Hydrogen Test

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Hydrogen Test - 18

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Weekly Quiz Competition

Question 1
1 / -0

$$H_{2}O_{2}$$ present in the atmosphere is formed by the action of sunlight on the atmospheric:

A
$$H_{2}$$ and $$O_{2}$$

B
$$H_{2}O$$ and $$O_{3}$$

C
moisture and $$O_{2}$$

D
$$H_{2}O$$ and $$SO_{2}$$

Solution

$$H_2O_2$$ present in the atmosphere is formed by the action of sunlight on the atmospheric $$H_2O$$ and $$O_3$$.
The reaction is as follows:
$$H_2O + \dfrac 13O_3 + \text{hv} \rightarrow H_2O_2$$
Question 2
1 / -0

$$H_{2}O_{2}$$ forms prismatic crystals at:

A
$$0^{o}C$$

B
$$2^{o}C$$

C
$$2K$$

D
$$-1.7^{o}C$$

Solution

On cooling, $$95-96\%$$, the peroxide in solid carbon dioxide and ether, or in methyl chloride at $$-23^oC$$, solidifies to a hard crystalline mass.

If a little of this solid is placed in the $$95\%$$ and the solution is cooled to $$-10^oC$$, columnar prismatic crystals of pure solid hydrogen peroxide melting at $$-1.7^oC$$ are obtained. These crystals explode with a trace of platinum black; alone, they are fairly stable.
Question 3
1 / -0

The product obtained at anode when $$50\%\: H_{2}SO_{4}$$ aqueous solution is electrolysed using platinum electrodes is :

A
$$H_{2}SO_{3}$$

B
$$H_{2}S_{2}O_{8}$$

C
$$O_{2}$$

D
$$H_{2}$$

Solution

Hydrogen peroxide can be produced by electrolysis of sulfuric acid. At the anode the following reaction takes place:
$$H_2SO_4^- \rightarrow S_2O_8^{2-} + 2H^+ + 2e^-$$
The reaction of this ion with water serves as a commercial preparation of hydrogen peroxide:
$$S_2O_8^{2-}(aq) + H_2O\rightarrow H_2O_2(aq) + 2HSO_4^- $$
Question 4
1 / -0

The melting point of most of the solid substances increases with an increase in pressure. However ice melts at a temperature lower than its usual melting points when pressure is increased. This is because:

A
the density of ice is lesser than $$H_{2}O$$

B
pressure generates heats

C
the chemical bonds break under pressure

D
ice is not a true solid

Solution

This can be explained with the help of Le Chatelier's principle.
As the density of ice is lesser and has more volume than water while applying pressure the volume decreases due to which its equilibrium is subjected to change and to counteract the effect of the change, it converts into liquid (water).
Question 5
1 / -0

Electrolysis of $$50\%\: H_{2}SO_{4}$$ produces:

A
$$H_{2}S_{2}O_{8}$$ at anode

B
$$H_{2}$$ at anode

C
$$H_{2}SO_{5}$$ at cathode

D
$$H_{2}O_{2}$$ at anode

Solution

Hydrogen peroxide can be produced by electrolysis of sulfuric acid. At the anode the following reaction takes place:
$$H_2SO_4^- \rightarrow S_2O_8^{2-} + 2H^+ + 2e^-$$
The reaction of this ion with water serves as a commercial preparation of hydrogen peroxide:
$$S_2O_8^{2-}(aq.) + H_2O\rightarrow H_2O_2(aq.) + 2HSO_4^- $$.
Question 6
1 / -0

Catalytic union of $$H_{2}$$ and $$O_{2}$$to get $$H_{2}O_{2}$$ is:

A
auto oxidation

B
electrolysis of $$50\%\:Na_{2}O_{2}$$

C
hydrolysis of aqueous solution of $$\left ( NH_{4} \right )_{2}SO_{4}+H_{2}SO_{4}$$

D
treating $$Na_{2}O_{2}$$ with cold dil. $$Na_{2}O_{2}$$

Solution

Auto oxidation is any oxidation that occurs in open air or in presence of oxygen and UV radiation and forms peroxides and hydroperoxides. A classic example of autoxidation is that of simple ethers like diethyl ether, whose peroxides can be dangerously explosive. It can be considered to be a slow, flameless combustion of materials by reaction with oxygen. Autoxidation is important because it is a useful reaction for converting compounds to oxygenated derivatives, and also because it occurs in situations where it is not desired (as in the destructive cracking of the rubber in automobile tires).
Question 7
1 / -0

In the preparation of $$H_{2}O_{2}$$ by auto-oxidation method, the starting substance is:

A
2-ethylanthraquinone.

