Hydrogen Test

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Hydrogen Test - 22

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Weekly Quiz Competition

Question 1
1 / -0

An excess of acidified solution of $$KI$$ is added to a $$25$$ mL $$H_2O_2$$ solution. The iodine liberated requires $$20$$ mL of $$0.3\ N\ Na_2S_2O_3$$ solution. Calculate the volume strength of $$H_2O_2$$:

A
$$1.144$$

B
$$1.244$$

C
$$1.344$$

D
$$1.444$$

Solution

$$I_{2}+2Na_{2}S_{2}O_{3}\rightarrow Na_{2}S_{4}O_{6}+2NaI$$
$$20$$ ml of $$0.3M(=0.3N)$$ $$Na_{2}S_{2}O_{3}$$ will react with $$\dfrac {(20)(0.3)}{(1000)(2)}$$ moles of $$I_{2}$$ which is $$0.003$$ moles or $$0.006$$ equivalents. Thus there are $$0.006$$ equivalents in $$25$$ ml of $$H_{2}O_{2}$$, hence, its normality is $$0.24$$ N and thus, the volume strength is $$0.24 \times 5.6 =1.344$$.
Question 2
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Assertion: Reducing power of nascent hydrogen is more than atomic hydrogen.
Reason: Bond energy of hydrogen is maximum.

A
Both Assertion & Reason are correct and Reason is correct explanation of Assertion

B
Both Assertion & Reason are correct but Reason is not correct explanation of Assertion

C
Assertion is correct but Reason is incorrect

D
Assertion is wrong but Reason is correct

Solution

The reducing power of atomic hydrogen is much higher than that of nascent hydrogen. Hence, the assertion is wrong.

The bond energy of hydrogen is high. Hence, the diatomic molecule of hydrogen is quite stable and very less reactive.

Thus, the reason is correct.
Question 3
1 / -0

Hydrolith, a source of hydrogen is :

A
$$NaH$$

B
$$ CaH_{2}$$

C
$$LiH$$

D
$$ BaH_{2}$$

Solution

A salt like binary compound $$(CaH_2)$$, calcium hydride used as a reducing agent and source of hydrogen.
Question 4
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Excess of $$KI$$ and dil. $$H_2SO_4$$, were mixed in $$50$$ ml $$H_2O_2$$. The $$I_2$$ liberated required $$20$$ ml of $$0.1$$ N $$Na_2S_2O_3$$. Find out the strength of $$H_2O_2$$ in $$g/lit^{-1}$$?

A
$$0.17 g/lit$$

B
$$0.34 g/lit$$

C
$$0.68 g/lit$$

D
$$1.36 g/lit$$

Solution

$$I_{2}+2Na_{2}S_{2}O_{3}->Na_{2}S_{4}O_{6}+2NaI$$
20ml of 0.1M $$Na_{2}S_{2}O_{3}$$ will react with $$\dfrac {(20)(0.1)}{(1000)(2)}$$ moles of $$I_{2}$$ which is 0.001 moles or 0.002 equivalents. Thus there are 0.002 equivalents in 50ml of $$H_{2}O_{2}$$. Hence, its strength is 0.002 x 17/0.05=0.68
Question 5
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STATEMENT-1: Alkaline earth metals form polymeric hydrides.
STATEMENT-2: Only $$Be$$ and $$Mg$$ among alkaline earth metals forms polymeric hydrides.

A
Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1

B
Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

C
Statement-1 is true, Statement-2 is false

D
Statement-1 is false, Statement-2 is true
Question 6
1 / -0

Which element forms hydride?

A
$$Cr$$

B
$$Mo$$

C
$$W$$

D
$$Sg$$

Solution

Chromium forms hydride when it reacts with hydrogen.

It forms the hydrides having the following formula $$CrH_{0.5}, CrH, CrH_2$$.

Hence, option A is correct.
Question 7
1 / -0

$$20$$ ml of $$H_2O_2$$ after acidification with dil $$H_2SO_4$$. required $$30$$ ml of N/2 $$KMnO_4$$ for complete oxidation. Calculate the % of $$H_2O_2$$ in g/lit.

A
10.75 g/lit

B
11.75 g/lit

C
12.75 g/ lit

D
13.75 g/lit

Solution

$$15$$ milli equivalents of $$KMnO_{4}$$ require $$15$$ milli equivalents of $$H_{2}O_{2}$$.

