Straight Lines ...

If area of a triangle is $$35$$ square units with vertices $$\left( {2, - 6} \right),\,\,\left( {5,\,\,4} \right)$$ and $$({k},\,\,4)$$ then $${k}$$ is :

Points A & B are in the first quadrant:Point 'o' isthe origin. If the slope of OA is 1, slope of OB is 7 and OA=OB, then the slope of AB is-

The area of a triangle with vertices $$A(5,0),B(8,0)$$ and $$C(8,4)$$ in square units is 

Area of the triangle with vertices $$(-2,2), (1,5)$$ and $$(6,-1)$$ is 

The vertices of a $$\triangle ABC$$ are $$A(3,8),B(-4,2)$$ and $$C(5,-1)$$. The area of $$\triangle ABC$$ is

If $$A$$ and $$B$$ are two points having co-ordinates $$(3,4)$$ and $$(5,-2)$$ respectively and $$P$$ is a point such that $$PA=PB$$ and area of triangle $$PAB=10$$ square units, then the co-ordinates of $$P$$ are

the area of a triangle with vertices $$ (-3, 0),(3,0) $$ and $$ (0, k) $$ is $$ 9 $$ sq units. then the value of $$ k $$ will be 

Let $$PQR$$ be a right angled isosceles traingle, right angled at $$P(2,1).$$ If the equation of the line $$QR$$ is $$2x+y=3$$, then the equation represnting the pair of lines $$PQ$$ and $$PR$$ is

If one of the diagonals of a square is along the line $$x=2y$$ and one of its vertices is $$\left(3,0\right)$$, then its sides through this vertex are given by the equations

Two medians drawn from acute angles of a right angled triangle intersect at an angle $$\dfrac\pi6$$. If the length of the hypotenuse of the triangle is $$3$$ units, then area of the triangle (in sq. units) is