Kinetic Theory Test

Result

Kinetic Theory Test - 66

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Weekly Quiz Competition

Question 1
1 / -0

An ideal diatomic gas is heated at constant volume, the supplied being Q. The increase in rotational kinetic energy is

A
Q

B
Q/2

C
3Q/5

D
2Q/5
Question 2
1 / -0

Velocity of gas molecules is $$500\ m/s$$ at $$300 K$$, at what temperature velocity will be equal to $$1500 m/s$$?

A
$$600\ K$$

B
$$900\ K$$

C
$$1800\ K$$

D
$$2700\ K$$

Solution
Question 3
1 / -0

What is the approximate root mean speed of line smoke particle of mass $$10^{-17}$$ kg at $$27^0C$$ ? $$[k=1.38\times 10^{-23}JK^{-1}$$]

A
$$2.0\times 10^{-2}ms^{-1}$$

B
$$2.7\times 10^{-2}ms^{-1}$$

C
$$3.5\times 10^{-2}ms^{-1}$$

D
$$4.4\times 10^{-2}ms^{-1}$$

Solution
Question 4
1 / -0

Average kinetic energy of a gas molecule is

A
Inversely proportional to the square of its absolute temperature

B
Directly proportional to the square root of its absolute temperature

C
Directly proportional to its absolute temperature

D
Directly proportional to square of absolute temperature

Solution
Question 5
1 / -0

An ideal gas is heated at constant volume until its pressure doubles.Which one of the following statements is correct?

A
The mean speed of the molecules doubles.

B
Root mean square speed of the molecules doubles.

C
Mean square speed of the molecules doubles.

D
Mean square speed of the molecules remains uncharged.
Question 6
1 / -0

The number of molecules in a gas pressure $$1.64\times 10^{-3}$$ atmospheres and temperature $$200K$$ having the volume $$1cc$$ are-

A
$$6.02\times 10^{16}$$

B
$$2.63\times 10^{16}$$

C
$$3.01\times 10^{19}$$

D
$$12.04\times 10^{19}$$

Solution
Question 7
1 / -0

A diatomic gas at $$ 17^0 C $$ is compressed to 1/32 of its original volume. Its final temperature is

A
1100 K

B
1500 K

C
1260 K

D
1160 K

Solution
Question 8
1 / -0

When 2 gms of a gas are introduced into an evacuated flask kept at $$25^0$$C the pressure is found to be one atmosphere. If 3 gms of another gas added to the same flask the pressure becomes 1.5 atmospheres. The ratio of the molecular weights of these gases will be

A
1 : 3

B
3 : 1

C
2 : 3

D
3 : 2

Solution

When $$2$$ grams of a gas $$A$$ is introduced in an evacuated flask kept at $$25 C$$; the pressure was found to be $$1atm$$ i.e.
The partial pressure of gas $$A=1atm$$.
And let moles be $$n_a=\dfrac{2}{M_{A}}$$
if $$3g$$ of another gas $$B$$ is then added to the same flask;
Partial pressure of gas $$B=1.5atm-1atm=0.5atm$$
moles of gas $$B=\dfrac{3}{M_{B}}$$
Again the temp and volume are constant therefore,
$$\dfrac{P_{1}}{n_{1}}=\dfrac{P_{2}}{n_{2}}$$
Hence, $$\dfrac{\dfrac{1}{2}}{M_{A}}$$ =$$\dfrac{\dfrac{0.5}{3}}{M_{B}}$$
$$M_{A}=\dfrac{0.5M_{B}}{3}\times2$$
$$\dfrac{M_{A}}{1}=\dfrac{M_{B}}{3}$$
or
$$\dfrac{M_{A}}{M_{B}}=\dfrac{1}{3}$$
Question 9
1 / -0

If the volume of the gas containing $$n$$ number of molecules is $$V$$, then pressure will decrease due to force of intermolecular attraction in the proportion :

A
$$ \dfrac {n}{V} $$

B
$$ \dfrac {n}{V^2} $$

C
$$ ( \dfrac {n}{V} )^2 $$

D
$$ ( \dfrac {1}{V^2} ) $$

Solution
Question 10
1 / -0

In a process $$PT=Constant$$, if molar heat capacity of a gas is $$C=37.35J/mol=K$$, then find the number of degrees of freedom of molecules in the gas.

A
$$n=10$$

B
$$n=5$$

C
$$n=6$$

D
$$n=7$$

Solution