Hence, $$15$$ milli equivalents are present in $$20$$ ml of sample.

Thus, strength is $$15 \times \dfrac{17}{20} = 12.75$$.
Question 8
1 / -0

Which is polymeric hydride?

A
$$ CaH_{2}$$

B
$$ MgH_{2}$$

C
$$ BaH_{2}$$

D
$$ SrH_{2}$$

Solution

$$MgH_2$$ forms a polymeric hydride by forming bridge bonds with hydrogen.
Question 9
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Which one of the following pairs of reactants does not produce oxygen when they react with each other?

A
$${F}_{2},\ {N}{a}{O}{H}$$ solution (hot, conc.)

B
$${F}_{2},\ {H}_{2}{O}$$

C
$${Cl}_{2},\ {N}{a}{O}{H}$$ solution (cold, dilute)

D
$${C}{a}{O}{C}l_{2},\ {H}_{2}{S}{O}_{4}$$ (dilute, small amount)

Solution

1. Fluorine reacts with hot concentrated $$NaOH$$ solution to form oxygen.
The reaction is as follows:

$$10F_2 + 20 NaOH \rightarrow 20 NaF + 10 O_2 + H_2O$$

2. Fluorine reacts with water to form oxygen.

$$2 F_2 + 2 H_2O \rightarrow O_2 + 4 F^{-} + 4 H^{+}$$.

3. Chlorine reacts with cold dilute $$NaOH$$ solution to form sodium chloride, sodium hypochloride and water. Oxygen is not formed in the reaction.

$$Cl_2+NaOH \rightarrow NaCl+NaOCl+H_2O$$

4. $$CaOCl_2 $$ reacts with small amount of dilute $$ H_2SO_4$$ to produce oxygen.

$$2CaOCl_2+H_2SO_4 \rightarrow CaCl_2+CaSO_4+2HClO$$
$$HClO \rightarrow HCl + O$$

Hence, the only reaction among the four which produce no oxygen is between $$Cl_2$$ and $$NaOH$$ (cold, dilute).

Hence, the correct option is C.
Question 10
1 / -0

Silicon hydrides are called:

A
silicones

B
silicates

C
silicides

D
silanes

Solution

Silicones are organo-silicon polymers that have $$R_2SiO$$ as a repeating unit whereas silicates are compounds having the repeating unit as $$SiO_4^{4-}$$.

A silicide is a compound that has silicon with (usually) more electropositive elements.

Silanes are silicon-hydrogen compounds.

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Hydrogen Test - 22

Result

Hydrogen Test - 22

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Question 1

$$1.144$$

$$1.244$$

$$1.344$$

$$1.444$$

Solution

Question 2

Both Assertion & Reason are correct and Reason is correct explanation of Assertion

Both Assertion & Reason are correct but Reason is not correct explanation of Assertion

Assertion is correct but Reason is incorrect

Assertion is wrong but Reason is correct

Solution

Question 3

$$NaH$$

$$ CaH_{2}$$

$$LiH$$

$$ BaH_{2}$$

Solution

Question 4

$$0.17 g/lit$$

$$0.34 g/lit$$

$$0.68 g/lit$$

$$1.36 g/lit$$

Solution

Question 5

Statement-1 is true, Statement-2 is true; Statement-2 is a correct explanation for Statement-1

Statement-1 is true, Statement-2 is true; Statement-2 is not a correct explanation for Statement-1

Statement-1 is true, Statement-2 is false

Statement-1 is false, Statement-2 is true

Question 6

$$Cr$$

$$Mo$$

$$W$$

$$Sg$$

Solution

Question 7

10.75 g/lit

11.75 g/lit

12.75 g/ lit

13.75 g/lit

Solution

Question 8

$$ CaH_{2}$$

$$ MgH_{2}$$

$$ BaH_{2}$$

$$ SrH_{2}$$

Solution

Question 9

$${F}_{2},\ {N}{a}{O}{H}$$ solution (hot, conc.)

$${F}_{2},\ {H}_{2}{O}$$

$${Cl}_{2},\ {N}{a}{O}{H}$$ solution (cold, dilute)

$${C}{a}{O}{C}l_{2},\ {H}_{2}{S}{O}_{4}$$ (dilute, small amount)

Solution

Question 10

silicones

silicates

silicides

silanes

Solution

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