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Binomial Theorem Test - 48

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Binomial Theorem Test - 48
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  • Question 1
    1 / -0
    The sum of coefficients of the two middle terms in the expansion of $$( 1 + x ) ^ { 2 n - 1 }$$ is equal to
    Solution
    $$(1+x)^{2n-1}$$ has $$2n$$ terms.
    Hence there are $$2$$ middle terms, the $$n^{th}$$ term and the $$(n+1)^{th}$$ term.
    $$t_n=(2n-1)C_{n-1}\cdot x^{n-1}$$
    $$t_{n+1}=(2n-1)C_{n+1-1}x^{n+1-1}=2nC_nx^n$$
    Sum of coefficients$$=(2n-1)C_{n-1}+(2n-1)C_n=2nC_n$$.

  • Question 2
    1 / -0
     If the coefficients of $$x^{-7}$$ and $$x^{-8}$$ to the expansion of $$\left(2+\dfrac {1}{3x}\right)^{n}$$ are equal then $$n=$$
    Solution

  • Question 3
    1 / -0
    The coefficient of $$x^{4}$$ in the expansion of $$\left(\dfrac{x}{2}-\dfrac{3}{x^{2}}\right)^{10}$$, is
    Solution

  • Question 4
    1 / -0
    The coefficient of $$x^{5}$$ in the expansion of $$(1+x)^{21}+(1+x)^{22}+....+(1+x)^{30}$$ is
  • Question 5
    1 / -0
    Find the middle term in the expansion of $${ \left( \dfrac { { 2x }^{ 2 } }{ 3 } +\dfrac { 3 }{ { 2x }^{ 2 } }  \right)  }^{ 10 }$$ 
    Solution

  • Question 6
    1 / -0
    The coefficient of $${x}^{3}$$ in the expression of $${(1+{x}^{2}+{x}^{3})}^{10}$$ is 
    Solution

  • Question 7
    1 / -0
    If $$(1+ax)^n=1+8x+24x^2+.....$$ then 
    Solution

  • Question 8
    1 / -0
    The coefficient of $$x^4$$ in the expansion of $$(1-2x+3x^2+4x^3)(1-x)^{-8}$$ is:
  • Question 9
    1 / -0
    The coefficient of $$x^6 y^5 z^3$$ in the expansion of $$(3xy - 2xz + zy)^7$$ is
    Solution

  • Question 10
    1 / -0
    The coefficient of $$x^{4}$$ in the expansion $$\left(1+5x+9x^{2}+.+\left(4k+1\right)x^{k}+..\right)\left(1+x^{2}\right)^{11}$$ is 
    Solution

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