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Hydrogen Test - 37

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Hydrogen Test - 37
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  • Question 1
    1 / -0
    Which property of water is used while washing clothes?
    Solution
    Water is a good solvent. It combine with dirt and other particles with it when treated with soap, which is water soluble and form lather in water. Hence due to its solubility it is used while washing clothes. 
  • Question 2
    1 / -0
    Statement I: Water has a higher boiling point than expected.
    Statement II: Each molecule forms a hydrogen bond with an adjacent molecule.
    Solution
    Option A is the correct answer.
    Water molecule contains a highly electronegative Oxygen atom in it. Thus water molecules are engaged in extensive intermolecular hydrogen bonding with their nearest water molecules. And thus a bulky molecule is formed.
    High amount of energy is required to dissociate these bonds and hence water molecules have a higher boiling point than expected.
  • Question 3
    1 / -0
    Statement 1: Water boils below $${100}^{o}C$$ at high altitudes. 
    Statement 2: Atmospheric pressure varies inversely with altitude.
    Solution
    Pressure changes inversely with altitudes and boiling point directly proportional to pressure. Pressure and boiling points are low at high altitudes. So water boils below 100$$ ^{\circ}C $$.
  • Question 4
    1 / -0
    Liquids with lower boiling point are more :
    Solution
    The higher the vapor pressure of a liquid at a given temperature, the higher the volatility and the lower the normal boiling point of the liquid. Hence liquids with lower boiling point are more volatile.
  • Question 5
    1 / -0
    Statement $$1$$: Water boils at a higher temperature on the moon.
    Statement $$2$$: The atmospheric pressure of the moon is less than that on earth.
    Solution
    Pressure is directly proportional to boiling point. On moon, there is less atmospheric pressure and because of this boiling point increases. So water boils at high temperature on the moon.
  • Question 6
    1 / -0
    Which of the following is NOT soluble in water?
    Solution
    Sand $$(SiO_2)$$ is not soluble in water.
  • Question 7
    1 / -0
    Balance the chemical reaction of laboratory preparation method of dihydrogen:
    Solution
    Hydrogen is prepared in the laboratory by the action of acids on metals. Dilute sulphuric acid containing 1 volume of concentrated acid to 5 volumes of water, or dilute hydrochloric acid containing 1 volume of concentrated acid to 4 volumes of water, is added to granulated zinc. Zinc sulphate or zinc chloride is formed in solution and the hydrogen that is evolved is collected over water in a trough.
    $$Zn+2{ H }^{ + }⟶{ Zn }^{ 2+ }+{ H }_{ 2 }$$

  • Question 8
    1 / -0
    When steam is passed over red hot iron we get which of the following products?
    Solution
    When steam is passed over red hot iron, ferric oxide and hydrogen is formed.

    $$3Fe+4H_2O\longrightarrow Fe_3O_4+4H_2$$
                                      ferric      Dihydrogen
                                      oxide

    The iron is oxidized to ferric oxide whereas the water is reduced to hydrogen.

    Thus the correct answer is (B) Ferric oxide and hydrogen.
  • Question 9
    1 / -0
    Which of the following would describe the behavior of the molecules or ions of $$AgNO_{3}(s)$$ in water?
    Solution
    $$AgNO_3$$ is an ionic compound. Thus it gets dissociated when added to water into $$Ag^+$$ ions and $${NO_3}^-$$ ions.
    Positively charged $$Ag^+$$ ions will be surrounded by negatively charged oxygen of water molecule and negatively charged $${NO_3}^-$$ ions are surrounded by hydrogens of water molecule to maintain electroneutrality principle.
  • Question 10
    1 / -0
    Water is considered an amphoteric substance. Which of following other substances can also be considered amphoteric?
    Solution
    Substances that can act as acid is one reaction and as a base in another are called amphoteric substances.
    In the first reaction the bisulfate ion,$$ HSO_4^-$$  acts as a base. In the second reaction it acts as an acid:

    1. $$HSO_4^-+H_3O^+\rightarrow H_2SO_4+H_2O$$
    $$HSO_4^-$$  accepts a proton from  $$H_3O^+$$ 

    2. $$HSO_4^-+OH\rightarrow H_2O+SO_4^{-2}$$
    $$HSO_4^-$$  gives (donates) a proton to  $$OH^−$$
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