Oscillations Te...

A particle of mass 1kg is moving in a S.H.M with an amplitude of 0.02m and a frequency of 60Hz. The maximum force acting on the particle is :

The circular motion of a particle with constant speed is:

The amplitude of oscillation of a particle is 0.05 m.If its period is 1.57s. Then the velocity at the mean position is

A body is executing SHM. If the force acting on the body is 6N when the displacement is 2 cm, then the force acting on the body when the displacement is 3 cm in newton is:

Water waves in a shallow dish are $$6.0\ m$$ long. At one point, the water moves up and down at a rate of $$4.8$$ oscillations/s. Speed of the wave is:

A particle executes simple harmonic oscillation
with an amplitude a. The period of oscillation is
T. The minimum time taken by the particle to
travel half of the amplitude from the
equilibrium position is:

The velocity of a particle that executes S.H.M. is  at its mean position 0.866 m/s.Velocity at a displacement half of its amplitude from mean position is

If the displacement $$x$$ and velocity $$v$$ of a particle executing S.H.M are related through the expression $$ 4v^{2}=25-x^{2} $$, then its maximum displacement in meters is

The displacement equations of two simple harmonic oscillators are given by $$ x_{1} =A_{1}\cos\omega t$$; $$ x_{2}= A_{2} \sin\left(\omega t+\frac{\pi }{6} \right )$$. The  phase difference between them is:

Assertion (A): The phase difference between displacement and velocity in SHM is $$ 90^{\circ} $$
Reason (R): The displacement is represented by y=A sin$$ \omega $$t and Velocity by V=A$$ \omega $$cos$$ \omega $$t.