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Solid State Test - 21

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Solid State Test - 21
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following is not a crystalline solid? 
    Solution
    Crystalline solids are solids that have their atoms, molecules, and ions highly repetitive in nature and arranged in a specific pattern. 

    KCl, CsCl, and rhombic sulphur are crystalline solids whereas glass is an amorphous solid.

    So, the correct option is (C).
  • Question 2
    1 / -0
    Which of the following is not related to amorphous solids?
    Solution
    Strength, photovoltaic optical properties, no sharp melting points, not bound by plane surfaces, hard etc. are the features of amorphous solids. However, they do not give diffraction bands.
  • Question 3
    1 / -0
    The crystalline sodium has body centred cubic unit cell with edge length equal to $$0.424$$ nm at $$298$$ K. The density (in kg m$$^{-3}$$) of sodium metal at $$298$$ K is:
    Solution
    The formula for calculating density is given below:
    $$d=\dfrac { zM }{ { N }_{ A }{ a }^{ 3 } } $$
    $$d=\dfrac { 2 \times 23 }{ 6 \times 10^ {23} \times (0.424 \times 10 ^ {-9} )^3}   $$ $$\implies d=1.002\times 10^{3}$$ kg m$$^{-3}$$
  • Question 4
    1 / -0
    In a hexagonal close packed (hcp) structure of spheres, the fraction of the volume occupied by the spheres is A. In a cubic close packed structure, the fraction is B. The relation between A and B is:
    Solution
    In both hexagonal close-packed and cubic close-packed structures, the fraction of volume occupied by the spheres is 0.74.

    Means A = B = 0.74

    Hence, the correct option is A.
  • Question 5
    1 / -0
    How many kinds of space lattices are possible in a crystal?
    Solution
    There are 14 kinds of space lattices are possible for crystals these are called as Bravais lattice.
  • Question 6
    1 / -0
    Which one of the following is correct?
    Solution
    Stoichiometric defects are the defects by which the stoichiometry of the solid is not changed. Stoichiometric defects make the crystals good electrical conductors as vacancies are created as ions are either displaced or removed from their respective places. 

    In Frenkel defect, the smaller ion (usually cation) is dislocated from its normal site to an interstitial site. It does not change the density of the solid but increases the dielectric constant of the crystals.

    The Schottky defect is basically a vacancy defect in ionic solids. In order to maintain electrical neutrality, the number of missing cations and anions is equal. Schottky defect lowers the density as both cations and anions are removed. 

    Hence, option (D) is correct.
  • Question 7
    1 / -0
    Which has a minimum percent volume occupied by the spheres?
    Solution
    The edge length or side of the cube, $$a$$ and the radius of each particle, $$r$$ are related as $$a = 2r$$.
    The volume of the cubic unit cell $$= a^{3} = (2r)^{3} = 8r^{3}$$
    A simple cubic unit cell contains only $$1$$ atom.
    The volume of the occupied space $$=\dfrac { 4\pi { r }^{ 3 } }{ 3 }$$
    $$\therefore \text{Packing efficiency }$$ $$=\dfrac{\text{Volume of one atom}}{\text{Volume of cubic unit cell}}\times 100 =52.4\% $$
  • Question 8
    1 / -0
    Which of the following does not represent a type of crystal system?
    Solution
    The crystal systems into which 14 Bravais lattice are being grouped are:
    1) Cubic
    2) Orthorhombic
    3) Tetrahedral 
    4) Hexagonal
    5) Rhombohedral
    6) Monoclinic
    7) Triclinic

    Hence, Isotropical is not a crystal system type.

    Hence, Option "D" is the correct answer.
  • Question 9
    1 / -0
    An element (atomic mass $$=100$$ amu) having a bcc structure has a unit cell edge equal to $$400$$ pm. The density (in g cm$$^{-3}$$) of the element is:
    Solution
    The formula for calculating density is given below:

    $$d=\dfrac { z\times M }{ { N }_{ A }\times { a }^{ 3 } } $$

    where,
    $$d=$$ density of the unit cell
    $$z=$$ effective number of atoms in the bcc unit cell $$=2$$
    $$M=$$ molar mass $$=100\ g/mol$$
    $$N_A=$$ Avogadro number
    $$a^3=$$ volume of the unit cell $$=(400\times { 10 }^{ -10 })^3cm ^{ 3 }$$

    Substituting the value, we get

    $$d=\dfrac { 2\times 100 }{ { 6\times 10 }^{ 23 }\times { (400\times { 10 }^{ -10 }cm) }^{ 3 } } =\ 5.2\ g .cm^{-3}$$
  • Question 10
    1 / -0
    Body diagonal of a cube is $$866$$ pm. Its edge length would be:
    Solution
    Body diagonal = $$ \sqrt 3 a $$
    $$\sqrt { 3 } a=\quad 866\quad pm\\ a\quad =\quad 500\quad pm\\ $$
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