Thermodynamics ...

A gas has pressure P and volume V. It is now compressed adiabatically to $$\dfrac{1}{32}$$ times the original volume. Given that $$(32)^{1.4}= 128$$, the final pressure is ($$\gamma = 1.4$$)

A polyatomic gas $$\displaystyle{\left(\gamma = \frac{4}{3}\right)}$$ is compressed to $$\displaystyle{\frac{1}{8}^{th}}$$ of its volume adiabatically. If its initial pressure $$P_o$$, its new pressure will be

A sample of gas expands from volume $$V_1$$ to $$V_2$$. The amount of work done by the gas is greatest when the expansion is

In pressure-volume diagram, the isochoric, isothermal, isobaric and iso-entropic parts respectively, are

For an isothermal expansion of a perfect gas, the value of $$\displaystyle{\dfrac{\Delta P}{P}}$$ is equal to

If a gas is heated at constant temperautre its isothermal compressibility

Temperature of the at the end of the first step, i.e. just at the start of adiabatic expansion will be -

The cycle on a $$P V$$ diagram is represented as

In an adiabatic process, the pressure is increased by $$\displaystyle{\dfrac{2}{3}}$$%. If $$\displaystyle{\gamma = \dfrac{3}{2}}$$, then the volume decreases by nearly

Two moles of helium gas are taken over the cycle ABCDA, as show in the P - T diagram. Assuming the gas to be ideal the work done on the gas in taking it from state A to B is :