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Thermodynamics Test - 3

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Thermodynamics Test - 3
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  • Question 1
    1 / -0

    For solids near room temperature the molar specific heat (R is the universal gas constant)

    Solution

    The molar specific heats of solids also demonstrate a marked temperature dependence. Solids have molar specific heats that generally decrease in a nonlinear manner with decreasing temperature and approach zero as the temperature approaches absolute zero. At high temperatures (usually above 300 K), the molar specific heats approach the value of 3R ≈ 25 J/mol.K, a result known as the DuLong–Petit law.

  • Question 2
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    In Thermodynamics Extensive variables depend

    Solution

    The variables which depend on the size or amount of the substance are called extensive variables.

    Example: Mass, volume etc

  • Question 3
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    In a quasi-static process,

    Solution

    A quasi-static process is a thermodynamic process that happens slowly enough for the system to remain in internal equilibrium.

  • Question 4
    1 / -0

    In which type of process is the volume constant

    Solution

    An isochoric process is a thermodynamic process during which the volume of the closed system undergoing such a process remains constant.

  • Question 5
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    The heat engine takes

    Solution

    a heat engine converts heat energy to mechanical work by using the temperature difference between a hot "source" and a cold "sink". Heat is transferred from the source, through the "working body" of the engine, to the "sink", and in this process some of the heat changes into work by using the qualities of the gas or liquid inside the engine.

  • Question 6
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    A refrigerator's working substance

    Solution

    According to the second law of thermodynamics heat cannot spontaneously flow from a colder location to a hotter area; work is required to achieve this.

  • Question 7
    1 / -0

    The coefficient of performance K of a refrigerator is given by

    Solution

    The performance of refrigerator is expressed by means of cofficient of performance

    cofficient of performance  = Heat extracted / work done = Q2 / W

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