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Sets Test - 20

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Sets Test - 20
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Weekly Quiz Competition
  • Question 1
    1 / -0
    If n(AB)=8,n(A)=6,n(B)=4n(A \cup B)=8, n(A)=6, n(B)=4, then n(AB)n(A\cap B)=
    Solution
    n(AB)=8n(A)=6,n(B)=4n(A\cup B)=8\\ n(A)=6\quad ,\quad n(B)=4 

    we know that 
    n(AB)=n(A)+n(B)n(AB)n(A\cup B)=n(A)+n(B)-n(A\cap B)\\
    8=6+4n(AB) 8=6+4-n(A\cap B)\\
    n(AB)=108=2 n(A\cap B)=10-8=2
  • Question 2
    1 / -0
    The set (AB)(BC)\left( {A \cap B'} \right)' \cup \left( {B \cap C} \right) is equal to :
    Solution

  • Question 3
    1 / -0
    If A and B are any two sets, then AB A \cup B is  equal to: 
    Solution

    A & B are two sets

    AB = (A-B) + (A∩B) + (B-A)



  • Question 4
    1 / -0
    If A={2,4,6,8,10},B={1,3,5,7,9}A=\left\{2, 4, 6, 8, 10\right\}, B=\left\{1, 3, 5, 7, 9\right\}, then ABA-B =____________
    Solution
    A={2,4,6,8,10}B={1,3,5,7,9}AB={2,4,6,8,10}{1,3,5,7,9}={2,4,6,8,10}A=\{ 2,4,6,8,10\} \\ B=\{ 1,3,5,7,9\} \\ A-B=\{ 2,4,6,8,10\} -\{ 1,3,5,7,9\} =\{ 2,4,6,8,10\}
  • Question 5
    1 / -0
    Let A,BA, B are two sets such that n(A)=6,n(B)=8n(A)=6, n(B)=8 then the maximum number of elements in n(AB)n(A\cup B) is _________
    Solution
    n(A)=6,n(B)=8n(A)=6,n(B)=8
    n(AB)n(A\cup B) will be maximum when AA & BB are disjoint sets.
    AB=ϕn(AB)=0n(AB)=n(A)+n(B)n(AB)=6+80=14n(AB)=14A\cap B=\phi \\ n(A\cap B)=0\\ n(A\cup B)=n(A)+n(B)-n(A\cap B)\\ =6+8-0\\ =14\\ n(A\cup B)=14
  • Question 6
    1 / -0
    If A={1, 2, 4}, B={2, 4, 5}, C={2, 5}, then (A-C)×\times(B-C) is equal to
    Solution
    A={1,2,4}A=\{1, 2, 4\}, B={2,4,5}B=\{2, 4, 5\}, C={2,5}C=\{2, 5\}
    AC={1,4}A-C=\{1, 4\}
    BC={4}B-C=\{4\}
    (AC)×(BC)={1,4}×{4}(A-C)\times (B-C)=\{1, 4\}\times \{4\}
    ={1,4},{4,4}=\{1, 4\}, \{4, 4\}.

  • Question 7
    1 / -0
    If A and B are two sets such that n(A)=17,n(B)=23,n(AB)=38n(A)=17, n(B)=23, n(A \cup B)=38, find n(AB)n(A \cap B).
    Solution
    We know,
    n(AB)=n(A)+n(B)n(AB)n(A \cap B)=n(A)+n(B)-n(A \cup B)
    n(AB)=17+2338=2n(A \cap B)=17+23-38=2
  • Question 8
    1 / -0
    Which of the following is set ?
    Solution
    As the collection of months having names starting with J is well defined. So, it's a set. Rest are not well defined , hence are not set.
  • Question 9
    1 / -0
    If X and Y are two sets such that n(X)=45,n(XY)=76,n(XY)=12,n(X)=45, n(X \cup Y)=76, n(X \cap Y)=12, find n(Y)n(Y).
    Solution
    n(XY)=n(X)+n(Y)n(XY)n(X \cup Y)=n(X) +n(Y)-n(X \cap Y)
    76=45+n(Y)1276=45+n(Y)-12
    n(Y)=43n(Y)=43
  • Question 10
    1 / -0
    If A={xNx\in N : xis a multiple of 3} and
    B={xNx\in N : is a multiple of 6}, then A-B is equal to
    Solution
    A=xϵN:xA=x\epsilon \quad N:x is a multiple of 33.
    A=3,6,9,12,15,18,......A=3,6,9,12,15,18,......
    B=(xϵN:xB=(x\quad \epsilon N:x is a multiple of 6)6)
    B=6,12,18,24,......B=6,12,18,24,......
    AB=(3,9,15,21,.....)\therefore A-B=(3,9,15,21,.....)
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