Hydrogen Test

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Hydrogen Test - 9

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Weekly Quiz Competition

Question 1
1 / -0

Hydrogen resembles halogens in many respects for which several factors are responsible. Of the following factors which one is most important in this respect?

A
Its tendency to lose an electron to form a cation

B
Its tendency to gain a single electron in its valence shell to attain stable electronic configuration

C
Its low negative electron gain enthalpy value

D
Its small size

Solution

Like halogens (with \(ns^ 2np ^5\) configuration belonging to the seventeenth group of the periodic table), it is short by one electron to the corresponding noble gas configuration, helium \((1s ^2 )\).
Question 2
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Why does \(H ^+\) ion always get associated with other atoms or molecules?

A
Ionisation enthalpy of hydrogen resembles that of alkali metals

B
Its reactivity is similar to halogens

C
It resembles both alkali metals and halogens

D
Loss of an electron from hydrogen atom results in a nucleus of very small size as compared to other atoms or ions. Due to small size it cannot exist free

Solution

Loss of the electron from hydrogen atom results in nucleus (\(H ^+\)) of 1.5 x \(10^{-3}\) = 1.5 pm size. This is extremely small as compared to normal atomic and ionic sizes of 50 to 200 pm. As a consequence, \(H ^+\) does not exist freely and is always associated with other atoms or molecules.
Question 3
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Metal hydrides are ionic, covalent or molecular in nature. Among LiH, NaH, KH, RbH, CsH, the correct order of increasing ionic character is

A
LiH > NaH > CsH > KH > RbH

B
LiH < NaH < KH < RbH < CsH

C
RbH > CsH > NaH > KH > LiH

D
NaH > CsH > RbH > LiH > KH

Solution

In ionic hydride as it is formed by s-Block element, down the group, electropositive character increases.
Question 4
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Which of the following hydrides is electron-precise hydride?

A
\(B_2H_6\)

B
\(NH_3\)

C
\(H_2O\)

D
\(CH_4\)

Solution

These hydrides have the required number of electrons to write their conventional Lewis structures.
Question 5
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Radioactive elements emit \(\alpha,\beta\,and\,\gamma\) rays and are characterised by their half-lives. The radioactive isotope of hydrogen is

A
Protium

B
Deuterium

C
Tritium

D
Hydronium

Solution

The tritium concentration is about one atom per \(10 ^{18}\) atoms of protium. Of these isotopes, only tritium is radioactive and emits low energy beta particles.
Question 6
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Which of the following statements are not true for hydrogen?

(i) It exists as diatomic molecule.

(ii) It has one electron in the outermost shell.

(iii) It can lose an electron to form a cation which can freely exist.

(iv) It forms a large number of ionic compounds by losing an electron.

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

\(H ^+\) does not exist freely and is always associated with other atoms or molecules. Unlike alkali metals, it has a very high ionization enthalpy and does not possess metallic characteristics under normal conditions.
Question 7
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Dihydrogen can be prepared on commercial scale by different methods. In its preparation by the action of steam on hydrocarbons, a mixture of CO and \(H_2\) gas is formed. It is known as.......

(i) Water gas

(ii) Syngas

(iii) Producer gas

(iv) Industrial gas

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

The mixture of CO and \(H_2\) is called water gas. As this mixture of CO and \(H_2\) is used for the synthesis of methanol and a number of hydrocarbons, it is also called synthesis gas or ‘syngas’.
Question 8
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Consider the reactions:

(A) \(H_2O_2+2HI\rightarrow I_2+2H_2O\)

(B) \(HOCl+H_2O_2\rightarrow H_3O^++Cl^-+O_2\)

Which of the following statements is correct about \(H_2O_2\) with reference to these eactions? Hydrogen perioxide is .

A
An oxidising agent in both (A) and (B)

B
An oxidising agent in (A) and reducing agent in (B)

C
A reducing agent in (A) and oxidising agent in (B)

D
A reducing agent in both (A) and (B)

Solution

In A, iodine is oxidized from -1 to zero whereas in B, chlorine get reduced from +1 to -1.
Question 9
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The oxide that gives \(H_2O_2\) on treatment with dilute \(H_2SO_4\) is-

A
\(PbO_2\)

B
\( BaO_2.8H_20 + O_2\)

C
\(MnO_2\)

D
\( TiO_2\)

Solution

Acidifying barium peroxide and removing excess water by evaporation under reduced pressure gives hydrogen peroxide.

Question 10

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Correlate the items listed in Column I with those listed in Column II. Find out as many correlations as you can.

