Straight Lines ...

The straight lines x + y = 0 , 3x - y – 4 = 0 , x + 3y – 4 = 0 form a triangle which is

Slope of any line parallel to X axis is

Projection (the foot of perpendicular) from ( x , y ) on the x – axis is

Slope of a line is not defined if the line is

If the distance between the points $$(4, p)$$ and $$(1, 0)$$ is $$5$$, then the value of $$p$$ is:

The coordinates of the point which is equidistant from the three vertices of the $$\Delta$$ AOB as shown in the Fig. is

The area of a triangle with vertices $$(a, b + c), (b, c + a)$$ and $$(c, a + b)$$ is

The line $$3x-4y+8=0$$ is rotated through an angle $$\displaystyle \frac { \pi  }{ 4 } $$ in the clockwise direction about the point $$(0,2)$$. The equation of the line in its new position is 

Plot $$(3, 0), (5, 0)$$ and $$(0, 4) $$ on cartesian plane. Name the figure formed by joining these points and find its area.

Find the area of triangle having vertices $$A (6, 10), B (4, 5)$$ and $$C (3, 8)$$ .

The area of a triangle with vertices $$A (3, 0), B (7, 0)$$ and $$C (8, 4)$$ is

The points $$A (2, 9), B (a, 5)$$ and $$C (5, 5) $$ are the vertices of a triangle $$ABC$$ right angled at $$B$$. Find the values of  $$a$$ and hence the area of $$\Delta $$ $$ABC$$.

The area of triangle ABC (in sq. units) is :

If the point $$A (2, 4)$$ is equidistant from $$P (3, 8)$$ and $$Q (7, y)$$, find the values of $$y$$.