Kinetic Theory Test

Result

Kinetic Theory Test - 20

Score
-
out of -
Rank
-
out of -

TIME Taken - -

SHARING IS CARING

If our Website helped you a little, then kindly spread our voice using Social Networks. Spread our word to your readers, friends, teachers, students & all those close ones who deserve to know what you know now.

Weekly Quiz Competition

Question 1
1 / -0

At what temperature the kinetic energy of a gas molecular is one-half of its value of $${30}^\circ C$$ ?

A
$$151.5 K$$

B
$$251.5 K$$

C
$$303 K$$

D
$$121 K$$

Solution
Question 2
1 / -0

The internal energy of a diatomic gas us given as $$U=U_0V$$, where $$U_0$$ is a constant . Molar heat capacity of gas is

A
$$\dfrac{5}{2}R$$

B
$$\dfrac{7}{2}R$$

C
$$\dfrac{9}{2}R$$

D
$$\dfrac{3}{2}R$$

Solution

It is given that $$U={{U}_{0}}V$$

For a diatomic molecule, internal energy is given by

$$ U=\dfrac{5}{2}nRT $$

$$ {{U}_{0}}V=\dfrac{5}{2}nRT $$

Taking derivative on both sides.

$$ {{U}_{0}}\dfrac{dV}{dT}=\dfrac{5}{2}R n $$

$$ {{C}_{v}}=\dfrac{5}{2}R\,\,\,\,\,(\because \dfrac{{{U}_{0}}dU}{ndT}={{C}_{v}}) $$

Hence, molar heat capacity is $$[\dfrac{5}{2}R]$$.
Question 3
1 / -0

The number of molecules in 22.4 $$cm^{3}$$ of nitrogen gas at STP is __________.

A
$$6.023\times10^{20}$$

B
$$6.023\times10^{23}$$

C
$$22.4\times10^{20}$$

D
$$22.4\times10^{23}$$

Solution

There are 6.022*10^23 molecules present in 22400cm^3 gas.
Therefore the no. of molecules present in 22.4cm^3=

6.022*10^23 * 22.4cm^3 divide by:
224000 cm^3

Hence we get the ans as 6.022*10^20 molecules.
Question 4
1 / -0

Every gas (real gas ) behaves as an ideal gas

A
At high temperature and low pressure

B
At low temperature and high pressure

C
At normal temperature

D
None of the above

Solution

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure, as the potential energy due to intermolecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them.
Question 5
1 / -0

A gas behaves more closely as an ideal gas at :

A
low pressure and low temperature

B
low pressure and high temperature

C
high pressure and low temperature

D
high pressure and high temperature

Solution

(B):
Condition for gas to behave like ideal gas :

(1) pressure should be lower so gases can move independently.
(2) The temperature should be high so that the kinetic energy of gases can overcome the interaction among molecules.
It satisfies the equation of state.
Question 6
1 / -0

Which of the following gives evidence to kinetic theory of gases?

A
assumption of kinetic theory

B
Boyle's law

C
idea of mean free path

D
diffusion and evaporation

Solution

Boyle's law states that at constant temperature the volume of a given mass of dry gas is inversely proportional to its pressure as is evident from the kinetic theory of gases.
Question 7
1 / -0

Significant motion for the molecules of a monoatomic gas corresponds to :

A
translatory

B
vibratory

C
rotatory

D
none of these

Solution

Monoatomic gas has only 3 degree of freedom (all translational)
Question 8
1 / -0

When 273c.c of a gas is heated through 10C. AT constant pressure.then its new volume will be .

A
272 c.c

B
273c.c

C
274c.c

D
275c.c
Question 9
1 / -0

A gas will approach ideal behaviour at

A
low temperature and low pressure

B
low temperature and high pressure

C
high temperature and low pressure

D
high temperature and high pressure

Solution

At high temperature and low temperature the gas volume becomes large such that both intermolecular forces and molecular volume can be neglected.Under this condition kinetic energy can be applied properly.Option C is correct.
Question 10
1 / -0

The mean kinetic energy per mole of an ideal gas at $$0^oC$$ is a approximately :

A
$$3.4\ J$$

B
$$3.4\times 10^2\ J$$

C
$$3.4\times 10^3\ J$$

D
$$207\ J$$

Solution

User

Question Analysis

Correct -
Wrong -
Skipped -

My Perfomance

Score
-
out of -
Rank
-
out of -

Re-Attempt Weekly Quiz Competition

Kinetic Theory Test - 20

Result

Kinetic Theory Test - 20

Score

-

Rank

-

SHARING IS CARING

Question 1

$$151.5 K$$

$$251.5 K$$

$$303 K$$

$$121 K$$

Solution

Question 2

$$\dfrac{5}{2}R$$

$$\dfrac{7}{2}R$$

$$\dfrac{9}{2}R$$

$$\dfrac{3}{2}R$$

Solution

Question 3

$$6.023\times10^{20}$$

$$6.023\times10^{23}$$

$$22.4\times10^{20}$$

$$22.4\times10^{23}$$

Solution

Question 4

At high temperature and low pressure

At low temperature and high pressure

At normal temperature

None of the above

Solution

Question 5

low pressure and low temperature

low pressure and high temperature

high pressure and low temperature

high pressure and high temperature

Solution

Question 6

assumption of kinetic theory

Boyle's law

idea of mean free path

diffusion and evaporation

Solution

Question 7

translatory

vibratory

rotatory

none of these

Solution

Question 8

272 c.c

273c.c

274c.c

275c.c

Question 9

low temperature and low pressure

low temperature and high pressure

high temperature and low pressure

high temperature and high pressure

Solution

Question 10

$$3.4\ J$$

$$3.4\times 10^2\ J$$

$$3.4\times 10^3\ J$$

$$207\ J$$

Solution

User

Question Analysis

My Perfomance

Score

-

Rank

-

Results Announcement on: coming Monday

Stay Tuned: We’ll update you on your result via email or SMS.