Column I	Column II
(i) Synthesis gas	(a) \(Na_2[Na_4(PO_3)_6\)
(ii) Dihydrogen	(b) Oxidising agent
(iii) Heavy water	(c) Softening of water
(iv) Calgon	(d) Reducing agent
(v) Hydrogen peroxide	(e) Stoichiometric compounds of s-block elements
(vi) Salt like hydrides	(f) Prolonged electrolysis of water
	(g) Zn + NaOH
	(h) Zn + dil. \(H_2SO_4\)
	(i) Synthesis of methanol
	(j) Mixture of CO and \(H_2\)

(i) → (i), (j) (ii) → (d), (e), (g), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (f)

(i) → (i), (j) (ii) → (d), (e), (g), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (e)

(i) → (i), (j) (ii) → (d), (e), (g), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (f),(j)

(i) → (i), (j) (ii) → (d), (e), (a), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (e)

Question 11
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Which of the following statement(s) is/are correct in the case of heavy water?

(i) Heavy water is used as a moderator in nuclear reactor.

(ii) Heavy water is more effective as solvent than ordinary water.

(iii) Heavy water is more associated than ordinary water.

(iv) Heavy water has lower boiling point than ordinary water.

A
(i),(ii)

B
(i),(iii)

C
(ii),(iii)

D
(ii),(iv)

Solution

Heavy water is used as moderator in nuclear reactors and in exchange reaction and due to its higher mass it is more associated with water.
Question 12
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Which of the following equations depicts the oxidising nature of \(H_2O_2\)?

A
\(2MnO_4^-+6H^++ 5H_2O_2 \) \(\rightarrow 2Mn^{2+}+ 8H_2O+ 5O_2\)

B
\(2Fe^{3+}+ 2H^+ +H_2O_2\) \(\rightarrow 2Fe^{2+}+ 2H_2O + O_2\)

C
\(2I^-+ 2H^++ H_2O_2\rightarrow I_2+2H_2O\)

D
\(KIO_4 + H_2O_2\rightarrow KIO_3 + H_2O + O_2\)

Solution

Iodine gets oxidized from -1 to zero.
Question 13
1 / -0

Which of the following statements about hydrogen are correct?

(i) Hydrogen has three isotopes of which protium is the most common.

(ii) Hydrogen never acts as cation in ionic salts.

(iii) Hydrogen ion, \(H ^+ \), exists freely in solution.

(iv) Dihydrogen does not act as a reducing agent.

A
(i),(iv)

B
(iii),(iv)

C
(ii),(iii)

D
(i),(ii)

Solution

Loss of the electron from hydrogen atom results in nucleus (\(H ^+ \)) of \(\sim\) 1.5 x \(10^{-3}\) pm size. This is extremely small as compared to normal atomic and ionic sizes of 50 to 200 pm. As a consequence, \(H ^+ \) does not exist freely and is always associated with other atoms or molecules.
Question 14
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Which of the following equations depicts reducing nature of \(H_2O_2\)?

A
\(2[Fe(CN)_6]^{4-} + 2H^+ + H_2O_2\) \(\rightarrow 2[Fe (CN)_6]^{3-} + 2H_2O \)

B
\(I_2 + H_2O_2 + 2OH^-\) \(\rightarrow 2I^- + 2H_2O + O_2\)

C
\(Mn^{2+} + H_2O_2\rightarrow Mn^{4+} + 2OH^-\)

D
\(PbS + 4H_2O_2\rightarrow PbSO_4 + 4H_2O\)

Solution

Iodine gets reduced from zero to -1.
Question 15
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Hydrogen peroxide is.

A
An oxidising agent

B
A reducing agent

C
Both an oxidising and a reducing agent

D
Neither oxidising nor reducing agent

Solution

It acts as an oxidising as well as reducing agent in both acidic and alkaline media.
Question 16
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Some of the properties of water are described below. Which of them is/ are not correct?

(i) Water is known to be a universal solvent.

(ii) Hydrogen bonding is present to a large extent in liquid water.

(iii) There is no hydrogen bonding in the frozen state of water.

(iv) Frozen water is heavier than liquid water.

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

The unusual properties of water in the condensed phase (liquid and solid states) are due to the presence of extensive hydrogen bonding between water molecules. This leads to high freezing point, high boiling point, high heat of vaporisation and high heat of fusion in comparison to \(H_2S\) and \(H_2Se\).
Question 17
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Hardness of water may be temporary or permanent. Permanent hardness is due to the presence of

(i) Chlorides of Ca and Mg in water

(ii) Sulphates of Ca and Mg in water

(iii) Hydrogen carbonates of Ca and Mg in water

(iv) Carbonates of alkali metals in water

A
(i),(ii)

B
(ii),(iii)

C
(iii),(iv)

D
(i),(iv)

Solution

Presence of calcium and magnesium salts in the form of hydrogen carbonate, chloride and sulphate in water makes water ‘hard’.
Question 18
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Which of the following reactions increases production of dihydrogen from synthesis gas?

