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Haloalkanes and Haloarenes Test - 20

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Haloalkanes and Haloarenes Test - 20
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Weekly Quiz Competition
  • Question 1
    1 / -0

    Which is the correct increasing order of boiling points of the following compounds?

    1-Bromoethane, 1-Bromopropane, 1-Bromobutane, Bromobenzene

    Solution

    The attractions get stronger as the molecules get bigger in size and have more electrons.

  • Question 2
    1 / -0

    Which of the following are secondary bromides?

    (i) \((CH_3)_2 CHBr \)

    (ii) \((CH_3)_3C CH_2Br \)

    (iii) \(CH_3CH(Br)CH_2CH_3 \)

    (iv) \((CH_3)_2CBrCH_2CH_3\)

    Solution

    Secondary bromides are bromides where the bromo group (-Br) is bonded to a secondary or 2- degree carbon atom. (ie 2°C).

    Thus in, (\(CH_3)_2CHBr\) – Bromide group is attached to sec –carbon or 2°C. \(CH_3CH(Br)CH_2CH_3\)- here also, the Bromide group is attached to sec- carbon or 2°C.

  • Question 3
    1 / -0

    Which of the following compounds can be classified as aryl halides?

    (i) \(p-ClC_6H_4CH_2CH(CH_3 )_2 \)

    (ii) \(p-CH_3CHCl(C_6H_4 )CH_2CH_3 \)

    (iii) \(o-BrH_2C-C_6H_4CH(CH_3 )CH_2CH_3 \)

    (iv) \(C_6H_5 -Cl\)

    Solution

    Aryl halides: These are the compounds in which the halogen atom is bonded to the \(sp^2\) hybridised carbon atom of an aromatic ring.

  • Question 4
    1 / -0

    Alkyl halides are prepared from alcohols by treating with

    (i) \(HCl + ZnCl_2 \)

    (ii) Red P + \(Br_2 \)

    (iii) \(H_2 SO_4\) + KI

    (iv) All the above

    Solution

    \(R - OH + HX \underset{}{\stackrel{ZnCl_2}{\longrightarrow}}\) R - X + \(H_2O\)

    R - OH \(\underset{X_2-Br_2,I_2}{\stackrel{red \; P/X_2}{\longrightarrow}}\) \(R - X\)

  • Question 5
    1 / -0

    Alkyl fluorides are synthesised by heating an alkyl chloride/bromide in presence of _______ or _________.

    (i) \(Ca F_2\)

    (ii) \(CoF_2 \)

    (iii) \(Hg_2F_2 \)

    (iv) NaF

    Solution

    The synthesis of alkyl fluorides is best accomplished by heating an alkyl chloride/ bromide in the presence of a metallic fluoride such as AgF, \(Hg_2F_2, CoF_2 \;or\; SbF_3\). The reaction is termed as Swartsrection.

    \(CH_3Br + AgF \rightarrow CH_3F^- + Ag^-Br\)

  • Question 6
    1 / -0

    Assertion : It is difficult to replace chlorine by –OH in chlorobenzene in comparison to that in chloroethane.

    Reason : Chlorine-carbon (C—Cl) bond in chlorobenzene has a partial double bond character due to resonance.

    Solution

    The statement at assertion 'It is difficult to replace chlorine by—OH in chlorobenzene in comparison to that in chloroethane' is a correct statement and the statement given for reason (ie. ' Chlorine - Carbon (C-Cl) bond in chlorobenzene has a partial double bond character due to resonance' is also correct.

  • Question 7
    1 / -0

    Assertion : Hydrolysis of (–)-2-bromooctane proceeds with inversion of configuration.

    Reason : This reaction proceeds through the formation of a carbocation.

    Solution

    Hydrolysis of (—)-2- bromooctane proceeds with inversion of configuration because the reaction proceeds through \(S_N2 \) mechanism. The formation of carbocation occurs when the reaction proceeds through \(S_N1\) mechanism. Therefore, given statements at assertion is correct, but that at reason is wrong.

  • Question 8
    1 / -0

    Assertion : Nitration of chlorobenzene leads to the formation of m-nitro chlorobenzene 

    Reason : \(NO_2\) group is a m-directing group.

    Solution

    Even though, \(NO_2\) group is m-directing group halogen atom in chlorobenzene besides being slightly deactivating is o, p-directing; therefore, further substitution occurs at ortho- and para-positions with respect to the halogen atom. So m-nitrochlorobenzene cannot be expected as a product in this case. This confirms that the given statement at assertion is wrong, but reason is correct.

  • Question 9
    1 / -0

    Among the halogens, the one which is oxidized by nitric acid is 

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