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Mathematical Reasoning Test - 9

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Mathematical Reasoning Test - 9
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  • Question 1
    1 / -0
    The negation of the boolean expression
    $$\sim s\vee \left( \sim r\wedge s \right) $$ is equivalent to:
    Solution
    $$\sim \left( \sim s\vee (\sim r\wedge s) \right) $$

    $$s\wedge (r\vee \sim s)$$
    $$(s\wedge r)\vee (s\wedge \sim s)$$

    $$(s\wedge r)\vee (F)$$

    $$(s\wedge r)$$
  • Question 2
    1 / -0
    Negation of the statement:
    $$\sqrt{5}$$ is an integer or $$5$$ is irrational is?
    Solution
    Let
    $$p=\sqrt5$$ is an integer $$\Rightarrow$$ $$\sim p=$$ $$\sqrt5$$ is not an integer
    $$q= 5 $$ is irrational $$\Rightarrow$$ $$\sim q=$$ $$5$$ is not an irrational

    1) $$\sqrt{5}$$ is not an integer and $$5$$ is not an irrational number
    $$\{\sim (p \vee q) = \sim p \wedge \sim q\}$$
  • Question 3
    1 / -0
    Consider the following three statements:
    P : 5 is a prime number.
    Q : 7 is a factor of 192.
    R : L.C.M. of 5 and 7 is 35.
    Then the truth value of which one of thefollowing statements is true ?
    Solution
    P is True
    Q is False
    R is True
    Option 4) $$T\vee(T\wedge T)=T$$
  • Question 4
    1 / -0
    The negation of the statement: "If I become a teacher, then I will open a school" is
    Solution
    Let $$p:$$ I become a teacher

    $$q:$$ I will open a school

    The given statement is $$p\rightarrow q=\left( \sim p \right) \vee q$$

    It negation is $$(~ \left( \text{~ p} \right) \vee q)=p\wedge \left( \text{~ q} \right) $$

    Thus negation of the given statement is 'I will become a teacher and I will not open school'.
  • Question 5
    1 / -0
    The contrapositive of the statement 'I go to school if it does not rain' is:
    Solution
    In the given statement, let $$p$$ denote the part "it does not rain"
    and $$q$$ denote the part "i go to school"
    So the given statement is $$p\longrightarrow q$$
    Now for a contrapositive statement, by definition we have
    $$\left( p\longrightarrow q \right) \leftrightarrow \left( \sim q\longrightarrow \sim p \right) $$
    So $$\sim q$$ means "i do not go to school"
    and $$\sim p$$ means "it rains"
    $$\sim q\longrightarrow \sim p$$ means "if i do not go to school, it rains"
  • Question 6
    1 / -0
    The negation of $$\sim s \vee (\sim r\wedge s)$$ is equivalent to
    Solution
    $$\sim (\sim s \vee (\sim r\wedge s)) \Rightarrow s \: \wedge \sim (\sim r \wedge s)$$

    $$\Rightarrow s \wedge (r \vee \sim s)$$

    $$\Rightarrow s \wedge r$$
  • Question 7
    1 / -0
    The contrapositive of the statement 'If I am not feeling well, then I will go to the doctor' is:
    Solution
    "If i am not feeling well, then I will go to doctor."

    Let $$p$$ be "I am not feeling well" and $$q$$ be "I will go to doctor".

    If $$p$$, then $$q$$.

    $$p\rightarrow q = \sim q\rightarrow \sim p$$

    If I will not go to doctor, then I am feeling well.                             .
  • Question 8
    1 / -0
    The contrapositive of the following statement, "If the side of a square doubles, then its area increases four times"' is:
    Solution
    Contrapositive of $$p\rightarrow q$$ is given by $$\sim q \rightarrow \sim p$$
    So, $$(3)$$ is the right option.
  • Question 9
    1 / -0
    Consider the following two statements:
    P: If $$7$$ is an odd number, then $$7$$ is divisible by $$2$$.
    Q: If $$7$$ is a prime number, then $$7$$ is an odd number.
    If $$V_{1}$$ is the truth value of the contrapositive of P and $$V_{2}$$ is the truth value of contrapositive of Q, then the ordered pair $$(V_{1}, V_{2})$$ equals:
    Solution
    The truth value of statement $$P$$ is $$F$$ as a True statement cannot 
    imply a false statement.

    The truth value of statement $$Q$$ is $$T$$ as True statement implying True statement is $$T$$

    The truth value of a conditional and its contra-positive are logically equivalent.  
    Hence $$V_1 $$ is $$F$$ and $$V_2$$ is $$T$$
  • Question 10
    1 / -0
    The Boolean expression  $$( ( p \wedge q ) \vee ( p \vee \sim q ) ) \wedge ( \sim p \wedge \sim q )$$  is equivalent to :
    Solution
    By Using Truth Tables for the mentioned Boolean expression we prove that the truth table for $$(\sim { p })\wedge (\sim { q })$$ mathces.
    Hence the correct answer is Option C
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