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Hydrogen Test - 34

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Hydrogen Test - 34
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Complete the following equation$$:$$
    $$Cl_2+H_2O\rightarrow$$
    Solution
    $$Cl_2+H_2O\rightarrow HCl+HClO$$
  • Question 2
    1 / -0
    Which of the following metal reacts with steam to liberate hydrogen?
    Solution
    Less reactive metals such as Magnesium, aluminum, zinc and iron react with steam to liberate hydrogen.
  • Question 3
    1 / -0
    ________ does not expand on melting and does not contract on freezing.
    Solution
    In melting process, ice changes to water and in freezing, water changes to ice. Both occur at 0$$ ^{\circ}C $$ only. Only change of state occurs here and not volume.
  • Question 4
    1 / -0
    Steam reacts with red hot iron to produce?
    Solution
    Steam reacts with red hot iron to produce ferric oxide and hydrogen.
  • Question 5
    1 / -0
    Oxygen is collected by downward displacement of water since it weighs  __________ as/than air.
    Solution
    The weight of oxygen is almost same as that of air.
  • Question 6
    1 / -0
    Which of the following reaction is correct when water reacts with metal?
    Solution
    Potassium reacts vigorously with cold water to form potassium hydroxide and hydrogen gas. With Sodium cold water form sodium hydroxide and hydrogen gas. When cold water reacts with calcium, produce milky turbid solution called Calcium hydroxide and $$H_2$$.
  • Question 7
    1 / -0
    Aluminium carbide reacts with water to give __________.
    Solution
    Aluminium carbide reacts with water gives methane gas.
  • Question 8
    1 / -0
    It is difficult to cook rice in an open vessel by boiling it at high altitudes because of:
    Solution
    At high altitude pressure is low and therefore the boiling point is also low. In this case, water starts boiling below its boiling point but rice cooks at $$100$$. So, it is difficult to cook rice at high altitudes.
  • Question 9
    1 / -0
    Which of the following is not correct regrading the electrolytic preparation of $$H_2O_2$$?
    Solution
    $$H_2O_2$$ can be prepared by electrolysis of 50% $$H_2SO_4$$.
    Here hydrogen is liberated at cathode
    $${ H }_{ 2 }{ SO }_{ 4 }\rightleftharpoons 2{ H }^{ + }+{ S{ O }_{ 4 } }^{ 2- }$$

    At anode:
    $$2{ HS{ O }_{ 4 } }^{ - }\rightleftharpoons H_2S_2O_8+2e^-$$
    $$H_2S_2O_8+H_2O\longrightarrow 2H_2SO_4+H_2O_2$$

    At cathode:
    $$2H^++2e^-\longrightarrow H_2$$
  • Question 10
    1 / -0
    Statement 1: Water is a polar substance.
    Statement 2: The sharing of the bonding electrons in water is unequal.
    Solution
    Since O is more electronegative than H, the bond pair of electrons are more towards O than towards H. The O-H bond is polar covalent bond.
    So both the statements are correct and statement 2 is the correct explanation of statement 1.
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