Oscillations Te...

Two particles of same period $$(T)$$ and amplitude undergo $$SHM$$ along the same line with initial phase of $$\pi/6$$. If they start at the same instant and at same point along opposite directions, find the time after which they will meet again for the first time:

The total energy of a particle executing SHM is directly proportional to the square of the following quantity.

A particle executes SHM according to equation $$x = 10 \cos[2\pi t+\pi / 2]$$, where $$t$$ is in second. The magnitude of the velocity of the particle at $$t=1/6s$$ will be:

A particle executes $$SHM$$ and its position with time as $$x = A \sin\omega t$$. Its average speed during its motion from mean position to mid-point of mean and extreme position is

A student says that he had applied a force $$F= -k\sqrt {x}$$ on a particle and the particle moves in simple harmonic motion. He refuses to tell whether $$k$$ is a constant or not. Assume that he has worked only with positive $$x$$ and no other force acted on the particle.

A particle undergoes $$SHM$$ of period $$T$$. The time taken to complete $$3/8th$$ oscillation starting from the mean position is 

The mass of particle executing S.H.M is 1 gm.If its periodic time is $$\pi $$ seconds, the value of force constant is:-

A particle is executing SHM about y=0 along y-axis. Its position at an instant is given by y=(7m) sin $$\left( \pi f \right) .$$ its average velocity for a time interval 0 to 0.5 s is

A small body of mass $$0.10 kg$$ is executing S.H.M of amplitude $$1.0m$$ and period $$0.20sec$$. The maximum force acting on it is:

The time period of SHM of a particle is $$12 s.$$ The phase difference between the position at $$t =3s,$$ and $$t = 4s$$ will be :