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Waves Test - 13

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Waves Test - 13
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  • Question 1
    1 / -0
    The maximum displacement of the particles of a medium in which a wave is travelling is called _________ .
    Solution
    A wave has basically three components which is used to define all of its properties,
    \rightarrow Amplitude
    \rightarrow Wavelength/ frequency
    \rightarrow Phase
    Amplitude of the wave is defined as the maximum displacement of the particle from its mean or initial position. For instance,
    In a single or solitude wave we can see maximum displacement of the particle two times (+k,k)(+k,-k), where k represents the maximum displacement or Amplitude.
    \therefore Option (A) is the correct answer.

  • Question 2
    1 / -0
    Two particles having the same phase must be at
    Solution
    Two particles having the same phase must be at two consecutive crests or two consecutive troughs.
  • Question 3
    1 / -0
    Light : Ray : : Sound : ?
    Solution
    The Light has particle nature 
    These particles (i.e photons) propagate 
    in from of Rays. Whereas in case 
    of sound, it propagates in the 
    from of pressure waves
    Option B-B is correct.

  • Question 4
    1 / -0
    The relation between frequency (n)(n) and wavelength (λ)(\lambda) of a sound wave is given by 
    (vv is velocity, nn is frequency and TT is time-period)
    Solution
    Time period (T)(T) of a wave is defined as the time taken to produce one complete wave, and frequency (n)(n) of a wave is defined as the number of complete waves produced in unit time.

    Thus they are related as,

    n=1Tn=\dfrac{1}{T}     or       T=1nT=\dfrac{1}{n}

    In one time period (T), a wave advances by a distance equal to one
    wavelength. Thus if vv is the velocity of the given wave, it is given by,

    v=λTv=\dfrac{\lambda}{T}

    As n=1Tn=\dfrac{1}{T}, we may write,

    v=nλv=n\lambda
  • Question 5
    1 / -0
    Two particles having the same phase must be at
    Solution
    For same phase angle, the two consecutive crest of wave 1 and wave 2 should be occurring at the same time period i.e. when they are in the same phase.Also same phase implies same frequency as well as same wavelength which will happen only if AB=ADA_B = A_D and AA=AC A_A = A_C  

  • Question 6
    1 / -0
    If the maximum acceleration of the body executing S.H.M. is a0_0 and maximum velocity is V0_0 the amplitude is given by
    Solution
    Max. acceleration in S.H.M, a0=ω2aa_0 = \omega^2 a       .....(i)          [a = amplitude]
    max. velocity = ω\omegaa
    v0=ωav_0 = \omega a
    v02=ω2a2\Rightarrow v_0^2 = \omega^2 a^2            ........ (ii)
    (ii)(i)a=v02a0\therefore \displaystyle \frac{(ii)}{(i)} \Rightarrow a = \frac{v_0^2}{a_0}
  • Question 7
    1 / -0
    What type of wave travels the faster?
    Solution
    A wave is the disturbance that transfers energy through matter or space. There are two types of wave i.e. Mechanical and Electromagnetic.
    Mechanical are those which propagate through a physical matter such as sound wave, ocean wave or earthquake wave while electromagnetic wave do not require a medium and they can even travel through vacuum such as light wave. As electromagnetic wave does not need a medium, it travels faster than mechanical wave. 
  • Question 8
    1 / -0
    Frequency (v)(v) and time period (T)(T) of a sound wave are related as :
    Solution
    We have the relation,

    v=1Tv=\frac{1}{T}

    where,

    vv is the frequency

    TT is the time period

    Then, the product of the frequency anf time period of the sound wave is unity.

    v×T=1T×T=1v \times T = \frac{1}{T} \times T = 1

  • Question 9
    1 / -0
    Fill in the blank. 
    When a sound wave, travelling in a medium bounces back to the same medium after striking the same second medium then _______ occurs.
    Solution
    When a sound wave, travelling in a medium bounces back to the same medium after striking the same second medium then  reflection of sound waves is said to take place. The reflection of sound wave is similar to the bouncing back of a rubber ball after striking a wall or the surface of a floor.
  • Question 10
    1 / -0
    Sound from the neighbouring room can be heard because
    Solution
    Due to multiple reflections of sound from walls, the sounds from adjoining room can be heard.
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