Oscillations Te...

The amplitude $$(A)$$ of damped oscillator becomes half in $$5$$ minutes. The amplitude after next $$10$$ minutes will be:

If velocity of a particle in SHM at x=4 m and x=5 m are 15 m/s and 13 m/s then its time period will be:

The time period of mass suspended from a spring is T. If the spring is cut into four equal parts and the same mass is suspended from one of the parts, then the new time period will be:

Select proper wave equation which describes simple harmonic progressive wave travelling along positive $$X$$ axis.

At time t = 0, one particle is at maximum positive amplitude and the other particle is at $$\cfrac{1}{\sqrt{2}}$$ of the positive amplitude. Their amplitudes and time periods T are same. If they are approaching, find the time by which they cross each other :-

A body attached to the lower end of a vertical spring oscillates with time period of 1 sec. The time period when two such springs are connected one below another is approximately:

In the arrangement , spring constant K has value $$2N\quad { m }^{ -1 }$$ ,mass M=3kg and mass m= 1kg. Mass M is in contact with a smooth surface . The coefficient of friction between two blocks is 0.1. The time period of SHM executed by the system is :
(assume both move together)

A simple harmonic wave is represented by the relation $$y\left ( x,t \right )=a_{0}sin2\pi \left ( vt-\dfrac{x}{\lambda } \right )$$ if the maximum particle velocity is three times the wave velocity, te wavelength $$\lambda $$ of the wave is-

Two bodies A and B of equal mass are suspended from separate massless springs of spring constant $$k_1$$ and $$k_2$$ respectively. If the bodies oscillate vertically such that their maximum velocities are equal, the ratio of the amplitude of A to that of B is

An object undergoing SHM taken 0.5 s to travel from one point of zero velocity to the next such point. The distance between those point is 50 cm. The period, frequency and amplitude of the motion is: