Sets Test

Result

Sets Test - 20

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

If $$n(A \cup B)=8, n(A)=6, n(B)=4$$, then $$n(A\cap B)$$=

A
$$2$$

B
$$4$$

C
$$6$$

D
$$8$$

Solution

$$n(A\cup B)=8\\ n(A)=6\quad ,\quad n(B)=4$$

we know that
$$n(A\cup B)=n(A)+n(B)-n(A\cap B)\\$$
$$ 8=6+4-n(A\cap B)\\$$
$$ n(A\cap B)=10-8=2$$
Question 2
1 / -0

The set $$\left( {A \cap B'} \right)' \cup \left( {B \cap C} \right)$$ is equal to :

A
$$A' \cup B \cup C$$

B
$$A' \cup B$$

C
$$A' \cup C'$$

D
$$A' \cap B$$

Solution
Question 3
1 / -0

If A and B are any two sets, then $$ A \cup B$$ is equal to:

A
$$(A-B) \cup (B-A) \cup (A \cap B)$$

B
$$ (A^0 \cap B^0)^0$$

C
$$(A-B) \cup (B-A)$$

D
$$A \cup (B-A)$$

Solution

A & B are two sets
AᴜB = (A-B) + (A∩B) + (B-A)
Question 4
1 / -0

If $$A=\left\{2, 4, 6, 8, 10\right\}, B=\left\{1, 3, 5, 7, 9\right\}$$, then $$A-B$$ =____________

A
$$\left\{\right\}$$

B
$$\left\{2, 4, 6, 8, 10\right\}$$

C
$$\left\{1, 3, 5, 7, 9\right\}$$

D
$$None$$

Solution

$$A=\{ 2,4,6,8,10\} \\ B=\{ 1,3,5,7,9\} \\ A-B=\{ 2,4,6,8,10\} -\{ 1,3,5,7,9\} =\{ 2,4,6,8,10\} $$
Question 5
1 / -0

Let $$A, B$$ are two sets such that $$n(A)=6, n(B)=8$$ then the maximum number of elements in $$n(A\cup B)$$ is _________

A
$$7$$

B
$$9$$

C
$$14$$

D
$$None$$

Solution

$$n(A)=6,n(B)=8$$
$$n(A\cup B)$$ will be maximum when $$A$$ & $$B$$ are disjoint sets.
$$A\cap B=\phi \\ n(A\cap B)=0\\ n(A\cup B)=n(A)+n(B)-n(A\cap B)\\ =6+8-0\\ =14\\ n(A\cup B)=14$$
Question 6
1 / -0

If A={1, 2, 4}, B={2, 4, 5}, C={2, 5}, then (A-C)$$\times$$(B-C) is equal to

A
{(1, 4)}

B
{(1, 4), (4, 4)}

C
{(4, 1), (4, 4)}

D
none of these

Solution

$$A=\{1, 2, 4\}$$, $$B=\{2, 4, 5\}$$, $$C=\{2, 5\}$$
$$A-C=\{1, 4\}$$
$$B-C=\{4\}$$
$$(A-C)\times (B-C)=\{1, 4\}\times \{4\}$$
$$=\{1, 4\}, \{4, 4\}$$.
Question 7
1 / -0

If A and B are two sets such that $$n(A)=17, n(B)=23, n(A \cup B)=38$$, find $$n(A \cap B)$$.

A
1

B
2

C
3

D
4

Solution

We know,
$$n(A \cap B)=n(A)+n(B)-n(A \cup B)$$
$$n(A \cap B)=17+23-38=2$$
Question 8
1 / -0

Which of the following is set ?

A
The collection of months having names starting with J.

B
The collection of smart boys in your class.

C
The collection of most talented persons.

D
The collection of sand grains in a Earth.

Solution

As the collection of months having names starting with J is well defined. So, it's a set. Rest are not well defined , hence are not set.
Question 9
1 / -0

If X and Y are two sets such that $$n(X)=45, n(X \cup Y)=76, n(X \cap Y)=12,$$ find $$n(Y)$$.

A
$$41$$

B
$$43$$

C
$$49$$

D
$$47$$

Solution

$$n(X \cup Y)=n(X) +n(Y)-n(X \cap Y)$$
$$76=45+n(Y)-12$$
$$n(Y)=43$$
Question 10
1 / -0

If A={$$x\in N$$ : xis a multiple of 3} and
B={$$x\in N$$ : is a multiple of 6}, then A-B is equal to

A
{6, 12, 18,.......}

B
{3, 6, 9, 12,.........}

C
{3, 9, 15, 21,.........}

D
none of these

Solution

$$A=x\epsilon \quad N:x$$ is a multiple of $$3$$.
$$A=3,6,9,12,15,18,......$$
$$B=(x\quad \epsilon N:x$$ is a multiple of $$6)$$
$$B=6,12,18,24,......$$
$$\therefore A-B=(3,9,15,21,.....)$$

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Sets Test - 20

Result

Sets Test - 20

Score

-

Rank

-

SHARING IS CARING

Question 1

$$2$$

$$4$$

$$6$$

$$8$$

Solution

Question 2

$$A' \cup B \cup C$$

$$A' \cup B$$

$$A' \cup C'$$

$$A' \cap B$$

Solution

Question 3

$$(A-B) \cup (B-A) \cup (A \cap B)$$

$$ (A^0 \cap B^0)^0$$

$$(A-B) \cup (B-A)$$

$$A \cup (B-A)$$

Solution

Question 4

$$\left\{\right\}$$

$$\left\{2, 4, 6, 8, 10\right\}$$

$$\left\{1, 3, 5, 7, 9\right\}$$

$$None$$

Solution

Question 5

$$7$$

$$9$$

$$14$$

$$None$$

Solution

Question 6

{(1, 4)}

{(1, 4), (4, 4)}

{(4, 1), (4, 4)}

none of these

Solution

Question 7

1

2

3

4

Solution

Question 8

The collection of months having names starting with J.

The collection of smart boys in your class.

The collection of most talented persons.

The collection of sand grains in a Earth.

Solution

Question 9

$$41$$

$$43$$

$$49$$

$$47$$

Solution

Question 10

{6, 12, 18,.......}

{3, 6, 9, 12,.........}

{3, 9, 15, 21,.........}

none of these

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.