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Statistics Test - 19

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Statistics Test - 19
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  • Question 1
    1 / -0
    The variance of six observations is given as $$16$$ and mean is $$8$$. If each observation is multiplied by $$3$$.
    Find the new variance:
    Solution
    Mean, $$u=8$$.
    So, $$\dfrac{x_1+x_2...x_6}{6}=8$$.
    $$\therefore x_1+x_2...x_6=48$$.
    Multiplying the above equation by $$3$$ on both the sides we get,
    $$3x_1+3x_2...3x_6=48\times 3$$
    $$\therefore u'=\dfrac{3x_1+3x_2....3x_6}{6}=\dfrac{48 \times 3}{6}$$
    $$\therefore u'=24$$
    Thus, new mean, $$u'=24$$.
    $$\therefore$$ New variance, $$\sigma ^2=\dfrac{(3x_1)^2+...(3x_6)^2}{6}-(24)^2$$
    $$\therefore \sigma ^2=9\times \dfrac{(x_1)^2+....(x_6)^2}{6}-576$$
    $$\therefore \sigma ^2=9\times \dfrac{480}{16}-576$$
    $$\therefore \sigma ^2=720-576$$
    $$\therefore \sigma ^2=144$$
    Thus, New Variance is $$144$$.
    Ans-Option $$D$$
  • Question 2
    1 / -0
    Find the variance of the following data:
    $$5,9,8,12,6,10,6,8$$
    Solution
    Here $$n=8$$.
    Mean, $$u=\dfrac{\sum x_i}{n}=\dfrac{64}{8}=8$$
    Value of Deviations $$(x_i-u)$$ are
    $$-3,1,0,4,-2,2,-2,0$$
    Variance, $$\sigma ^2=\dfrac{\sum(x_i-u)^2}{n}=\dfrac{38}{8}=4.75$$.
    Ans- Option $$B$$. 
  • Question 3
    1 / -0
    $$x_i$$$$3$$$$5$$$$7$$$$9$$$$11$$$$13$$
    $$f_i$$$$6$$$$8$$$$15$$$$25$$$$8$$$$4$$
    Find the Mean Deviation (M.D) about the mean
    Solution
    Total Frequency, $$N=\sum f_i=66$$.
    Mean, $$u=\dfrac{(\sum{f_i \times x_i})}{N}=\dfrac{528}{66}=8$$
    Now deviations $$f_i \times |x_i-u|$$ are,
    $$30,24,15,25,24,20$$.
    $$\therefore MD(u)= \dfrac{(\sum{f_i \times  |x_i-u|})}{N}=\dfrac{138}{66}=2.09$$
    Thus, $$MD(u)=2.09$$
    Ans- Option $$C$$.
  • Question 4
    1 / -0

    Directions For Questions

    Factory$$A$$$$B$$
    Number of Workers$$4000$$$$5000$$
    Mean Wages$$3500$$$$3500$$
    Variance in wages$$64$$$$81$$

    ...view full instructions

    Find the Coefficient of Variation of Factory $$A$$.
    Solution
    Coefficient of Variation, $$C.V=\dfrac{S.D}{Mean} \times 100 \%$$
    So, $$C.V_A=\dfrac{S.D_A}{Mean_A} \times 100 \%$$

    $$\therefore C.V_A=\dfrac{\sqrt {64}}{3500} \times 100 \%$$.
    $$\therefore C.V_A=0.22857 \%$$.
    Ans-Option $$A$$.
  • Question 5
    1 / -0
    Find the Standard Deviation of the following data:
    $$5,9,8,12,6,10,6,8$$
    Solution
    Here $$n=8$$.
    Mean, $$u=\dfrac{\sum x_i}{n}=\dfrac{64}{8}=8$$
    Value of Deviations $$(x_i-u)$$ are
    $$-3,1,0,4,-2,2,-2,0$$
    Variance, $$\sigma ^2=\dfrac{\sum(x_i-u)^2}{n}\\=\dfrac{(-3-8)^2-(1-8)^2-(0-8)^2-(4-8)^2-(-2-8)^2-(2-8)^2-(-2-8)^2-(0-8)^2}{8}\\=\dfrac{38}{8}=4.75$$.
    Standard Deviation, $$S.D=\sqrt{\sigma ^2}$$
    $$\therefore S.D=\sqrt{4.75}=2.17$$
    Ans- Option $$D$$. 
  • Question 6
    1 / -0
    Variance remains unchanged by change of
    Solution
    Variance will be changed if scale changes or both scale and origin changes 
    $$*$$ Variance won't be effected by change of origin.
  • Question 7
    1 / -0
    Standard deviation is calculated from the Harmonic Mean (HM).
    Solution
    Standard deviation is calculated from mean $$i.e$$ arithmetic mean.
    It never be calculated from harmonic mean.
  • Question 8
    1 / -0

    Directions For Questions

    Factory$$A$$$$B$$
    Number of Workers$$4000$$$$5000$$
    Mean Wages$$3500$$$$3500$$
    Variance in wages$$64$$$$81$$

    ...view full instructions

    Find the Coefficient of Variation for Factory $$B$$:
    Solution
    Coefficient of Variation, $$C.V=\dfrac{\text{S.D}}{\text{Mean}} \times 100 \%$$
    So, $$C.V_B=\dfrac{{S.D_B}}{{Mean_B}} \times 100 \%$$
    Therefore, $$C.V_B=\dfrac{\sqrt {81}}{3500} \times 100 \%$$
    $$\Rightarrow  C.V_A=0.25714 \%$$.
  • Question 9
    1 / -0
    The formula for the coefficient of range is $$\dfrac{\text{Range}}{a+b}$$. Here, $$a$$ and $$b$$ denote:
    Solution
    Range is the difference between the maximum value and the minimum value of the data set.

    Let $$a$$ be the maximum value of the data set and
    $$b$$ be the minimum value of the data set

    Therefore, $$range = a-b$$

    Coefficient of range is the relative measure of the dispersion.

    It is given by $$\text{coefficient of range}=\dfrac{a-b}{a+b}=\dfrac{range}{a+b}$$
  • Question 10
    1 / -0
    The variance of $$10, 10, 10, 10, 10$$, is
    Solution
    Since we know that if all the data items of a distribution are same. Then, the variance of items is 0.
    Here, all the data items are same and equal to 10.
    Hence, variance is 0.
    Option C is correct.
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