B
2-ethylanthraquinol.

C
p-benzoquinone.

D
N-methylaniline.

Solution

In the auto-oxidation method, 2-Ethylanthraquinone is reduced to 2-ethylanthraquinol by Hydrogen in the presence of palladium. This 2-ethylanthraquinol is oxidised by air to 2-ethylanthraquinone again.

Then $$ H_{2}O_{2}$$ forms. so here the starting substance is 2-ethylanthraquinone.

Hence, the correct option is $$\text{A}$$
Question 8
1 / -0

Which of the following compound gives $$H_{2}O_{2}$$ by the addition of $$H_{2}O$$?

A
$$CO(NH_2)_2.H_2O_2$$

B
$$Na_{2}HPO_{4}.H_{2}O_{2}$$

C
$$(NH_{4})_{2}SO_{4}.H_{2}O_{2}$$

D
All of the above

Solution

$$CO(NH_{2})_{2}.H_{2}O_{2}\overset {water}{\longrightarrow} CO(NH_{2})_{2}+H_{2}O_{2}$$

$$Na_{2}HPO_{4}.H_{2}O_{2}\overset{water}{\longrightarrow} Na_{2}HPO_{4}+H_{2}O_{2}$$

$$(NH_{4})_{2}SO_{4}.H_{2}O_{2}\overset{water}{\longrightarrow}(NH_{4})_{2}SO_{4}+H_{2}O_{2}$$

Hence, option D is correct,
Question 9
1 / -0

Which one of the following compounds undergoes hydrolysis during distillations to yield hydrogen peroxide?

A
$$H_{2}S_{2}O_{8}$$

B
$$H_{2}S_{2}O_{6}$$

C
$$HNO_{3}$$

D
$$H_{4}P_{2}O_{7}$$

Solution

One of the methods of preparation of $$H_2O_2$$ is from sulphuric acid.
Electrolysis of acidic sulphate solutions leads to the formation of peroxodisulfuric acid which then further hydrolyses to give $$H_2O_2$$.
Question 10
1 / -0

Assertion (A): Hydrogen shows resemblance with alkali metals as well as halogens.
Reason (R): Hydrogen exists in atomic form only at high temperature.

A
Both A and R are true and R is the correct explanation of A

B
Both A and R are true but R is not a correct explanation of A

C
A is true but R is false

D
A is false but R is true

Solution

Hydrogen is having similarities with alkali metals and halogens in many properties because of only 1 valence electron.
Hydrogen exists in atomic form at high temperatures. At normal it exists as a diatomic molecule.

Both assertion and reason are true but the reason does not satisfy the assertion.
Option B is correct.

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Hydrogen Test - 18

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Hydrogen Test - 18

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Question 1

$$H_{2}$$ and $$O_{2}$$

$$H_{2}O$$ and $$O_{3}$$

moisture and $$O_{2}$$

$$H_{2}O$$ and $$SO_{2}$$

Solution

Question 2

$$0^{o}C$$

$$2^{o}C$$

$$2K$$

$$-1.7^{o}C$$

Solution

Question 3

$$H_{2}SO_{3}$$

$$H_{2}S_{2}O_{8}$$

$$O_{2}$$

$$H_{2}$$

Solution

Question 4

the density of ice is lesser than $$H_{2}O$$

pressure generates heats

the chemical bonds break under pressure

ice is not a true solid

Solution

Question 5

$$H_{2}S_{2}O_{8}$$ at anode

$$H_{2}$$ at anode

$$H_{2}SO_{5}$$ at cathode

$$H_{2}O_{2}$$ at anode

Solution

Question 6

auto oxidation

electrolysis of $$50\%\:Na_{2}O_{2}$$

hydrolysis of aqueous solution of $$\left ( NH_{4} \right )_{2}SO_{4}+H_{2}SO_{4}$$

treating $$Na_{2}O_{2}$$ with cold dil. $$Na_{2}O_{2}$$

Solution

Question 7

2-ethylanthraquinone.

2-ethylanthraquinol.

p-benzoquinone.

N-methylaniline.

Solution

Question 8

$$CO(NH_2)_2.H_2O_2$$

$$Na_{2}HPO_{4}.H_{2}O_{2}$$

$$(NH_{4})_{2}SO_{4}.H_{2}O_{2}$$

All of the above

Solution

Question 9

$$H_{2}S_{2}O_{8}$$

$$H_{2}S_{2}O_{6}$$

$$HNO_{3}$$

$$H_{4}P_{2}O_{7}$$

Solution

Question 10

Both A and R are true and R is the correct explanation of A

Both A and R are true but R is not a correct explanation of A

A is true but R is false

A is false but R is true

Solution

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