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Thermodynamics Test - 21

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Thermodynamics Test - 21
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  • Question 1
    1 / -0
    When a gas undergoes an adiabatic compression its:
    Solution
    In an adiabatic process , no heat enters or leaves the system i.e. $$dQ=0$$.
         The first law of thermodynamics says , 
                       $$dQ=dU+dW=0$$
    or                $$dU=-dW$$ 
      when a gas compresses adiabatically , work is done on the system ,therefore $$dW$$ must be negative i.e. change in internal energy is positive it means internal energy of the system would increase and hence the temperature of the gas will increase.
  • Question 2
    1 / -0
    A gas undergoes a reversible adiabatic expansion. Identify the correct option about gas.
    Solution
    From First Law of Thermodynamics,
    $$Q=W+\Delta U$$
    For an adiabatic process,
    $$Q=0$$
    $$\implies W+\Delta U=0$$
    $$\implies \Delta U=-W$$
    For adiabatic expansion, the work done would be positive.
    Hence change in internal energy of system is negative.
    Thus internal energy deceases, and so does the temperature.
  • Question 3
    1 / -0
    Which of the following statement is true as per the second law of thermodynamics for an isolated, ordered system?
    Solution
    The second law of thermodynamic states that the entropy of an isolated system increases over time and remain constant for reversible process. 
  • Question 4
    1 / -0
    Which of the following is true about refrigeration?
    Solution
    A refrigerator is infact a reverse heat engine which absorbs heat from source (material) at lower temperature, do work on it and then passes the heat to the sink (sorrounding) at higher temperature, thus we can say that heat is removed from inside the refrigerator.
  • Question 5
    1 / -0
    Which of the following is a restatement of first law of thermodynamics:
    Solution
    First law of thermodynamics states that the quantity of heat given to a system $$dQ$$  is equal to the sum of the increase in its internal energy $$dU$$ and the external work done by the system $$dW$$ in expansion 
     $$dQ=dU+dW$$
    it means total energy is conserved there is no loss of energy
  • Question 6
    1 / -0
    Identify which of the following is correct about the cooling process as shown above ?
    I. Negative work
    II. An isothermal process
    III. Increasing energy

    Solution
    Here the arrow of work input towards the cooling device so its means work on the system. We know that work on the system will be negative. In this process, temperature is increasing so its not a isothermal and it is increasing energy. Thus, statement I will be right.    
  • Question 7
    1 / -0
    A heat engine receives $$150$$ Joules of heat energy and performs $$70$$ Joules of work. If heat loss in the surrounding is zero. Find out by what value does the internal energy of the system change?
    Solution
    By the first law of thermodynamics, $$dQ=dU+W$$
    so, change in internal energy $$dU=dQ-W=150-70=80 J$$
  • Question 8
    1 / -0
    Which of the following option hold true for the above heat engine? 

    Solution
    As the heat is absorbed by heat engine from source (hot reservoir)  then it give some heat into work and rest is given to the sink(cold reservoir)  so  ($$Q_{1}>Q_{2}$$). Therefore net work done $$W=Q_{1}-Q_{2}$$ will be positive. 
  • Question 9
    1 / -0
    Identify the incorrect statement ?
    Solution
    Energy and matter are interconvertible and the relation between them is given by $$E=mc^2$$ as followed from Einstein's theory of Relativity.
    The conversion of energy, kinetic or electromagnetic, to particles with rest mass is experimentally observed only when the energy comes in big enough clumps to create a massive particle, when the energy is low, this is going to be the lightest charged particle, the electron. Electrons can only be created along with a positively charged particle, to conserve charge, and this is almost always a positron.
    The conversion of mass to energy is nowadays popular in nuclear fission reactors.
  • Question 10
    1 / -0
    During what kind of process is there no change in internal energy?
    Solution
    Isothermal process :    $$T = constant$$   i.e   $$\Delta T = 0$$ K
    Change in internal energy        $$\Delta U = nC_v (\Delta T)  = 0$$ J
    Thus internal energy remains constant in an isothermal process.
    As internal energy is a state function, thus change in internal energy is also zero in one cycle of a cyclic process.
    Hence option E is correct.
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