Self Studies

Conic Sections ...

TIME LEFT -
  • Question 1
    1 / -0

    If the curves $$f(x) = e^{x}$$ and $$g(x) = kx^{2}$$ touches each other then the value of $$k$$ is equal to

  • Question 2
    1 / -0

    Find the equation of the circle which passes through the point $$(1, 1)$$ & which touches the $$x^2 + y^2 + 4x - 6y - 3 = 0$$ at the point $$(2, 3)$$ on it.

  • Question 3
    1 / -0

    Let circles $${C}_{1}$$ and $${C}_{2}$$ an Argand plane be given by $$\left| z+1 \right| =3$$ and $$\left| z-2 \right| =7\ \ $$ respectively. If a variable circle $$\left| z-{ z }_{ 0 } \right| =r\quad $$ be inside circle $${C}_{2}$$ such that it touches $${C}_{1}$$ externally and $${C}_{2}$$ internally then locus of $${z}_{0}$$ describes a conic $$E$$ whose eccentricity is equal to

  • Question 4
    1 / -0

    Find the locus of the point of intersection of the lines $$\sqrt{3}x-y-4\sqrt{3} \lambda=0$$ and $$\sqrt{3}\lambda x+\lambda y-4\sqrt{3}=0$$ for different values of $$\lambda$$.

  • Question 5
    1 / -0

    Find the equation of the circle which passes through the point (1, 1) & which touches the circle $$x^{2} + y^{2} + 4x - 6y - 3 = 0$$ at the point $$(2, 3)$$ on it.

  • Question 6
    1 / -0

    The equation of the hyperbola whose foci are $$(6, 5), (-4, 5)$$ and eccentricity $$5/4$$ is?

  • Question 7
    1 / -0

    If the curve y = | x- 3| touches the parabola $$y^2 = \lambda (x-4), \lambda >0$$, then latus rectum of the parabola, is

  • Question 8
    1 / -0

    The equation of the circle passing through $$(4,\ 5)$$ having the centre at $$(2 ,\ 2)$$ is

  • Question 9
    1 / -0

    state whether following statements are true or false
    Statement 1 : $$\sqrt {(x-1)^2 +y^2} + \sqrt{(x+1)^2 + y^2} = 4$$ represent equation of ellipse
    Statement 2 : The locus of point which moves such that sum of its distance from two fixed points is constant is an ellipse.

  • Question 10
    1 / -0

    Directions For Questions

    If $$7{l}^{2}-9{m}^{2}+8l+1=0$$ and we have to find the equation of circle having $$lx+my+1=0$$ is a tangent and we can adjust given condition as $$16{l}^{2}+8l+1=9\left({l}^{2}+{m}^{2}\right)$$
    or $${\left(4l+1\right)}^{2}=9\left({l}^{2}+{m}^{2}\right)\Rightarrow \dfrac{\left|4l+1\right|}{\sqrt{\left({l}^{2}+{m}^{2}\right)}}=3$$
    Center of circle$$=\left(4,0\right)$$ and radius$$=3$$ when any two non-parallel lines touching a circle, then centre of circle lies on angle bisector of lines.

    ...view full instructions

    If $$16{m}^{2}-8l-1=0,$$ then equation of the circle having $$lx+my+1=0$$ is a tangent is

Submit Test
Self Studies
User
Question Analysis
  • Answered - 0

  • Unanswered - 10

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
Submit Test
Self Studies Get latest Exam Updates
& Study Material Alerts!
No, Thanks
Self Studies
Click on Allow to receive notifications
Allow Notification
Self Studies
Self Studies Self Studies
To enable notifications follow this 2 steps:
  • First Click on Secure Icon Self Studies
  • Second click on the toggle icon
Allow Notification
Get latest Exam Updates & FREE Study Material Alerts!
Self Studies ×
Open Now