Straight Lines ...

The equation of the line which passes through the point ( 1 , - 2 ) and cuts off equal intercepts from the axis is

If a line is drawn through the origin and parallel to the line x – 2y + 5 = 0 , its equation is

The line passing through ( 1, 1 ) and parallel to the line 2x – 3y + 5 = 0 is

The equation of the line which passes through the point ( 2 , - 3 ) and cuts off equal intercepts from the axis is

The straight lines x + y - 4 = 0 , 3x + y – 4 = 0 , x - 3y – 4 = 0 form a triangle which is

The line which passes through the point ( 0 , 1 ) and perpendicular to the line x – 2y + 11 = 0 is

The acute angle between the lines x – y = 0 and y = 0 is

The middle point of the line segment joining $$ (3 , 1) $$ and $$ (1 , 1) $$ is shifted by two units ( in the sense increasing y) perpendicular to the line segment. Then the coordinates of the point in the new position is

A line passes through the point $$(3,4)$$ and cut off intercepts from the coordinates axes such that their sum is $$14$$. The equation of the line is 

The points $$A(-4,1)$$, $$B(-2,-2),C(4,0),D(2,3)$$ are the vertices of

The points $$A(2a,4a),B(2a,6a)$$ and $$C(2a+\sqrt{3}a,5a)$$ (when $$a> 0$$) are vertices of

Which of the following sets of points form an equilateral triangle 

A line is of length $$10$$ m and one end is $$(2,-3)$$, the $$x$$ - co-ordinate of the other is $$8$$, then its $$y$$- coordinate is:

The coordinates of a point on the line y=x where perpendicular from the line 3x+4y=12 is 4 units, are

The mid points of three sides of a triangle are (0, 1) (0, 2) and (0, 3). Area of this triangle. 

lf the line joining the points $$(\mathrm{a}\mathrm{t}_{1}^{2},2\mathrm{a}\mathrm{t}_{1}),(\mathrm{a}\mathrm{t}_{2}^{2},\ 2\mathrm{a}\mathrm{t}_{2})$$ is parallel to $$\mathrm{y}=\mathrm{x},$$ then $$\mathrm{t}_{1}+\mathrm{t}_{2}=$$ 

The acute angle between the lines
$$l x  + my =l+m, l(x-y) +m(x + y)=2m $$ is