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Sets Test - 22

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Sets Test - 22
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Weekly Quiz Competition
  • Question 1
    1 / -0
    The equation x + cosx $$=$$ a has exactly one positive root. Complete set of values of 'a' is

    Solution
    Let f(x) = x + cosx a
    $$\Rightarrow f'(x)=1-sinx\geq 0\forall x \epsilon R.$$
    Thus f(x) is increasing in $$\left ( -\infty ,\infty  \right )$$, as zero of f'(x) don't for an interval. f(0) = 1 a

    For a positive root, $$1-a< 0$$

    $$\Rightarrow a> 1$$
  • Question 2
    1 / -0
    Find the equivalent set for $$A - B $$.
    Solution


    Hence By this graph we see that $$A-B = A - (A \cap B)$$

  • Question 3
    1 / -0
    In an examination $$80\%$$  passed in English, $$85\%$$ in Maths, $$75\%$$ in both and $$40$$ students failed in both subjects. Then the number of  students appeared are
    Solution
    $$n(E)=80$$
    $$n(M)=85$$
    $$n(E \cap M)=75$$
    $$n(E \cup M)=n(E)+n(M)-n(E \cap M)=80+85-75=90$$
    $$n(E \cup M)'=10$$
    Let n be the total number of students appeared
    $$\dfrac{10}{100} \times n=40$$
    $$\therefore n=400$$
  • Question 4
    1 / -0
    $$p\cap (q\cup r)=?$$
    Solution

  • Question 5
    1 / -0
    In a science talent examination, 50% of the candidates fail in Mathematics and 50% fail in Physics. If 20% fail in both these subjects, then the  percentage who pass in both Mathematics and Physics is:
    Solution
    By set theory

    $$n(M\cup P) = n(M) + n(P)-n(M\cap P)$$         where M and P are sets of students failing in respective subjects.

    $$=0.5 + 0.5 - 0.2 = 0.8$$

    This indicates $$80\%$$ of the class fails in at least one of the given subjects while $$20\%$$ pass in both.
  • Question 6
    1 / -0
    If $$A - B = \phi$$ and $$B - A = \phi$$ then A and B are

    Solution
    if $$A-B = \phi$$ and $$B-A = \phi$$
    hence this relation contains $$A-B$$  and $$B-A$$ doesn't contains any element,
    so, the elements in $$A$$ & $$B$$ are same.
  • Question 7
    1 / -0
    All the students of a batch opted Psychology, Business, or both. 73% of the students opted Psychology and 62% opted Business. If there are  220 students, how many of them opted for both Psychology and business?
    Solution
    By set theory

    $$n(P\cap B) = n(P) + n(B)-n(P\cup B)$$

    $$=0.73+0.62-1.00=0.35$$

    $$35\%$$ of $$220 = 77$$
  • Question 8
    1 / -0
    In a group of 15 women, 7 have nose studs, 8 have ear rings and 3 have neither. How many of these have both nose studs and ear rings?
    Solution
    Since 3 women have neither nose studs nor earrings 

    $$n(N\cup E) = 15-3 = 12$$

    By set theory

    $$n(N\cap E) = n(N) + n(E)-n(N\cup E)$$

    $$=7+8-12 = 3$$
  • Question 9
    1 / -0
    If $$A$$ and $$B$$ have some elements in common, then $$n(A \cup B)$$ is:
    Solution
    We know that $$n(A\cup B)+n(A\cap B) = n(A)+n(B)$$

    But $$n(A\cap B) >0$$ always
    $$\Rightarrow n(A)+n(B)=n(A\cup B)+n(A\cap B)>n(A\cup B)$$
    Hence, $$n(A\cup B)<n(A)+n(B)$$.
  • Question 10
    1 / -0
    If $$A - B = \emptyset $$, then relation between A and B is :
    Solution
    If A and B are disjoint it would mean A is a null set. Otherwise A and B must be equal to $$A\cap B$$ AT LEAST.

    Hence option C is correct.
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