A
\(CH_4(g) + H_2O(g) \underset{Ni}{\overset{1270\,K}{\longrightarrow}} CO (g) + 3H_2 (g)\)

B
\(C (s) + H_2O (g) \overset{1270\,K}{\longrightarrow} CO (g) + H_2 (g)\)

C
\(CO (g) + H_2O (g) \underset{Catalyst}{\overset{673\,K}{\longrightarrow}} CO_2 (g) + H_2 (g)\)

D
\(C_2H_6 + 2H_2O \underset{Ni}{\overset{1270\,K}{\longrightarrow}}2CO + 5H_2\)

Solution

The production of dihydrogen can be increased by reacting carbon monoxide of syngas mixtures with steam in the presence of iron chromate as catalyst.

Question 19

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Match Column I with Column II for the given properties/applications mentioned therein.

Column I	Column II
(i) H	(a) Used in the name of perhydrol
(ii) \(H_2\)	(b) Can be reduced to dihydrogen by NaH
(iii) \(H_2O\)	(c) Can be used in hydroformylation of olefin
(iv) \(H_2O_2\)	(d) Can be used in cutting and welding

(i) → (d) (ii) → (b) (iii) → (c) (iv) → (a)

(i) → (d) (ii) → (c) (iii) → (a) (iv) → (b)

(i) → (d) (ii) → (c) (iii) → (b) (iv) → (a)

(i) → (c) (ii) → (d) (iii) → (b) (iv) → (a)

Question 20
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In the following questions a statement of Assertion (A) followed by a statement of Reason (R) is given. Choose the correct option out of the choices given below each question.

Assertion (A): Permanent hardness of water is removed by treatment with washing soda.

Reason (R): Washing soda reacts with soluble magnesium and calcium sulphate to form insoluble carbonates.

A
Statements A and R both are correct and R is the correct explanation of A

B
A is correct but R is not correct

C
A and R both are correct but R is not the correct explanation of A

D
A and R both are false

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Hydrogen Test - 9

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Hydrogen Test - 9

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Question 1

Its tendency to lose an electron to form a cation

Its tendency to gain a single electron in its valence shell to attain stable electronic configuration

Its low negative electron gain enthalpy value

Its small size

Solution

Question 2

Ionisation enthalpy of hydrogen resembles that of alkali metals

Its reactivity is similar to halogens

It resembles both alkali metals and halogens

Loss of an electron from hydrogen atom results in a nucleus of very small size as compared to other atoms or ions. Due to small size it cannot exist free

Solution

Question 3

LiH > NaH > CsH > KH > RbH

LiH < NaH < KH < RbH < CsH

RbH > CsH > NaH > KH > LiH

NaH > CsH > RbH > LiH > KH

Solution

Question 4

\(B_2H_6\)

\(NH_3\)

\(H_2O\)

\(CH_4\)

Solution

Question 5

Protium

Deuterium

Tritium

Hydronium

Solution

Question 6

(i),(ii)

(ii),(iii)

(iii),(iv)

(i),(iv)

Solution

Question 7

(i),(ii)

(ii),(iii)

(iii),(iv)

(i),(iv)

Solution

Question 8

An oxidising agent in both (A) and (B)

An oxidising agent in (A) and reducing agent in (B)

A reducing agent in (A) and oxidising agent in (B)

A reducing agent in both (A) and (B)

Solution

Question 9

\(PbO_2\)

\( BaO_2.8H_20 + O_2\)

\(MnO_2\)

\( TiO_2\)

Solution

Question 10

(i) → (i), (j) (ii) → (d), (e), (g), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (f)

(i) → (i), (j) (ii) → (d), (e), (g), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (e)

(i) → (i), (j) (ii) → (d), (e), (g), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (f),(j)

(i) → (i), (j) (ii) → (d), (e), (a), (h), (i) (iii) → (f) (iv) → (a), (c) (v) → (b), (d) (vi) → (e)

Question 11

(i),(ii)

(i),(iii)

(ii),(iii)

(ii),(iv)

Solution

Question 12

\(2MnO_4^-+6H^++ 5H_2O_2 \) \(\rightarrow 2Mn^{2+}+ 8H_2O+ 5O_2\)

\(2Fe^{3+}+ 2H^+ +H_2O_2\) \(\rightarrow 2Fe^{2+}+ 2H_2O + O_2\)

\(2I^-+ 2H^++ H_2O_2\rightarrow I_2+2H_2O\)

\(KIO_4 + H_2O_2\rightarrow KIO_3 + H_2O + O_2\)

Solution

Question 13