Solid State Test

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Solid State Test - 15

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Weekly Quiz Competition

Question 1
1 / -0

In which of the following structures coordination number for cations and anions in the packed structure will be same?

A
\(Cl^–\) ion form fcc lattice and \(Na^+\) ions occupy all octahedral voids of the unit cell.

B
\(Ca^{2+}\) ions form fcc lattice and \(F^-\) ions occupy all the eight tetrahedral voids of the unit cell.

C
\(O^- _{2}\) ions form fcc lattice and \(Na^+\) ions occupy all the eight tetrahedral voids of the unit cell.

D
\(S^{2-}\) ions form fcc lattice and \(Zn^{2+}\) ions go into alternate tetrahedral voids of the unit cell.

Solution

NaCl crystals have rock salt structure having fcc lattice in which \(Cl^–\) ions are present at fcc lattice points and face centre and Na+ occupies all the octahedral voids of given unit cell.
Where, coordination number of \(Na^+\) = 6
Coordination number of \(Cl^-\) = 6
Question 2
1 / -0

What is the coordination number in a square close packed structure in two dimensions?

A
2

B
3

C
4

D
6

Solution

In square closed structure in two dimensions each sphere is in contact with four of its neighbours. Thus the two dimensional coordination number is 4 .
Question 3
1 / -0

Which kind of defects are introduced by doping?

A
Dislocation defect

B
Schottky defect

C
Frenkel defects

D
Electronic defects

Solution

Doping can be done with an impurity which is electron rich or electron defficient as compared to the intrinsic semicoonductor like silicon or germanium . Such impurities inntroduce electronic deffects in them.
Question 4
1 / -0

Silicon doped with electron-rich impurity forms ........

A
p-type semiconductor

B
n-type semiconductor

C
Intrinsic semiconductor

D
Insulator

Solution

When silicon is doped with electron rich impurity like P or As , the increase in conductivity is due to the negatively charged electron . Hence, silicon doped with electron rich impurity is termed as n -type semiconductor.
Question 5
1 / -0

Which of the following statements is not true?

A
Paramagnetic substances are weakly attracted by magnetic field.

B
Ferromagnetic substances cannot be magnetised permanently.

C
The domains in antiferromagnetic substances are oppositely oriented with respect to each other.

D
Pairing of electrons cancels their magnetic moment in the diamagnetic substances.

Solution

Ferromagnetic species are strongly attracted in the magnetic field and can be permanently magnetised.
Question 6
1 / -0

Which of the following statements are correct?

(i) Ferrimagnetic substances lose ferrimagnetism on heating and become paramagnetic.

(ii) Ferrimagnetic substances do not lose ferrimagnetism on heating and remain ferrimagnetic.

(iii) Antiferromagnetic substances have domain structures similar to ferromagnetic substances and their magnetic moments are not cancelled by each other.

(iv) In ferromagnetic substances all the domains get oriented in the direction of magnetic field and remain as such even after removing magnetic field.

A
(i) and (iv)

B
(i) and (ii)

C
(i) and (iii)

D
(ii) and (iii)

Solution

Ferrimagnetic substances are materials that have domains of atoms of opposing magnetic moments which are unequal in number, therefore causing spontaneous magnetization, that is, they show behaviour just like ferromagnets below the Curie Temperature and show no magnetic order above the Curie Temperature, as in, they become paramagnetic.
Question 7
1 / -0

Which of the following features are not shown by quartz glass?

(i) This is a crystalline solid.

(ii) Refractive index is same in all the directions.

(iii) This has definite heat of fusion.

(iv) This is also called super cooled liquid.

A
(i) and (iii)

B
(i) and (ii)

C
(iii) and (ii)

D
(iii) and (iv)

Solution

Quartz glass is an amorphous solid. It therefore, doesn't have a definite heat of fusion.
Question 8
1 / -0

Which of the following cannot be regarded as molecular solid?

(i) SiC (Silicon carbide)

(ii) AlN

(iii) Diamond

(iv) \( I_2\)

A
(i), (ii) and (iii)

B
(i), (ii) and (iv)

C
(i), (iii) and (iv)

D
(iii), (ii) and (iv)

Solution

SiC (Silicon carbide ) , AlN, and diamond are not regarded as molecular solids. They are grouped separately as covalent or network solids.

Crystalline solids are classified on the basis of intermolecular forces working in them with four categories – molecular, ionic, metallic and covalent solids. The constituent particles of molecular solids are molecules, further subdivided on the basis of the bond types.

According to the properties of these solids, only (iv) \(I_2\) is a molecular solid and the other options are covalent solids and network solids.
Question 9
1 / -0

Frenkel defect is also known as ..............

(i) stoichiometric defect

(ii) dislocation defect

(iii) impurity defect

(iv) non-stoichiometric defect

A
(i) and (ii)

B
(ii) and (iii)

C
(iv) and (iii)

D
(iv) and (i)

Solution

Frenkel Defect is a stoichiometric defect, which are point defects in crystal structure which do not affect the stoichiometry of the solid. Stoichiometric defects show vacancy as well as intrinsic defects. Frenkel Defect is shown by ionic solids, where the smaller ion (usually cation) is dislocated from its normal site to an interstitial site. It creates a vacancy defect at its original site and an interstitial defect at its new location. Frenkel defect is also called dislocation defect and it does not change the density of the solids.

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Solid State Test - 15

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Solid State Test - 15

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Question 1

\(Cl^–\) ion form fcc lattice and \(Na^+\) ions occupy all octahedral voids of the unit cell.

\(Ca^{2+}\) ions form fcc lattice and \(F^-\) ions occupy all the eight tetrahedral voids of the unit cell.

\(O^- _{2}\) ions form fcc lattice and \(Na^+\) ions occupy all the eight tetrahedral voids of the unit cell.

\(S^{2-}\) ions form fcc lattice and \(Zn^{2+}\) ions go into alternate tetrahedral voids of the unit cell.

Solution

Question 2

2

3

4

6

Solution

Question 3

Dislocation defect

Schottky defect

Frenkel defects

Electronic defects

Solution

Question 4

p-type semiconductor

n-type semiconductor

Intrinsic semiconductor

Insulator

Solution

Question 5

Paramagnetic substances are weakly attracted by magnetic field.

Ferromagnetic substances cannot be magnetised permanently.

The domains in antiferromagnetic substances are oppositely oriented with respect to each other.

Pairing of electrons cancels their magnetic moment in the diamagnetic substances.

Solution

Question 6

(i) and (iv)

(i) and (ii)

(i) and (iii)

(ii) and (iii)

Solution

Question 7

(i) and (iii)

(i) and (ii)

(iii) and (ii)

(iii) and (iv)

Solution

Question 8

(i), (ii) and (iii)

(i), (ii) and (iv)

(i), (iii) and (iv)

(iii), (ii) and (iv)

Solution

Question 9

(i) and (ii)

(ii) and (iii)

(iv) and (iii)

(iv) and (i)

Solution

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