Oscillations Te...

A particle is executing SHM with time period T Starting from mean position, time taken by it to complete $$\dfrac { 5 }{ 8 } $$ oscillations is:

The equation of motion of a particle executing SHM is $$\left( \dfrac { d ^ { 2 } x } { d t ^ { 2 } } \right) + k x = 0$$ The time period of the particle will be 

A particle performs $$SHM$$ on x-axis with amplitude $$A$$ and time period $$T$$. The time taken by the particle to a distance $$A/5$$ starting from rest is:

The figure shows the displacement time graph of a particle executing S.H.M.
If the time period of oscillation is $$2 s$$ the equation of motion of its SHM 

A coin is placed on a horizontal platform, which undergoes horizontal simple harmonic motion about a mean position $$O$$.The coin does not slip on the platform. The force of friction acting on the coin is $$F$$.

a simple harmonic has an amplitude A and time period T. Find the time required by it to travel directly from $$x=0$$ to $$\, x=\frac { A}{ \sqrt { 2} } $$

When the displacement is half of the amplitude, then what fraction of total energy of a simple harmonic oscillator is kinetic:-

The displacement $$x$$ (in metres) of a particle performing simple harmonic motion is related to time $$t$$ (in seconds as} $$x = 0.05 \cos \left( 4 \pi t + \frac { \pi } { 4 } \right)$$. The frequency of the motion will be

Restoring force on the bob of a simple pendulum of mass 100 gm when its amplitude is $${1^\circ}$$ :

A simple harmonic motion is represented by $$y = 5 ( \sin 3 \pi t + \sqrt { 3 } \cos 3 \pi t ) \mathrm { cm }$$  The amplitude and time period of the motion are :