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Solid State Test - 4

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Solid State Test - 4
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which of the following is NOT a molecular solid?

    Solution

    Diamond is a covalent solid.

     

  • Question 2
    1 / -0

    Germanium or silicon becomes semiconductor due to

    Solution

    Germanium and silicon behaves as semiconductor only when doped with some group 15 element like P or As.

     

  • Question 3
    1 / -0

    If the anionic site is occupied by an electron and it becomes part of the lattice it is called

    Solution

    F-centres is the anionic site occupied by the electron ( e– becomes part of the lattice) . These electrons are coloured centres, often referred to as F-centers.

     

  • Question 4
    1 / -0

    For which type of cubic lattice, a = 2r?

    Solution

    In simple cubic unit cell only the corners are occupied. If a is the edge length and r is the radius, a = 2r.

     

  • Question 5
    1 / -0

    Which one of the following can be made n-type semiconductor only when doped with some group 15 elements like P or As?

    Solution

    Group 14 elements can be made n-type semiconductor  when doped with some group 15 element.

     

  • Question 6
    1 / -0

    Which of the following system has all unequal edge lengths and all bond angles equal?

    Solution

    In orthorhombic crystal system all angles are 90 degrees but the three edge lengths are not equal.

     

  • Question 7
    1 / -0

    The constituent particles (atoms/molecules/ions) forming three dimensional structure of solids are assumed to be

    Solution

    These are assumed to be identical hard spheres.

     

  • Question 8
    1 / -0

    The intermolecular forces existing between two non polar molecules are called

    Solution

    The forces operating between non polar molecules are weak dispersion forces also known as “London forces”.

     

  • Question 9
    1 / -0

    If germanium is doped with arsenic, what kind of semiconductor will be formed?

    Solution

    Germanium has four valence electrons and arsenic has five valence electron. So fifth electron in arsenic is extra and conductivity is by negative charge .

     

  • Question 10
    1 / -0

    Atoms of element B form a ccp lattice and those of the element A occupy 2/3rd of the tetrahedral voids, the formula of the compound is:

    Solution

    Number of close packed spheres = n

    Number of tetrahedral voids = 2n

    Only 2/3 are occupied by the atoms of element A. Hence the formula of the compound is A4B3.

     

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