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Hydrogen Test - 46

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Hydrogen Test - 46
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  • Question 1
    1 / -0
    Which combination do not produce $${ H }_{ 2 }$$ except:-
    Solution
     Because gold (Au) is the least reactive metal, even less than hydrogen, now as Hydrogen is more reactive, gold cannot displace it, hence water and gold will not react.

    $$Cu$$ can't liberate $$H_2$$ from $$H_2SO_4$$ and same case with $$Pt$$ and $$HNO_3$$. 

    Hence option D is correct.
  • Question 2
    1 / -0
    Which of the following has maximum purity
    Solution
    $$ \begin{array}{l} \text { Distilled water is water that has been boiled} \\ \text { into vapour and condensed back into liquid in a } \\ \text { seperate container. Impurities in the original } \\ \text { water that do not boil below or near the} \\ \text { boiling point of water remain in the original } \\ \text { container. } \\ \text { So, Distilled water has maximum purity. } \\ \text { (B) Distilled water. } \end{array} $$
  • Question 3
    1 / -0
    The physical state of water is liquid at which of the following temperatures?
    Solution
    At 0$$ ^{\circ}C $$, water exists as ice. 
    At 100$$ ^{\circ}C $$, it exists as steam.
    At 25$$ ^{\circ}C $$, water exists in liquid form.
  • Question 4
    1 / -0
    Very pure hydrogen $$(99.9\%)$$ can be made by which of the following processes?
    Solution
    Electrolysis of water gives $$99.9$$% pure hydrogen. 

    It is the decomposition of water into Oxygen $$(O_2)$$ and Hydrogen gas $$(H_2)$$, due to an electric current being passed through the water.

    So, option (B) is correct.
  • Question 5
    1 / -0
    Very pure hydrogen (99.9%) can be made by 'which of the following processes?
    Solution
    Highly pure hydrogen can be obtained by electrolysis of water.
    It is the decomposition of water into $$O_2$$ & $$H_2$$ gas by passing electric current.
    At anode, $$6H_2O(l) \longrightarrow O_2(g)+4H_3O^++4e^-$$
    cathode, $$4e^-+4H_2O(l) \longrightarrow 2H_2(g)+4OH^-(aq)$$
    Overall $$\longrightarrow 2H_2O(l) \longrightarrow 2H_2(g)+O_2(g)%$$
  • Question 6
    1 / -0
    Which of the following reaction will not produce hydrogen gas?
    Solution
    $$a)$$ $$Fe_{(s)}+2HCl_{(aq)}\longrightarrow FeCl_{2(aq)}+H_{2(g)}$$
    $$b)$$ $$Zn+conc.\text{ }2H_2SO_4\longrightarrow ZnSO_4+SO_2+2H_2O$$
    $$c)$$ $$Zn+2NaOH\longrightarrow Na_2ZnO_2+H_2$$
    $$d)$$ In Nelson's cell, at cathode:
    $$2H_2O+2e^-\rightleftharpoons H_2+2OH^-$$
    Hence, $$B$$ is the correct answer.
  • Question 7
    1 / -0
    Which of the following compound will evolve $$H_{2}$$ gas when reacts with alkali metals?
    Solution
    Alcohols when reacting with sodium metal evolution of hydrogen gas takes place. For example ethyl alcohol (ethanol) when reacting with sodium metal, the formation of sodium ethoxide and hydrogen gas takes place. It can be shown by the following reaction.
     $$\underset{alcohol}{2R-OH} + 2Na \longrightarrow \underset{sodium \ alkoxide}{2R-O^{-}Na^{+}} + H_{{2}{(g)}}\uparrow$$

    $$\underset{Ethanol}{2R-OH} + 2Na \longrightarrow \underset{sodium \ ethoxide}{2R-O^{-}Na^{+}} + H_{{2}{(g)}}\uparrow$$

    Hence, option $$D$$ is correct.
  • Question 8
    1 / -0
    $${ H_{ 2 }O }_{ 2 }$$ is:
    Solution
    $$H_2O_2$$ is both oxidizing as well as reducing agent.
    These two chemical equation shows different behaviour of $$H_2O_2$$ :-
    $$\longrightarrow H_2O_2+2I^-+2H^+ \longrightarrow I_2+2H_2O$$
    $$\longrightarrow 5H_2O_2+2MnO^-_4+6H^+ \longrightarrow 2Mn^{2+}$$
    In first reaction $$H_2O_2$$ act as an oxidizing agent as oxidation states change from $$-1$$ to $$-2$$.
    In $$2^{nd}$$ reaction $$H_2O_2$$ act as reducing agent as oxidation state of $$Mn$$ changes from $$+7$$ to $$+2$$ by $$H_2O_2$$ (itself gets oxidized).
  • Question 9
    1 / -0
    Hydrogen peroxide is now generally prepared to industrial scale by the:
    Solution
    Hydrogen peroxide is prepared from barium peroxide by the following methods.
    By the action of dilute sulphuric acid. A paste of hydrated barium peroxide ($$BaO_2.8H_2O$$) is prepared in ice – cold water and then added slowly to an ice-cold solution of 20% $$H_2SO_4.$$
  • Question 10
    1 / -0
    Water released from dams is measured in?
    Solution
    Water retained from dams is measured in cubic feet per second or CFS.
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