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Kinetic Theory Test - 78

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Kinetic Theory Test - 78
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  • Question 1
    1 / -0
    A closed cylindrical vessel contains $$N$$ moles of an ideal diatomic gas at a temperature $$T$$. On supplying heat, the temperature remains same, but $$n$$ moles get dissociated into atoms. The heat supplied is:
    Solution
    Solution:- (C) $$\cfrac{1}{2} nRT$$
    Since the gas is enclosed in a vessel, during heating, volume of the gas remains constant. 
    $$\therefore W = 0$$
    $$\therefore q = \Delta{U} ..... \left( 1 \right)$$

    Now,
    As we know that,
    $$\Delta{U} = n {C}_{v} \Delta{T}$$

    Initial internal energy of the gas is
    $${U}_{1} = N \left( \cfrac{5}{2} R \right) T = \cfrac{5}{2} NRT$$

    Since $$n$$ moles dissociate into atoms, therefore after heating, the vessel contains $$\left( N - n \right)$$ moles of diatomic gas and $$2n$$ moles of mono atomic gas. Hence the internal energy of the gas after heating will be equal to

    $${U}_{2} = \left( N - n \right) \left( \cfrac{5}{2} R \right) T + 2n \left( \cfrac{3}{2} R \right) T$$

    $$\Rightarrow { U}_{2} = \cfrac{1}{2} nRT + \cfrac{5}{2} NRT$$

    $$\therefore \Delta{U} = {U}_{2} - {U}_{1}$$

    $$\Rightarrow \Delta{U} = \left( \cfrac{1}{2} nRT + \cfrac{5}{2} NRT \right) - \cfrac{5}{2} NRT$$ 

    $$\Rightarrow \Delta{U} = \cfrac{1}{2} nRT$$

    Now from $${eq}^{n} \left( 1 \right)$$, we get

    $$q = \cfrac{1}{2} nRT$$
  • Question 2
    1 / -0
    The number of molecules in 1 cc of water is closed to 
    Solution

  • Question 3
    1 / -0
    The pressure of an ideal gas veries according to the law $$P=P_{0}-AV^{2}$$ where $$P_{0}$$ and A are positive constants. What is the highest temperature that can be attained by the gas?
    Solution

  • Question 4
    1 / -0
    The heat capicity of liquid water at constant pressure, $$C_p$$ is $$18 $$ cals $$ deg^{-1} mol^{-1}$$. The value of heat capacity of water at constant volume, Cv is approximately:
    Solution

  • Question 5
    1 / -0
    $$C_{\upsilon }$$ values for monoatomic and diatomic gases respectively are: 
  • Question 6
    1 / -0
    A diatomic gas is undergoing a process for which P versus V relation is given as $${ PV }^{ -\frac { 5 }{ 3 }  }$$ = constant. The molar heat capacity of the gas for this process is:
    Solution

  • Question 7
    1 / -0
    The molar heat capacity of eater at constant pressure, C, is $$75JK^{-1}mol^{-1}$$. When 1.0KJ of heat is supplied to 100g of water which is free to expand, the increase in temperature of water is :
    Solution

  • Question 8
    1 / -0
    The heat capacity of liquid water is 75.6 J/mol k, while the enthaply of fusion of ice is 6.0 kJ/mol. What is the smallest number of ice cubes at $$0^{0}C$$ , each containing 9.0 g of water neede to cool 500 g of liquid water from $$20^{0}C$$ to $$0^{0}C$$?
    Solution

  • Question 9
    1 / -0
    Two closed containers of equal volume filled with air at pressure $$P_{0}$$ and temperature $$T_{0}$$. Both are connected by  narrow tube. If one of the container is maintained at temperature $$T_{0}$$ and another at temperature T, then new pressure in the containers will be 
    Solution

  • Question 10
    1 / -0
    A gas has molar heat capacity $$C = 4.5\ R$$ in the process $$PT = constant$$. Find the number of degrees of freedom (n) of molecules in the gas.
    Solution

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