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Solid State Test - 50

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Solid State Test - 50
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Weekly Quiz Competition
  • Question 1
    1 / -0
    Which of the following pairs have layer lattice structure in solid state chemistry-
  • Question 2
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    In the given crystal what should be the cation $$X$$ which replaces to create a $${ Na }^{ + }$$ cation vacancy?

    Solution
    The correct option is (A).

    Substitutional impurity in $$NaCl$$

    1) Each $$Sr^{2+}$$ replaces two $$Na^+$$ ions( to maintain charge neutrality). It occupies the site of one ion and other site remains vacant. 

    2) The cationic vacancies thus produced are equal in number to that of $$Sr^{2+}$$ ions.

    Additional Information:
    This defect occurs when regular cation is replaced by some different cation. The different cation may occupy a regular lattice site or interstitial site. 

    Thus we can say that when cation of higher valence is added as an impurity to an ionic solid, two or more cations of lower valency are replaced by cation of higher valency to maintain electrical neutrality. Hence, some cationic vacancies are created.
  • Question 3
    1 / -0
    $$NH_3$$ and $$BF_3$$form an adduct readily because they form
    Solution

  • Question 4
    1 / -0
    Schottky defect is observed in the crystal of:
    Solution
    Schottky defect is a type of point defect in crystal lattice named after walter H scottky. In non-iodic crystals, it means a lattice vacany defect. In ionic-crystals, the defect forms when oppositely charged ions leave their lattice sites, creating vacancies.
    Eg. $$AgBr,NaCl$$  $$\Rightarrow$$ Schottky defect abserved in $$NaCl$$ crystal.
  • Question 5
    1 / -0
    Amorphous solids are those which have:
    Solution
    Properties of Amorphous solids:
    (a) Amorphous solids do not have any regular arrangement of the constituent particles. They may have short range order. The amorphous solids have irregular shapes.
    (b) They do not have sharp melting point. They gradually soften over a range of temperatures. They do not have definite enthalpy of fusion.
    (c) When cut with a sharp edged tool they cut into two pieces with irregular surfaces.
    (d) Amorphous solids are isotropic in nature. It is because the arrangement of constituent particles is irregular along all the directions. Therefore, the value of any physical property (electrical resistance or refractive index) would be same along each direction.

    So, option B is correct.
  • Question 6
    1 / -0
    An element $$X$$ (atomic mass $$= 24 gm/mol$$) forms a face centered cubic lattice. If the edge length of the lattice is $$4$$ x $$10^{-8}$$ $$cm$$ and the observed density is $$2.40$$ x $$10^{3}$$ $$kgm^{3}$$ then the percentage occupancy of lattice points by element $$X$$ is : (Use $$N_{A}$$ $$=$$ $$6$$ x $$10^{23}$$) 
    Solution
    Theoretical density $$=  \dfrac{Z.M}{N_{A} . a^3}$$
    $$= \dfrac{4 \times 24 \times 10^{-3}}{6 \times 10^{23} \times (4 \times 10^{-10})^{3}}$$
    $$= 2.5 \times 10^{3} \,kg / m^{3}$$
    $$\% \,occupancy = \dfrac{Observed \,density}{Ideal \,density} \times 100$$
    $$= \dfrac{2.4 \times 10^{3}}{2.5 \times 10^{3}} \times 100 = 96\%$$
  • Question 7
    1 / -0
    The compound with the largest lattice energy would be:
    Solution
    The lattice energy depends on the attraction between the oppositely charged ions.,
    $$NaF$$ has largest lattice energy .
  • Question 8
    1 / -0
    Oxygen atom forms FCC unit cell with 'A' atoims occupying all tetrahedral voids and 'B' atoms occupying all octahedral voids. If atoms are removed from two of the body diagonals then determine the formula of resultant compound formed.
    Solution

  • Question 9
    1 / -0
    In an atomic bcc lattic what fraction of edge is not covered by atoms?
    Solution
    Edge not covered by atom $$= a - 2r$$
    also in bcc, $$4r = \sqrt{3}a$$
    Therefore, edge not covered
    $$= a - \dfrac{\sqrt 3}{2}a = a \left ( \dfrac{2 - \sqrt 3}{2} \right )$$
    $$\Rightarrow$$ Fraction of edge not covered by atoms
    $$= \dfrac{2 - \sqrt{3}}{2} = 0.134$$
  • Question 10
    1 / -0
    $$PQ$$ is $$NaCI$$ type solid $$P$$ occupies corners of cubic unit cell. If all the atoms present along face centered axis are removed, the resultant stoichiometry and $$%$$ decrease in the total number of atoms per unit cell are
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