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Haloalkanes and Haloarenes Test - 28

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Haloalkanes and Haloarenes Test - 28
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  • Question 1
    1 / -0
    $$C_6H_5-\!\!\!\!\!\underset{H}{\underset{|}{\overset{\,\,\,\,\,\,CH_3}{\overset{|}{C}}}}\!\!\!\!\!-Br+H_2O \to HO -\!\!\!\!\!\underset{H}{\underset{|}{\overset{\,\,\,\,\,\,CH_3}{\overset{|}{C}}}}\!\!\!\!\! -C_6H_5+HBr$$

    The above reaction result in 98% racemization, the reaction mainly follows:
    Solution
    An alkyl halide with chiral carbon forms a racemic mixture through $$SN^1$$ mechanism.

    $$SN^2$$ mechanism changes the configuration of a compound due to formation of the transition state.

    $$SN^1$$ mechanism proceeds through carbocation formation so it's a two-step process and as stability of carbocation increases, reaction favours $$SN^1$$ mechanism.

    $$3^0$$ carbocation are more stable than others and also polar solvent increases the stability of carbocation so they both favours $$SN^1$$ mechanism.

    Also, the rate of $$SN^1$$ mechanism depends on nucleophile concentration only so as conc. of nucleophile increases, reaction favours $$SN^1$$ mechanism.

  • Question 2
    1 / -0
    Which of the following statement is not correct?
    Solution
    $$Chlorine$$ shows two effects $$-I$$ & $$+M$$.

    Due to$$ the - I $$ effect of $$Cl$$ group, it reduces the electron density of benzene so chlorobenzene is less reactive than benzene for electrophilic substitution reaction.

    But due to the $$+M$$ effect, it is ortho, para directing, and in chlorobenzene further substitution takes place at ortho and para positions.

    Option A is correct.
  • Question 3
    1 / -0
    The compound $$X$$ is:

    Solution

    As $$Cl-$$ group attached to benzene is ortho, para directing so it forms $$o-,p-$$ chloro toluene.

    Reaction is as shown.

  • Question 4
    1 / -0
    Which of these is o, p-directing and deactivating group?
    Solution
    $$X-$$ (halogen group) has two effects $$-I$$ & $$+M$$.

    Due to the $$-I$$ group, it reduces the electron density of benzene so halobenzene is less reactive than benzene for electrophilic substitution reaction.

    But due to the $$+M$$ effect, it is ortho, para directing (resonance effect predominates over inductive effect) and in halobenzene, further substitution takes place at ortho and para positions. 
  • Question 5
    1 / -0
    If $$C_{4}H_{9}Cl$$ with $$Na/ether$$ gives $$2,5$$-dimethylhexane, then the compound, $$C_{4}H_{9}Cl$$ is:
    Solution
    The reaction of  Isobutyl chloride $$(C_{4}H_{9}Cl)$$ with $$Na/Ether$$ gives $$2,5$$-dimethylhexane. This is a condensation reaction in which two molecules of sodium chloride are obtained for every molecule of $$2,5$$-dimethylhexane.

    Option C is correct.

  • Question 6
    1 / -0
    The reaction of toluene with $$Cl_{2}$$ in presence of $$Fe$$, the product(s) formed is/are:
    Solution
    $$-CH_3$$ group on benzene is ortho and para directing. 

    In presence of $$Cl^-$$, it forms ortho (minor) and para (major) chlorotoluene as products.

    Option A is correct.

  • Question 7
    1 / -0
    Which one of the following compounds is most reactive for aromatic electrophilic substitution reaction?
    Solution
    Due to $$- I$$ effect of $$X-$$ group, it reduces electron density of benzene, so halobenzene is less reactive than benzene for electrophilic substitution reaction.

    As electro-negativity of $$F$$ is highest among halogens, so its $$-I$$ effect is highest.

     So, reactivity of halobenzene compounds towards electrophilic substitution is $$ Ph-I > Ph-Cl >Ph-F$$.

    Due to $$-M$$ effect of nitrate group, it is less reactive than other compounds.

    Option C is correct.
  • Question 8
    1 / -0
    Which of the following is used in paint removing?
    Solution
    $$CHCl_3$$ is used as solvent and as an anaesthetic.
    $$CCl_4$$ is used as a fire extinguisher.
    $$CH_2Cl_2$$ is used as paint removing.
    $$CH_3Cl$$ is used as a refrigerant.

    Hence, the correct option is B.
  • Question 9
    1 / -0
    $$2C_{6}H_{5}Cl+2Na\rightarrow X$$
    In the given reaction $$X$$ is:
    Solution
    Fitting reaction: Aryl chloride reacts with Na in presence of dry ether and diaryl forms as product.(similar to Wurtz reaction).
    Reaction:
    $$2C_{6}H_{5}Cl+2Na\rightarrow Ph-Ph+2NaX$$ 
  • Question 10
    1 / -0
    Reaction of Chlorobenzene with $$CH_3Cl$$ in presence of $$AlCl_{3}$$ gives:
    Solution
    As $$Cl^-$$ group attached to benzene is ortho, para directing so it forms $$o-,p-$$ chloro toluene.
    This is a Fridel Craft's  alkylation reaction.
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