Thermodynamics Test

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Thermodynamics Test - 70

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Weekly Quiz Competition

Question 1
1 / -0

A thermodynamic process in which temperature T of the system remains constant though other variable P and V may change , is called

A
Isochoric process

B
Isothermal process

C
Isobaric process

D
None of these

Solution

In isothermal process, temperature remains constant.
so ideal gas equation becomes $$PV$$=constant
Question 2
1 / -0

A gas is compressed at a constant pressure of 50 N / $$m^{2}$$ from a volume of 10$$m^{3}$$ to a volume of 4$$m^{3}$$. Energy of 100 J then added to the gas by heating. Its internal energy is

A
Increased by 400 J

B
Increased by 200 J

C
Increased by 100 J

D
Decreased by 200 J

Solution

Given: $$P=50 N/m^2, V_1=10m^3, V_2=4m^3, \Delta W=100J$$
From FLOT $$\Delta Q =\Delta U+\Delta W=\Delta U+P\Delta V\Rightarrow 100=\Delta U+50\times (4-10)\Rightarrow \Delta U=400 J$$
Question 3
1 / -0

Which relation is correct for isochoric process

A
$$\Delta Q=\Delta U$$

B
$$\Delta W=\Delta U$$

C
$$\Delta Q=\Delta W$$

D
None of these

Solution

For isochoric process $$\Delta V=0\Rightarrow \Delta W=0$$ From FLOT $$\Delta Q=\Delta U+\Delta W\Rightarrow \Delta Q=\Delta U$$
Question 4
1 / -0

A cycle tyre bursts suddenly. This represents an

A
Isothermal process

B
Isobaric process

C
Isochoric process

D
Adiabatic process

Solution

The process is very fast, so the gas fails to gain or lose heat.Hence this process in adiabatic.
Question 5
1 / -0

An adiabatic process occurs at constant

A
Temperature

B
Pressure

C
Heat

D
Temperature and pressure

Solution

In adiabatic process, no heat transfers between system and surrounding
Question 6
1 / -0

A given system undergoes a change is which the work done by the system equal the decrease in its internal energy. The system must have undergone an

A
Isothermal change

B
Adiabatic chnage

C
Isobaric change

D
Isochoric change

Solution

In adiabatic change Q = constant $$ \Rightarrow \Delta Q= o $$
So$$ \Delta W = -\Delta U \left ( \therefore \Delta Q=\Delta U+\Delta W \right )$$
Question 7
1 / -0

The process in which no heat enters or leaves the system is termed as

A
Isochoric

B
Isobaric

C
Isothermal

D
Adiabatic

Solution

In adiabatic process, no transfer of heat takes place between system and surrounding.
Question 8
1 / -0

In an adiabatic process, the state of a gas is changed from $$P_{1}, V_{1}, T_{1}$$ to $$P_{2}, V_{2}, T_{2}$$. Which of the following relation is correct

A
$$T_{1} V_{1}^{\gamma -1} = T_{2} V_{2}^{\gamma -1}$$

B
$$P_{1} V_{1}^{\gamma -1} = P_{2} V_{2}^{\gamma -1}$$

C
$$T_{1} P_{1}^{\gamma } = T_{2} P_{2}^{\gamma }$$

D
$$T_{1} V_{1}^{\gamma} = T_{} V_{2}^{\gamma}$$

Solution

$$P_1V_1^{\gamma}=P_2V_2^{\gamma}$$
$$\dfrac{RT_1}{V_1}V_1^{\gamma}=\dfrac{RT_2}{V_2}V_2^{\gamma}$$
$$T_1V_1^{\gamma-1}=T_2V_2^{\gamma-1}$$
Question 9
1 / -0

When a gas expands adiabatically

A
No energy is required for expansion

B
Energy is required and it comes the wall of the container of the gas

C
Internal energy of the gas is used in doing work

D
Law of conservation of energy does not gold

Solution

$$ \Delta Q = \Delta U + \Delta W = 0 \Rightarrow \Delta W= - \Delta U $$
if $$ \Delta W $$ is positive i.e., gas does work then $$ \Delta U$$ should benegative meaning internal energy is used in doing work.
Question 10
1 / -0

$$\bigtriangleup U + \bigtriangleup Q = 0$$ is valid for

A
Adiabatic process

B
Isothermal process

C
Isobaric process

D
Isochoric process

Solution

In adiabatic process ΔQ=0⇒ΔU+ΔW=0

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Thermodynamics Test - 70

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Thermodynamics Test - 70

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Question 1

Isochoric process

Isothermal process

Isobaric process

None of these

Solution

Question 2

Increased by 400 J

Increased by 200 J

Increased by 100 J

Decreased by 200 J

Solution

Question 3

$$\Delta Q=\Delta U$$

$$\Delta W=\Delta U$$

$$\Delta Q=\Delta W$$

None of these

Solution

Question 4

Isothermal process

Isobaric process

Isochoric process

Adiabatic process

Solution

Question 5

Temperature

Pressure

Heat

Temperature and pressure

Solution

Question 6

Isothermal change

Adiabatic chnage

Isobaric change

Isochoric change

Solution

Question 7

Isochoric

Isobaric

Isothermal

Adiabatic

Solution

Question 8

$$T_{1} V_{1}^{\gamma -1} = T_{2} V_{2}^{\gamma -1}$$

$$P_{1} V_{1}^{\gamma -1} = P_{2} V_{2}^{\gamma -1}$$

$$T_{1} P_{1}^{\gamma } = T_{2} P_{2}^{\gamma }$$

$$T_{1} V_{1}^{\gamma} = T_{} V_{2}^{\gamma}$$

Solution

Question 9

No energy is required for expansion

Energy is required and it comes the wall of the container of the gas

Internal energy of the gas is used in doing work

Law of conservation of energy does not gold

Solution

Question 10

Adiabatic process

Isothermal process

Isobaric process

Isochoric process

Solution

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