\)

\(CO (g) + 2H_2 (g) \underset{Catalyst}{\overset{Cobalt}{\longrightarrow}}\) \( CH_3OH (l)\)

Solution

Question 4

(i),(ii)

(ii),(iii)

(iii),(iv)

(i),(iv)

Solution

Question 5

(i),(ii)

(ii),(iii)

(iii),(iv)

(i),(iv)

Solution

Question 6

(i) → (e) (ii) → (d) (iii) → (b) (iv) → (a) (v) → (c)

(i) → (e) (ii) → (d) (iii) → (b) (iv) → (c) (v) → (a)

(i) → (e) (ii) → (b) (iii) → (d) (iv) → (a) (v) → (c)

(i) → (e) (ii) → (a) (iii) → (b) (iv) → (d) (v) → (c)

Question 7

(ii),(iii),(iv)

(i),(iii),(iv)

(i),(ii),(iv)

(i),(ii),(iii)

Solution

Question 8

Statements A and R both are correct and R is the correct explanation of A

A is correct but R is not correct

A and R both are correct but R is not the correct explanation of A

A and R both are false

Question 9

(i) → (b), (d) (ii) → (b) (iii) → (a), (c)

(i) → (b), (d) (ii) → (c) (iii) → (a), (c)

(i) → (a), (d) (ii) → (c) (iii) → (b), (c)

(i) → (b), (c) (ii) → (c) (iii) → (a), (d)

Question 10

\(Ca^{2+}\)

\(Na^+\)

\(Cl^-\)

\(K^+\)

Solution

Question 11

\(Ca_3 (PO_4)_2\)

\(Na_3PO_4\)

\(Na_6P_6O_{18}\)

\(Na_2HPO_4\)

Solution

Question 12

Groups 7,8,9

Group 13

Groups 15, 16, 17

Group 14

Solution

Question 13

Group 6

Group 7