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Solid State Test - 77

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Solid State Test - 77
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Weekly Quiz Competition
  • Question 1
    1 / -0
    A compound has a BCC unit cell with an edge length of 10A. If the density is 2 g/cm3g/cm^{3} then the molar mass of the compound  is 
    Solution

  • Question 2
    1 / -0
    CCP is also called as : 
    Solution

  • Question 3
    1 / -0
    Sodium crystallises in bcc arrangement with the interfacial sepration between the atoms of the edge 53pm53 pm. The density of the solid is :
  • Question 4
    1 / -0
    Select the correct statement related to hexagonal close packing of identical spheres in three dimensions.
    Solution

  • Question 5
    1 / -0
    In a cubic lattice if atoms are present only at all the corners and alternate face centres then the packing efficiency will be:
    Solution

  • Question 6
    1 / -0
    Edge length is 200pm\mathrm { pm } in body-centred unit cell what will be the radius of atom in pm?
    Solution

  • Question 7
    1 / -0
    Crystals of different ionic compounds having similar arrangement of ions as well as geometry are known:
  • Question 8
    1 / -0
    Which of the following is the only incorrect statement regarding amorphous solids?
    Solution

  • Question 9
    1 / -0
    A lattice is defined as
    Solution

  • Question 10
    1 / -0
    What is the packing efficiency of arrangement in a body centred unit cell?
    Solution
    Packing efficiency is defined as the percentage of space occupied by constituent particles packed inside the lattice.
    Consider edge length is aa
    In BCC,
    AC=AB2+BC2=a2+a2=2aAC=\sqrt{AB^2+BC^2}=\sqrt{a^2+a^2}=\sqrt2 a

    AC=FDAC=FD

    and AF=AD2+FD2=2a2+a2=3aAF=\sqrt{AD^2+FD^2}=\sqrt{2a^2+a^2}=\sqrt{3}a

    Thus 3a=4r\sqrt3 a=4r i.e., a=4r3a=\dfrac{4r}{\sqrt3}
    Volume of the unit cell=a3=(4r3)3=64r333a^3=\left(\dfrac{4r}{\sqrt3}\right)^3=\dfrac{64r^3}{3\sqrt3}
    Now, No. of spheres per unit cell=8×18+1=1+1=28\times \dfrac18+1=1+1=2
    Thus volume of two spheres=2×43πr3=83πr32\times \dfrac43 \pi r^3=\dfrac83 \pi r^3
    Packing efficiency=83πr36433r3=0.68\therefore \text{Packing efficiency}=\dfrac{\dfrac83 \pi r^3}{\dfrac{64}{3\sqrt3}r^3}=0.68
    Thus, %Packing efficiency=68%\%\text{Packing efficiency}=68\% 

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