Oscillations Te...

A particle is executing S.H.M.with amplitude $$5$$ cm along x axis, origin as mean position. If at $$x= +4$$ cm magnitude of velocity is equal to magnitude of acceleration then find time period of oscillation in seconds.

A simple harmonic oscillator of angular frequency $$2$$ rad/s is acted upon by an external force $$F = \sin t$$ N. If the oscillator is at rest in its equilibrium position at $$t= 0$$, its position at later times is proportional to:

If amplitude of particle executing $$SHM$$ is doubled, which of the following quantities are doubled
i) Time period
ii) Maximum velocity
iii) Maximum acceleration
iv) Total energy

A simple harmonic motion has an amplitude A and time period T. Find the time required by it to travel diameter from .

A simple motion is represented by:
$$y = 5(\sin 3 \pi t + \sqrt{3} \cos 3\pi t)cm$$
The amplitude and time period of the motion are:

A body oscillates with SHM according to the equation $$x=(5.0\quad m)\cos { [(2\pi \quad rad\quad { s }^{ -1 } } )t+{ \pi  }/{ 4] }$$
At t=1.5 s, its acceleration is:

Which of the following quantity is unitless

A particle executes simple harmonic motion with an amplitude of 5 cm. when the particle is at 4 cm from the mean position, the magnitude of its velocity in SI units is equal to that of its acceleration. then, its periodic time in second is:

After charging a capacitor $$C$$ to a potential $$V$$ , it is connected across an ideal inductor $$L$$.The capacitor starts discharging simple harmonically at time $$t = 0 .$$The charge on the capacitor at a later time instant is $$q$$ and the periodic time of simple harmonic oscillations is $$T$$. Therefore, 

Two particles undergoing simple harmonic motion of same frequency and same amplitude cross each other at $$x=\dfrac {A}{2}$$. Phase difference between them is