Evolution Test

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Evolution Test - 60

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Question 1
1 / -0

Which among the following initiated study in population genetics and related fields?

A
Hardy-Weinberg law

B
Lamarckism

C
Mechanistic theory of Darwin

D
Natural theory

Solution

The Hardy-Weinberg law initiated the study in population genetics and related fields. It states that an equilibrium of allele frequencies in a gene pool remains in effect in each succeeding generation of a sexually reproducing population if five conditions are met. They are random mating and the absence of mutation, gene flow, genetic drift and selection.
So, the correct option is 'Hardy-Weinberg law'.
Question 2
1 / -0

Non-directional force altering Hardy-Weinberg equilibrium is _____________.

A
Genetic drift

B
Gene flow

C
Gene recombination

D
Mutation

Solution

Answer is option A i.e. "Genetic drift"
Genetic drift is a mechanism of evolution in which allele frequencies of a population change over generations due to chance. Genetic drift is non-directional and non-adaptive, i. e. the genes of a small population changes irrespective of selective advantages or disadvantages.
Question 3
1 / -0

What is correct formulation of Hardy-Weinberg law?

A
$p^2 + 2pq + q^2 = 1$

B
$p^2 + pq + q^2 = 1$

C
$p^2 + 2pq + q^2 = 0$

D
$p^2 + pq + q^2 = 0$

Solution

The Hardy-Weinberg equation is given by,
p2 + 2pq + q2 = 1
Here, p and q represent the individual allele frequencies.
Therefore, p2= frequency of homozygous condition represented by p.
q2= frequency of homozygous alleles represented by q.
2pq = frequency of heterozygous condition.
So, the correct answer is 'p2 + 2pq + q2 = 1'
Question 4
1 / -0

Study of living cultures is

A
Ethnology

B
Ethnography

C
Sociobiology

D
Exobiology.
Question 5
1 / -0

Frequency of A allele is $0.6$ and that of a allele is $0.4$ . What would be frequency of heterozygotes in random mating population?

A
$0.36$

B
$0.16$

C
$0.24$

D
$0.48$

Solution

In a stable population, for a gene with two alleles, 'A' (dominant) and 'a' (recessive), if the frequency of 'A' is p and the frequency of 'a' is q, then the frequencies of the three possible genotypes (AA, Aa and aa) can be expressed by the Hardy-Weinberg equation:

p^2+2pq+q^2=1

where p^2 = Frequency of AA (homozygous dominant) individuals

q^2 = Frequency of aa (homozygous recessive) individuals

2pq = Frequency of Aa (heterozygous) individuals.

So, p= 0.6 and q = 0.4 (given)

.'. 2pq (frequency of heterozygote) =2 x 0.6 x 0.4=0.48

So, the correct answer is '0.48'.
Question 6
1 / -0

Maintenance of genetic equilibrium is known as :

A
Gause principle

B
Bergmen law

C
Glogger principle

D
Hardy-Weinerg principle

Solution

Hardy-Weinberg principle states that the allelic frequency in a random mating population will remain constant in the absence of mutation, migration and selection. So, there is genetic equilibrium
So, the correct answer is 'Hardy-Weinberg principle'
Question 7
1 / -0

In random mating population in equilibrium, which of the following brings about a change in gene frequency in a nondirectional manner?

A
Mutations

B
Random drift

C
Selection

D
Migration

Solution

Random drift is a non-directional factor. In actual practice, gene frequencies due to random drift may approach limits, i.e.; 1 and 0.
This would simply be possible only when a new population arises due to a very small sample leading to the fixation of one allele at the cost of another.
In this manner, the changes in gene frequency can be brought about without the existence of any directional force, i.e; mutation, selection and migration and this change has been called random genetic drift.
Thus, Random drift brings about a change in gene frequency in a non-directional manner in a random mating population at equilibrium. Thus, Option b is correct.
Question 8
1 / -0

Change in frequency of alleles in a population results in evolution as proposed by :

A
De Vries theory

B
Hardy-Weinberg principle

C
Darwin's theory

D
Lamarck's theory
Solution
According to Hardy-Weinberg principle, disturbance in genetic equilibrium or change of frequency of alleles in a population can be interpreted as accumulation or change in variations that results in evolution.
Five factors are known to affect Hardy-Weinberg equilibrium,
1. Gene migration or gene flow
2. Genetic drift.
3. Mutation.
4. Genetic recombination.
5. Natural selection.
So, the correct answer is 'Hardy-Weinberg principle'
Question 9
1 / -0

In which condition gene ratio remains constant in a species?

A
Gene flow

B
Mutation

C
Random mating

D
Sexual selection

Solution

According to Hardy-Weinberg's principle, the gene and genotypic frequencies in a population in a large random mating population will remain constant from generation to generation in the absence of migration, mutation, and selection.
So, the correct answer is 'Random mating'.
Question 10
1 / -0

The earliest man-like primate was

A
Ramapithecus

B
Australopithecus

C
Homo habitue

D
Homo erectus

Solution

Ramapithecus appeared 10 to 15 millions years ago.After Ramapithecus , Australopithecus and Homo habillis, Homo erectus, appeared followed by the Modern man appeared.
That's why Ramapithecus was the earliest man like primate.
So, the correct option is 'A'.

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Evolution Test - 60

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Evolution Test - 60

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SHARING IS CARING

Question 1

Hardy-Weinberg law

Lamarckism

Mechanistic theory of Darwin

Natural theory

Solution

Question 2

Genetic drift

Gene flow

Gene recombination

Mutation

Solution

Question 3

p2+2pq+q2=1 p^2 + 2pq + q^2 = 1 p2+2pq+q2=1

p2+pq+q2=1 p^2 + pq + q^2 = 1 p2+pq+q2=1

p2+2pq+q2=0 p^2 + 2pq + q^2 = 0 p2+2pq+q2=0

p2+pq+q2=0 p^2 + pq + q^2 = 0 p2+pq+q2=0

Solution

Question 4

Ethnology

Ethnography

Sociobiology

Exobiology.

Question 5

0.360.360.36

0.160.160.16

0.240.240.24

0.480.480.48

Solution

Question 6

Gause principle

Bergmen law

Glogger principle

Hardy-Weinerg principle

Solution

Question 7

Mutations

Random drift

Selection

Migration

Solution

Question 8

De Vries theory

Hardy-Weinberg principle

Darwin's theory

Lamarck's theory

Solution

Question 9

Gene flow

Mutation

Random mating

Sexual selection

Solution

Question 10

Ramapithecus

Australopithecus

Homo habitue

Homo erectus

Solution

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$p^2 + 2pq + q^2 = 1$

$p^2 + pq + q^2 = 1$

$p^2 + 2pq + q^2 = 0$

$p^2 + pq + q^2 = 0$

$0.36$

$0.16$

$0.24$

$0.48$